PyQt, after app quit, my command line is unresponsive

[Jinxvar]

Hi, I have some weird behaviour that I can not understand.
I run this code "python3 ToonPi.py" from my Raspberry Pi command line.
This generates a screen with picture and button using PyQt5 and Qt5.5. When I click the button the app quits, so far so good.
However, from that point on my command line no longer works and I can not see the blinking line which I
normally see when I want to type something in. I have to reboot my RPi to try again.
Anyone have any idea on this?

Below are both the py file and the QML file.
QML File

import QtQuick 2.3
import QtQuick.Controls 1.4

ApplicationWindow {
    id: window
    visible: true
	width: 800; height: 480

	Rectangle {
		id: screen
		width: 800; height: 480

		SystemPalette { id: activePalette }

		Item {
			width: parent.width
			anchors { top: parent.top; bottom: toolBar.top }

			Image {
				id: background
				anchors.fill: parent
				source: "./pics/toonback.png"
				fillMode: Image.PreserveAspectCrop
			}
		}

		Button{
			x: 100
			y: 100
			text : "Quit"
			onClicked: {
				Qt.quit()
			}
		}
		
		Rectangle {
			id: toolBar
			width: parent.width; height: 30
			color: activePalette.window
			anchors.bottom: screen.bottom


			Text {
				id: score
				anchors { right: parent.right; verticalCenter: parent.verticalCenter }
				text: "Score: Who knows?"
			}
		}
		
	}
}

And the Python file

import sys
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQml import QQmlApplicationEngine


def main():

    engine = QQmlApplicationEngine("basic.qml")
    engine.quit.connect(myApp.quit)

    # Execute the Application and Exit
    myApp.exec_()

# Main Function
if __name__ == '__main__':
    # Create main app
    myApp = QApplication(sys.argv)
    sys.exit(main())

[Metavoid]

hello,
So reset or clear wont make it "blink" again?

[Jinxvar]

You mean reboot? After reboot its fine.
What do you mean by reset or clear?

[David.G]

Perhaps because you are not returning the value. There's no return.

Did you try adding

return myApp.exec_()

exec_() will return an integer. (usually 0)