Accessing QQuickItem Transform object from C++ ?

Hello, I am writing a custom QQuickItem derived class in C++ and registering it in QML to use in my Scene Graph based scene. It's very simple as I'm testing things out yet, here is my QML declaration for my object:
Hexagon { id: hexa0 anchors.fill: parent anchors.margins: 20 transform: Translate { x: 200 y: 200 } }
And here is my code for drawing this item:
QSGNode *Hexagon::updatePaintNode(QSGNode *old_node, UpdatePaintNodeData *) { qDebug() << "updatePaintNode"; QSGGeometryNode *node = 0; QSGGeometry *geometry = 0; if (old_node == nullptr) { node = new QSGGeometryNode; geometry = new QSGGeometry(QSGGeometry::defaultAttributes_Point2D(), _num_points); geometry>setLineWidth(3); geometry>setDrawingMode(QSGGeometry::DrawLineLoop); node>setGeometry(geometry); node>setFlag(QSGNode::OwnsGeometry); QSGFlatColorMaterial *material = new QSGFlatColorMaterial; material>setColor(QColor(0, 0, 255)); node>setMaterial(material); node>setFlag(QSGNode::OwnsMaterial); } else { node = static_cast<QSGGeometryNode *>(old_node); geometry = node>geometry(); geometry>allocate(_num_points); } QSGGeometry::Point2D *vertices = geometry>vertexDataAsPoint2D(); float angle_offset = 0.0f; float angle_inc = 2*M_PI / _num_points; float angle_rad = qDegreesToRadians(angle_offset); for (int i=0; i<_num_points; i++) { float x = sin(angle_rad) * _radius; float y = cos(angle_rad) * _radius; vertices[i].set(x, y); angle_rad += angle_inc; } node>markDirty(QSGNode::DirtyGeometry); return node; }
Now, I would like to transform this object from my C++ code. I cannot seem to find how to access the QML declared Transform object in such a way from C++ that I could just do something like transform.setPos(origin.x, origin.y);
How can I access and set this transform object from the updatePaintNode() method ?
Thank you!

Okay found out the solution, calling setX() and setY() and so also that I removed the anchors from the QML code, now setting translation works! Didn't realize the anchors prevented setX() and setY() from working.