Why does QHostAddress::protocol() always return QAbstractSocket::IPv6Protocol

[yvbbrjdr]

When I establish IPv4 connection between a QTcpSocket and a QTcpServer, I find out that the socket.peerAddress().toString() returns a IPv6 version of IPv4 address, which is like ::ffff:192.168.1.100. And then I check the socket.peerAddress().protocol() and it returns QAbstractSocket::IPv6Protocol. Why does it return an IPv6 when I am using IPv4?

[yvbbrjdr]

I found that it is the same in all platforms, including Windows, Linux, and macOS.

[SGaist]

Hi,

AFAICS, your system is using a IPV4 mapped IPV6. So technically there's nothing wrong going on from a Qt point of view. The IPV4/IPV6 handling is done outside of Qt's scope and you get accurate information.

[yvbbrjdr]

@SGaist So I am trying to use the function QHostAddress::toIPv4Address(bool *ok) and check the "ok" to see if the IP address is a IPv4. Is that OK?

[SGaist]

AFAIK, it should be yes.

[alex_la]

It's a bug in Qt. Appears everytime. Even if disable IPv6 stack.

[ChrisW67]

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