How to Implement the coding part of this UI Integration?

[Aviral 0]

Hi all, I have a prebuilt LogDisplay QT Application, and I want to Integrate it into my current QT GUI application.
I have used stacked widget as the container for the application and using only 1 page of that. Suggest if some another good option other than QStackWidget?

I have promoted the QStackWidget to LogDisplay class.

Please someone tell me the mainwindow coding part to call the logdisplay class in that QStacked widget.

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

Do you have any idea what I am doing wrong here

What do you expect this code to do?
You added a layout to ui->page. Then you added logDisplay as another page. But you wanted to have logDisplay on ui->page, right? Can you please read more carefully? I wrote before:

// Or, if ui->page has a layout:
LogDisplay *logDisplay = new LogDisplay();
ui->page->layout()->addWidget(logDisplay);

So, don't you think your code should be like:

// Or, if ui->page has a layout:
LogDisplay *logDisplay = new LogDisplay();
ui->page->setLayout(new QHBoxLayout);
ui->page->layout()->addWidget(logDisplay);

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

Suggest if some another good option other than QStackWidget?

Why?

"Please someone tell me the mainwindow coding part to call the logdisplay class in that QStacked widget." - what "coding part"? What does "call the logdisplay class" mean?
Please ask clear questions...

[Aviral 0]

@jsulm Actually I am trying to add the LogDisplay application integrate with another UI application.
I have a QWidget which contains QStackedView and Using QstackedView I am displaying LogDisplay class.

QWidget *widget = new QWidget(this);
    QStackedWidget *stackedWidget = new QStackedWidget(this);
    LogDisplay *logDisplay = new LogDisplay(this);

    //stackedWidget->setCurrentWidget(widget);
    widget->setLayout(new QHBoxLayout);
    widget->layout()->addWidget(stackedWidget);
    setCentralWidget(stackedWidget);
            stackedWidget->addWidget(logDisplay);
            stackedWidget->show();

But the Logdisplay class is taking the whole screen of application instread of what I am giving the position and size in UI design. How to solve this?
Here the output I am getting:

in Full Screen.
But I defined the stackedwidget as:

[jsulm]

This post is deleted!

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

But the Logdisplay class is taking the whole screen of application instread of what I am giving the position and size in UI design. How to solve this?

You are NOT using what you defined in UI! You're adding a NEW QWidget which is then replacing the central widget of your main window! You are also creating a NEW QStackedWidget instead of using the one you added in UI! Why don't you use ui->stackedWidget instead of doing all this?! ui->stackedWidget is the stacked widget you added in your ui...

[Aviral 0]

@jsulm Can you help me write it up?

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

Can you help me write it up?

Write what?
Simply use ui->stackedWidget to access your stacked widget, there is no need for the code you posted because you already added a stacked widget in designer...

[Aviral 0]

@jsulm how to add LogDisplay object in ui->stackedwidget?

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

how to add LogDisplay object in ui->stackedwidget?

Like shown in documentation: https://doc.qt.io/qt-6/qstackedwidget.html Did you read it?

stackedWidget->addWidget(firstPageWidget);

Before you ask:

LogDisplay *logDisplay = new LogDisplay(this);
ui->stackedWidget->addWidget(logDisplay);

[Aviral 0]

@jsulm The Object of Page in StackedWidget is "page" in UI,
and I have implemented like this:

 ui->stackedWidget->addWidget(ui->page);
    LogDisplay *logDisplay = new LogDisplay(this);
    ui->stackedWidget->addWidget(logDisplay);

Still No Stacked window is shown. Please Help!

[jsulm]

@Aviral-0 If you want to add your logDisplay to an existing widget in stackedwidget (for whatever reason) then do so:

LogDisplay *logDisplay = new LogDisplay(ui->page);
// Or, if ui->page has a layout:
LogDisplay *logDisplay = new LogDisplay();
ui->page->layout()->addWidget(logDisplay);

Then please don't call ui->stackedWidget->addWidget(logDisplay)!

[Aviral 0]

@jsulm Using this:

ui->stackedWidget->addWidget(ui->page);
    LogDisplay *logDisplay = new LogDisplay();

    ui->page->layout()->addWidget(logDisplay);

Application is crashing with both above suggestions.

[J.Hilk]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

ui->stackedWidget->addWidget(ui->page);
LogDisplay *logDisplay = new LogDisplay();

where, for the love of god, did you see this as a suggestion ?

[jsulm]

@Aviral-0 Please, I never said you need ui->stackedWidget->addWidget(ui->page)!
ui->page was already added to stacked widget in UI! Please think about what you're doing!
This should work:

LogDisplay *logDisplay = new LogDisplay();
ui->page->layout()->addWidget(logDisplay);

If it crashes then please first use a debugger to see why. Debugger is really one of the most basic tools of a programmer.

[Aviral 0]

This post is deleted!

[Aviral 0]

@J-Hilk Hi, I am sorry for some silly questions, I am new to programming job and it doesn't interest me much, but gotta do it for the living. Just to cover my basic needs so that I can do what interests me! Hope you'll understand!

[JonB]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

I am new to programming job and it doesn't interest me much, but gotta do it for the living.

Ummm.....

Just to cover my basic needs so that I can do what interests me!

I don't know how easy it will be to use programming to cover your "basic needs" while you go off doing whatever you actually want to do! Programming is (relatively) hard, it certainly requires some effort to understand what is going on! All the best :)

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

Launches the application but I see no stackedwidget in it.

Probably because ui->page page of your stacked widget is shown and not the other you're adding.
I already told you: if your app crashes use debugger to see why. I guess ui->page has no layout, so ui->page->layout() returns nullptr. Add a layout to it then.

[Aviral 0]

@JonB Yeah! Do you have any idea what I am doing wrong here:

ui->page->setLayout(new QHBoxLayout);
    LogDisplay *logDisplay = new LogDisplay(ui->page);

   // ui->stackedWidget->layout()->addWidget(logDisplay);

    ui->stackedWidget->addWidget(logDisplay);
    ui->stackedWidget->show();

[jsulm]

@Aviral-0 said in How to Implement the coding part of this UI Integration?:

Do you have any idea what I am doing wrong here

What do you expect this code to do?
You added a layout to ui->page. Then you added logDisplay as another page. But you wanted to have logDisplay on ui->page, right? Can you please read more carefully? I wrote before:

// Or, if ui->page has a layout:
LogDisplay *logDisplay = new LogDisplay();
ui->page->layout()->addWidget(logDisplay);

So, don't you think your code should be like:

// Or, if ui->page has a layout:
LogDisplay *logDisplay = new LogDisplay();
ui->page->setLayout(new QHBoxLayout);
ui->page->layout()->addWidget(logDisplay);