[SOLVED] Monitoring an object changed asynchronously by a Callback function

SGaist

Hi,

If you need that much performance, you'd better do a benchmark. What is your use case ?

sirop

@SGaist
I was told today that we'll use milliseconds interval.
So it is no longer a performance question.

I just implemented a QTimer for monitoring the callback function changing my vector,
and it was fast enough.

SGaist

Why not embed that QVector in a QObject wrapper that will emit a signal whenever the vector is modified ?

sirop

@SGaist said:

Why not embed that QVector in a QObject wrapper that will emit a signal whenever the vector is modified ?

QVector in a QObject wrapper?

I thought about something like:

QBuffer buffer(&byteArray);

and then use the above mentioned QBuffer signals.

SGaist

That's also an alternative yes, you can even go further using a QIODevice derived class and create a device that would your data directly

sirop

@SGaist

Yes, I subclassed QBuffer, implemented my own

qint64 MyBuffer::writeData(const char *data, qint64 len)
{
    buffer().clear();
    buffer().append(data,len);
    emit bytesWritten(len);
    return len;
}

and then:

QObject::connect(DDEComm::instance()->buf,&QBuffer::bytesWritten,[=](qint64 bytes)
{
    printf("bytesWritten: %d, Buffer: %s\n", (int) bytes, DDEComm::instance()->buf->data().data());
});

It works so far as it should.

But what was your proposal about embedding QVector in a QObject wrapper?
Is is something where one has to use http://doc.qt.io/qt-5/properties.html ?

Anyway I'd mark then this thread as SOLVED.

SGaist

No you don't have to. The use of properties depends on your software architecture and your class design.

sirop

@SGaist
How else can I inroduce my own SIGNAL function for any Object?

SGaist

Just declare your signal in the class header and emit it in your code. Take for example QTimer, the timeout signal is not attached to any property and none of them has any signal.

sirop

@SGaist

Thanks. Now I have a more clear picture about signals.