QML and Qt Quick

@morte What do you mean by not draws ? See if you get updated height inside the Component.

@themts Hmmm that sounds really odd, but without the code, I don't know why it would output that error. I will say that you do not need a copy constructor. You could make a new qml type from class Thing : public QObject { Q_OBJECT public: explicit Thing(QObject* parent = nullptr); virtual ~Thing(); };

@Meteor +1 for parent.modelData

@themts You can set a custom palette to the application itself. For eg: QGuiApplication app(argc, argv); QQmlApplicationEngine engine; engine.load(QUrl(QStringLiteral("qrc:///Example.qml"))); QPalette customPalette(app.palette()); customPalette.setColor(QPalette::WindowText,QColor("yellow")); app.setPalette(customPalette); return app.exec();

Hi, I don't understand what's the problem. Setting enabled to false automatically changes the color of the checkbox. CheckBox { text: "Hello" enabled: !checked }

@olejl77 You can add typeChanged signal and emit it from the model itself when new item is added to model or as per your requirement (i.e when specific item is added). What I want is a way to bind to a a specific object inside the model, and not to the model itself. AFAIK the only way to access the items of model is through model itself. The example I posted earlier will always get the Item at 0 index and not any other when.

@pnmrvvtl Looking at the source here (Line 660), the assert occurs when the rect (viz. here the canvas) is not valid. But I tested something similar on Linux and it works. Following is the code: import QtQuick 2.4 Canvas { id: root width: 200 height: 200 property point initialpos : Qt.point(0,0) property point finalpos: Qt.point(0,0) property int count : 0 onPaint: { var ctx = getContext("2d") ctx.clearRect(0, 0, width, height); ctx.lineWidth = 2 ctx.strokeStyle = "red" ctx.beginPath() ctx.moveTo(initialpos.x,initialpos.y) ctx.lineTo(finalpos.x,finalpos.y) ctx.stroke() ctx.closePath() } Timer { interval: 1000; running: true; repeat: true onTriggered: { initialpos = Qt.point(Math.floor(Math.random() * 200) + 1,Math.floor(Math.random() * 200) + 1) finalpos = Qt.point(Math.floor(Math.random() * 200) + 1,Math.floor(Math.random() * 200) + 1) root.paint(0,0,root.width,root.height) root.save("/home/ashish/grab/"+count+++".jpg") } } } This code just takes snaps of Canvas and save into directory after an interval of 1 sec. This works for me and there is no assert. Also root.requestPaint() instead of root.paint(0,0,root.width,root.height) works even if the Window is minimized. Can you test it on your system ?

@maxsivkov Scenario is to have several elements (images with attached mouseareas (to change image source when mouse is inside the image) and also show hints (tooltips) for listview's item. So its better no to do it when the ListView scrolls and only when user hovers mouse over that particular Item To show tooltip my idea was to sit on a onPositionChanged event and restart timer, stop it in onExited event. I think better to use onEntered and onExited. Using onPositionChanged will continuously restart it as mouse moves. Also hide it after a particular timeout instead of only in onExited.

Hi Buttnik, Thanks for the help, it does exactly what I was looking for.

@th.thielemann TableView already has a clicked signal. You can use that.

@grheard It didn't work because the requirement is to clip beyond the ListView's boundary and not the delegate's one. And so setting clip for ListView did the trick.

I moved a little bit using the following Timer { id: elapsedTimer interval: 10; running: false; repeat: false onTriggered: canvas.timeChanged() } function timeChanged() { canvas.currentValue = canvas.currentValue + 1 if(canvas.currentValue >= 100) { // here I must emit a signal } } Now I will enter inside the if condition at the desired time. But what should I do once I am in there? Can I somehow emit a signal so whoever is using the button can attach to it?

One last thing, apparently this error only occur in IOS devices

@mcosta said: change the size depending on resolution Thanks let me try

@emppu How to prevent that a user opens the same window twice? Do I need a flag variable in C++ code or is it easily done in QML? This seems a common workflow (preference window, open/save dialog, etc). I don't want to disable the main window while About window is open. You can do it right itself in QML. Declare component as global property and then check for null before creating that component. property Component component ... MenuItem { ... onTriggered: { if(!component) { component = Qt.createComponent("About.qml"); var about = component.createObject(main); about.show(); } } } In my case main window didn't disable. Did you set any particular Qt::WindowFlags flag ? If I keep an instance of About window as an attribute of main ApplicationWindow, does it occupy the memory since the main window is loaded? If I have many different windows, this is really inefficient. What's the simplest solution? Anything instantiated will occupy memory. To delay that process you use the technique you mentioned or you can use Loader to load them dynamically.

Ahhhhh! Thanks! I didn't know what textrole is for! THANKS cu mts