[solved] emit error(ErrorString) -> cannot be used as a function!

[rentner323]

Hi,
In my Object I declared a Signal:
@
signals:
void error(QString e);
@

In serveral Functions i want to emit the error-Signal if Problems occur, this works:
@
emit error("Server Timeout!");
@

This not (telling me: "'error' cannot be used as a function):
@
QString errorString;
errorString = "Error Occured: ";
errorString.append(pTcpSocket->errorString());
emit error(errorString);
@

Why?

[SGaist]

Hi,

Are you sure you are not already using error as a variable in the same function ?

Generally speaking using error as a function name is not a good idea, you should rather have something like :

@void errorOccured(const QString& errorText)@

It will make your code clearer to read and avoid name clashes.

Hope it helps

[sierdzio]

Hint You should be passing QStrings as const references:
@
voi error(const QString &e);
@

Your second example should work just as the first one. Maybe you are using it outside of your class, or maybe it clashes with some other members (a variable, or a macro in one of the includes). Maybe try renaming it to something less common.

[rentner323]

[quote author="SGaist" date="1385377701"]
Are you sure you are not already using error as a variable in the same function ?
[/quote]

That was the Problem! I've totally overlooked that.

Thanks!

[SGaist]

You're welcome !

Using meaningful names for functions and variables is a good way to avoid these kind of problems.

Since you have it working now, pleas update the thread title prepending [solved] so other forum users may know a solution has been found :)