How to replace QWidget name dynamically with variable

[mrjj]

Hi
Cant you just put
self.dlg.name1
self.dlg.name2
etc
into a list ?

You can also build this list automatically from DLG
https://doc.qt.io/qt-5/qobject.html#findChildren

[qtnoob420]

@mrjj my thought is to get relevant fields that i need to work with from QGIS and then adress my QLineEdits, QCheckboxes, etc with that.

For every of my input field i have a label too. wouldnt they be found too with "findchildren"?

[jsulm]

@qtnoob420 If you want to access your widgets using a string then you could simply put your widgets in a dictionary. This would be way faster than using findChildren.

[qtnoob420]

@jsulm it's not that i explicitly want to do it that way, but that I don't know any other way. I don't have the experience and the knowledge i guess

[qtnoob420]

@jsulm can you provide me any help on how to do that?

[mrjj]

@qtnoob420
Hi

Something like

a_dict = dict()
a_dict["name"] = self.dlg.name1
a_dict["name3"] = self.dlg.name2

and you can look up the self.dlg.name1 widget with "name"

"name" is the actual name of the widget. (objectname)

[JonB]

@qtnoob420
Python has a dict type, to store an arbitrary set of key-value pairs.

If you want to do as @jsulm said and "access your widgets using a string" you could do something like:

widgets = dict()
widgets["name1"] = self.dlg.name1
widgets["name2"] = self.dlg.name2
...

You can then access, say, self.dlg.name2 via widgets["name2"]. You can also iterate through all of them, keys and values, via

for key in widgets:
     print(key, '->', widgets[key])

If you don't want key names you can of course do similar by just storing them in a list/array instead of a dictionary.

[SGaist]

Hi,

There might be some stuff doable with some Python introspection or even just using QObject's objectName method.

Can you show the code of the class of your self.dlg variable ?

[qtnoob420]

@mrjj okay i got this so far.
now i want to set values of my fields like this...

a_dict["name"].setText("some text")

but i get the error:

a_dict["name"].setText("some text")
AttributeError: 'str' object has no attribute 'setText'

[qtnoob420]

@JonB i am still not able to address them like i imagine to.
if i try to set values of my field like:

a_dict["name"].setText("some text")

i get the error:

AttributeError: 'str' object has no attribute 'setText'

[jsulm]

@qtnoob420 said in How to replace QWidget name dynamically with variable:

a_dict["name"]

What did you store there? Can you show how (and what) you set it (a_dict["name"]=...).
What does type(a_dict["name"]) print out?
It seems you put a string there...

[qtnoob420]

@jsulm oh youre right. but idk how i could assign them in an other way:

i assigned them like:

a_dict[attribute] = "self.dlg."+attribute

attribute is the name of the attributes from QGIS. and i named my QWidgets in a similar way to match them.

[jsulm]

@qtnoob420 Well, you are assigning a string. So, how should that work?
Why don't you assign self.dlg.attribute? Where attribute is the name of the attribute.
Also, what type is self.dlg?

[qtnoob420]

@jsulm it makes completely sense, i just dont know how :(

i tried stuff like...

a_dict[attribute] = self.dlg.attribute
AttributeError: 'BaumkatasterDialog' object has no attribute 'attribute'


feature_dict[attribute] = self.dlg.+attribute
SyntaxError: invalid syntax

... which doesnt work either. i just dont know no better

i used the PluginBuilder3 so it was created by the plugin. i can access all of my UI Widgets from the QtDesigner with "self.dlg.widget_name"

[jsulm]

@qtnoob420 As I said: use real name of the attribute, not the word "attribute". Example: if you have attribute called "a" then do:

a_dict[attribute] = self.dlg.a

But it seems that you only have strings containing attribute names, right?
Then you could do it like this:

f = getattr(self.dlg, attribute)
f() # Here we call attribute

You do not even need a dictionary.
One example for string in Python:

s="abc"
f=getattr(s, "upper")
f() # prints ABC