[SOLVED] QString and .arg()

[Paawan]

Hi Guys,

Need some help. As usual.

Is it possible to split the QString and .arg() parts.

For example:

@

QString phrase = "bingo";

QString test1 = ("%1");

test1.arg(phrase);

qDebug() << test1;

@

I am trying to make it work but when I run the program it is displaying "%1" not "bingo" as I had expected.

Thanks

[p3c0]

Hi,

"QString::arg":http://qt-project.org/doc/qt-5/qstring.html#arg returns a copy so you should assign it to other QString and the print.

@
QString tmp = test1.arg(phrase);
qDebug() << tmp;
@

or

@
qDebug() << test1.arg(phrase);
@

[Paawan]

Thanks Gene. But the problem is something is as given below:

@
QString Entertainment::toString(bool labeled, QString sepchar) const{
QString result("%1/ilm Type: %3Oilm Rating: %5");
if(!labeled){
result = QString("%1%2%3%4%5");
}
return result.arg(Film::toString(labeled, sepchar)).arg(sepchar).arg(FilmTypesStrings.at(m_Type)).arg(sepchar)
.arg(MPAARatingsStrings.at(m_Rating));
}
@

What I cannot understand in the above is:

In line 2 how is the result getting its values?

In line 4 how is result getting its values?

Thanks again.

[p3c0]

It is getting from here
@
return result.arg(Film::toString(labeled, sepchar)).arg(sepchar).arg(FilmTypesStrings.at(m_Type)).arg(sepchar)
.arg(MPAARatingsStrings.at(m_Rating));
@

[Paawan]

Ok.

Am I correct in saying that in line 2 and line 4 in my code it is just QString "result" is just creating a place holder.

and the actual arguments are given when it is "result" being returned?

Thanks again.

[Paawan]

Tried it out.

It works.

Thank you for explaining it to me.

[p3c0]

You're Welcome :)

bq. Am I correct in saying that in line 2 and line 4 in my code it is just QString “result” is just creating a place holder.

Yes.

bq. and the actual arguments are given when it is “result” being returned?

Yes, the function first gets executed and then the result is returned.