QUrl adding parameter

Paysami

Hello there,
After 2hours of trying add variable into QUrl i decided to write for help.
I need to put parameter and value after base url.
Key is in private like QString key;

QString key = "29vVtpyUwORVl0aw";
QUrl url("http://127.0.0.1/restapi/api.php");
QNetworkRequest request(url);
request.setHeader(QNetworkRequest::ContentTypeHeader, "application/x-www-form-urlencoded");
//reply and responses

This is what i want to prepare for QNetworkRequest request(url);

http://127.0.0.1/restapi/api.php?key=29vVtpyUwORVl0aw
//If i put this into QUrl it works fine.

Thanks for responds

mrjj

@Paysami
Hi
Im not sure what question is.
If
"http://127.0.0.1/restapi/api.php?key=29vVtpyUwORVl0aw" works then

QString key = "29vVtpyUwORVl0aw";
QString base="http://127.0.0.1/restapi/api.php";
QString extra="?key=";
QUrl url( base +extra+key);

should also work?

Paysami

@mrjj
Thanks for respond.
lol, its working.

I tried that for first but it was not working.
I was reading full manual of QNetworkRequest about some headers, atributes and etc..
Maybe i had some bad syntaxes because QUrl wasnt allow something next then "string".

Thanks for help.

mrjj

@Paysami
Super :)
Good work reading the docs.
Well, one trap i sometimes fall in is
QString + QString + char *
Where it really wants
QString + QString + QString(char *)
So as example
QUrl url("http://127.0.0.1/restapi/api.php" + key);
--->
QUrl url(QString("http://127.0.0.1/restapi/api.php") + key);

I am only guessing. The error could have been many things. :)

Solved QUrl adding parameter