Calling the "Timer" function

Darq

Hello.

I use the "Timer" function to make the image appear. I'm having trouble looping this function. Instead of looping and appearing every few seconds, the image appears twice and disappears. Where is the error that there is no looping?

Image {
	id: abc
	source: 'abc.png' 
	anchors.centerIn: parent
	anchors.verticalCenterOffset: 0
	anchors.horizontalCenterOffset: 0
	cache: false
	smooth: true
	visible: true
	layer.enabled: true
	layer.effect: DropShadow 
	{
		horizontalOffset: 5
		verticalOffset: 4
		color: "#AA000000"
		radius: 8
		samples: 10
	}
}

	Timer {
	interval: 2000
	onTriggered: abc.visible = false
	running: true
	repeat: true
	}

dheerendra

@Darq said in Calling the "Timer" function:

abc.visible = false

This line is an issue. Try this.

abc.visible = !abc.visible

jsulm

@Darq It's not clear what you want to achieve. Do you want that the image appears, then disappears after two seconds and appears again after two seconds as long as the timer is running? If so, then why do you set abc.visible to false in onTriggered? You need to set it to inverted value (like: abc.visible = !abc.visible)

Darq

Thank you very much, it works now.

I don't understand the principle of operation of onTriggered, why must the state be true and after the = sign the state false?

jsulm

@Darq said in Calling the "Timer" function:

why must the state be true and after the = sign the state false?

Nobody suggested that.
onTriggered is called on every timeout (in your case after 2sec and then again after 2sec and so on). In your code you set visibiliyt alsways to false - so, how shoult it ever become visible? The logic is quite simple: in onTriggered you change visibility to true if it was false and to false if it was true...