[SOLVED] QString and .arg()
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Hi Guys,
Need some help. As usual.
Is it possible to split the QString and .arg() parts.
For example:
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QString phrase = "bingo";
QString test1 = ("%1");
test1.arg(phrase);
qDebug() << test1;
@
I am trying to make it work but when I run the program it is displaying "%1" not "bingo" as I had expected.
Thanks
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Hi,
"QString::arg":http://qt-project.org/doc/qt-5/qstring.html#arg returns a copy so you should assign it to other QString and the print.
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QString tmp = test1.arg(phrase);
qDebug() << tmp;
@or
@
qDebug() << test1.arg(phrase);
@ -
Thanks Gene. But the problem is something is as given below:
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QString Entertainment::toString(bool labeled, QString sepchar) const{
QString result("%1/ilm Type: %3Oilm Rating: %5");
if(!labeled){
result = QString("%1%2%3%4%5");
}
return result.arg(Film::toString(labeled, sepchar)).arg(sepchar).arg(FilmTypesStrings.at(m_Type)).arg(sepchar)
.arg(MPAARatingsStrings.at(m_Rating));
}
@What I cannot understand in the above is:
In line 2 how is the result getting its values?
In line 4 how is result getting its values?
Thanks again.
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It is getting from here
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return result.arg(Film::toString(labeled, sepchar)).arg(sepchar).arg(FilmTypesStrings.at(m_Type)).arg(sepchar)
.arg(MPAARatingsStrings.at(m_Rating));
@ -
You're Welcome :)
bq. Am I correct in saying that in line 2 and line 4 in my code it is just QString “result” is just creating a place holder.
Yes.
bq. and the actual arguments are given when it is “result” being returned?
Yes, the function first gets executed and then the result is returned.
