How to replace QWidget name dynamically with variable

mrjj

Hi
Cant you just put
self.dlg.name1
self.dlg.name2
etc
into a list ?

You can also build this list automatically from DLG
https://doc.qt.io/qt-5/qobject.html#findChildren

qtnoob420

@mrjj my thought is to get relevant fields that i need to work with from QGIS and then adress my QLineEdits, QCheckboxes, etc with that.

For every of my input field i have a label too. wouldnt they be found too with "findchildren"?

jsulm

@qtnoob420 If you want to access your widgets using a string then you could simply put your widgets in a dictionary. This would be way faster than using findChildren.

qtnoob420

@jsulm it's not that i explicitly want to do it that way, but that I don't know any other way. I don't have the experience and the knowledge i guess

qtnoob420

@jsulm can you provide me any help on how to do that?

mrjj

@qtnoob420
Hi

Something like

a_dict = dict()
a_dict["name"] = self.dlg.name1
a_dict["name3"] = self.dlg.name2

and you can look up the self.dlg.name1 widget with "name"

"name" is the actual name of the widget. (objectname)

JonB

@qtnoob420
Python has a dict type, to store an arbitrary set of key-value pairs.

If you want to do as @jsulm said and "access your widgets using a string" you could do something like:

widgets = dict()
widgets["name1"] = self.dlg.name1
widgets["name2"] = self.dlg.name2
...

You can then access, say, self.dlg.name2 via widgets["name2"]. You can also iterate through all of them, keys and values, via

for key in widgets:
     print(key, '->', widgets[key])

If you don't want key names you can of course do similar by just storing them in a list/array instead of a dictionary.

SGaist

Hi,

There might be some stuff doable with some Python introspection or even just using QObject's objectName method.

Can you show the code of the class of your self.dlg variable ?

qtnoob420

@mrjj okay i got this so far.
now i want to set values of my fields like this...

a_dict["name"].setText("some text")

but i get the error:

a_dict["name"].setText("some text")
AttributeError: 'str' object has no attribute 'setText'

qtnoob420

@JonB i am still not able to address them like i imagine to.
if i try to set values of my field like:

a_dict["name"].setText("some text")

i get the error:

AttributeError: 'str' object has no attribute 'setText'

jsulm

@qtnoob420 said in How to replace QWidget name dynamically with variable:

a_dict["name"]

What did you store there? Can you show how (and what) you set it (a_dict["name"]=...).
What does type(a_dict["name"]) print out?
It seems you put a string there...

qtnoob420

@jsulm oh youre right. but idk how i could assign them in an other way:

i assigned them like:

a_dict[attribute] = "self.dlg."+attribute

attribute is the name of the attributes from QGIS. and i named my QWidgets in a similar way to match them.

jsulm

@qtnoob420 Well, you are assigning a string. So, how should that work?
Why don't you assign self.dlg.attribute? Where attribute is the name of the attribute.
Also, what type is self.dlg?

qtnoob420

@jsulm it makes completely sense, i just dont know how :(

i tried stuff like...

a_dict[attribute] = self.dlg.attribute
AttributeError: 'BaumkatasterDialog' object has no attribute 'attribute'


feature_dict[attribute] = self.dlg.+attribute
SyntaxError: invalid syntax

... which doesnt work either. i just dont know no better

i used the PluginBuilder3 so it was created by the plugin. i can access all of my UI Widgets from the QtDesigner with "self.dlg.widget_name"

jsulm

@qtnoob420 As I said: use real name of the attribute, not the word "attribute". Example: if you have attribute called "a" then do:

a_dict[attribute] = self.dlg.a

But it seems that you only have strings containing attribute names, right?
Then you could do it like this:

f = getattr(self.dlg, attribute)
f() # Here we call attribute

You do not even need a dictionary.
One example for string in Python:

s="abc"
f=getattr(s, "upper")
f() # prints ABC