Solved Problem with operator <<

[SteMMo]

Hi all,
I'm defining a simple custom class and I'd like to define a << operator to have a suitable debug output.
The class is defined as:

class Prenotazione : public QObject
{
  Q_OBJECT 
  public:
    int _id;
    int _value;

    QDebug operator<<( QDebug dbg, const Prenotazione &myObject){
        dbg << "QQQ";
        return dbg;
    };

The compiler says that 'error C2804: 'operator <<' (binary) has too many parameters'.

I saw many examples and they are written in this way .. in don't understand why I have this error ..

Thanks!

[J.Hilk]

@SteMMo well, you overloaded it for a const reference, not for a pointer -> so dereference it

p = new Prenotazione();
    p->_id = query.value("id").toUInt();
    qDebug()<< "[DataSource] p:" << *p;

[J.Hilk]

@SteMMo friend is missing, you are trying to declare a non-member operator overload that acts on a class template for the QDebug << operator

and not an overload for the Prenotazione << operator

[SteMMo]

@J-Hilk thanks,
the code now is accepted but I continue to have:

[DataSource] p: Prenotazione(0x8098b118)

from the code:

    p = new Prenotazione();
    p->_id = query.value("id").toUInt();
    qDebug()<< "[DataSource] p:" << p;

[J.Hilk]

@SteMMo well, you overloaded it for a const reference, not for a pointer -> so dereference it

p = new Prenotazione();
    p->_id = query.value("id").toUInt();
    qDebug()<< "[DataSource] p:" << *p;