Solved QRect and wrong rectangle coordinates

[JulienD]

Hi,

Currently using QT 5.15 and reading Qrect, I just want to make sure of one thing:

QRect a(0,100,50,-50);

yields (for topLeft, topRight, bottomRight, bottomLeft):

QPoint(0,100)   QPoint(49,100)   QPoint(49,49)   QPoint(0,49)

Which is correct (don't care about the -1)

But if I do

QRect a(0,100,50,50);

it yields

QPoint(0,100)   QPoint(49,100)   QPoint(49,149)   QPoint(0,149)

Which is not logical since the topLeft is below the bottomLeft !
So to be correct in all cases (rotation included), should I enforce the minus ? Or will another surprise arise?

Thanks

[Bonnie]

What are you talking about?
QPoint(0,149) is below QPoint(0,100) because the GUI coordinate system looks like this:

(picture is from: https://doc.qt.io/qt-5/coordsys.html)

[JulienD]

Missed that info. Everything is alright. thanks!

[HoMa]

I want to add that the documentation of QRect reads different from your assumption: The consturctor which takes 4 int arguments assums "width" and "height" as last arguments. These are no point coordinates.

QRect(int x, int y, int width, int height)