[Solved]Program exited with code 0
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wrote on 15 Nov 2012, 07:26 last edited by
- Find error in your code
or/and - Check for correctness your index @(index >= 0 && index < vec.size())@ before operator[]
if (index == -1) is an exit condition - just exit from your app :-))
- Find error in your code
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wrote on 15 Nov 2012, 07:56 last edited by
The index is initialized to '0'.
Some formats are there to enter the Question and Answers in Database, through editor.
While the Question is entered the parseQuestion function is called.
While the Answer is entered the parseOption function is called.
In the parseOption function, the condition is checked. The function includes the index,option,stmt,phrase .
The phrase is the one entered within the '| ' (eg |Lotus\ is our national flower) In this eg to highlight "Lotus" we are using the '| ' symbol.
In the above eg Lotus is the phrase, if any stmt seen before the phrase is considered as stmt1,and after the phrase is the stmt2.I give another eg.
If i am entering a Ques and Ans like this
What is Qt?
Qt is a |cross platform application framework
Qt is a is the stmt1
*|cross platform application framework* is the phraseWhile running with above eg my code runs fine and every thing enters into the database.
But when i am entering like this
What is Qt?
Qt is a |cross platform application framework\ .
Qt is a is the stmt1
*|cross platform application framework* is the phrase
.. is considered as the stmt2 and returns the index value as '-1' since there is no '|'
The following is the condition it checks for the stmt2, and no '|' is seen so returning '-1'until for stmt1 amd the phrase it reads the index value as +ve value only.
bt when reading the stmt2 it is returning '-1'.@
while(option[index] != '|')
{
stmt1[j] = option[index];
cout<<"stmt1[j]\n"<<stmt1<<endl;
if(option[index]=='\0')
{
stmt1[j] = '\0';
option[0] = '\0';
return -1; //here it returns '-1'
}
index++;
j++;
}
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wrote on 15 Nov 2012, 08:13 last edited by
You should check for '|' and NOT '\0'.
E.g.:
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while(option[index] != '|' &&
option[index] != '\0')
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wrote on 15 Nov 2012, 09:04 last edited by
I used some cout stmts to check wat the option of index is.
The option[index] is printing as the "|" symbol.
After the stmt1 the "|" is seen and return the option[index] as "|" and returning the index value as +ve value.
Then when coming to the stmt2 it checks the condition, "|" . The condition is not get satisfied returning "-1".And I also tried wat u said,
@
1.
while(option[index] != '|' &&
2.
option[index] != '\0')
@
It is not taking the phrase value,only it reads the stmt1, and exit from the editor. -
wrote on 15 Nov 2012, 09:06 last edited by
try to add you check
@
if(option[index]=='\0')
{
stmt1[j] = '\0';
option[0] = '\0';
return -1; //here it returns '-1'
}
@after the loop if you want to exit with code -1.
Why are you using this loop instead of "QString::indexOf":http://qt-project.org/doc/qt-4.8/qstring.html#indexOf
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wrote on 15 Nov 2012, 09:16 last edited by
Ya i checked by adding the "if" after the loop.
But it doesn't exit from the loop, runs until i stop the execution. -
wrote on 15 Nov 2012, 09:18 last edited by
- Is option a QString?
- Is option ends with '\0'?
If 1 and 2 are true than this loop shouldn't be infinite.
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wrote on 15 Nov 2012, 09:30 last edited by
ya the option is QString only.
You asked me to check the "if" by adding it after the loop. By adding it after the loop only becomes infinite. -
wrote on 15 Nov 2012, 09:39 last edited by
Should this help?
@
int pos1 = option.indexOf('|');
if (pos1 != -1)
{
stmt1 = option.left(pos1);int pos2 = option.indexOf('\\', pos1); if (pos2 != -1) { phrase = option.mid(pos1, pos2 - pos1); }
else
{
// there is no '|' symbol in option
}
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wrote on 15 Nov 2012, 10:11 last edited by
Ya i tried tis by replacing tat, bt it is still the same not exiting from the loop, also printing the stmt as null.
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wrote on 15 Nov 2012, 10:25 last edited by
You shouldn't use a single backslash in option string, because it will be processed as '.' in second case.
So, before processing, replace single backslashes with doubled or select another symbol -
wrote on 15 Nov 2012, 10:33 last edited by
This means whether you are asking me to use double backslash in the phrase itself or at the end of last stmt i've to put double backslash.
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wrote on 15 Nov 2012, 11:23 last edited by
By trying with this code,
@
1.int pos1 = option.indexOf('|');
2.if (pos1 != -1)
3. {
4. stmt1 = option.left(pos1);
5. int pos2 = option.indexOf('\', pos1);
7. if (pos2 != -1)
8. {
9. phrase = option.mid(pos1, pos2 - pos1);
10 }
11. else
12. {
13. // there is no '|' symbol in option
14. }
@
I am getting this error "commitdb.cpp:1219: error: a function-definition is not allowed here before ‘{’ token" in some other functions.
so i removed this code and compile with the the original code itself.@@ -
wrote on 15 Nov 2012, 12:08 last edited by
add } before else
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wrote on 15 Nov 2012, 12:23 last edited by
Ya i added }
Now it is not exiting from the editor and its working.
But, the question is entering into database finely, the answer is not entering to the database (i.e options) printing the null values for option,stmt1 and stmt2 . Also the null values are entering to database more than once -
wrote on 15 Nov 2012, 12:26 last edited by
Sorry, I don't understand what you do you want.
- Insert some values into some db?
- something else?
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wrote on 15 Nov 2012, 12:34 last edited by
no through editor i am entering the Ques and answer also
The xml file generates, from the xml file to database it is entering, bt the Ques is entering into the database correctly.
The options i.e Qt is a |cross platform\ appln framework is the Answer stmt.
Bt this enters the database as null value only not the stmt or phrase -
wrote on 15 Nov 2012, 12:37 last edited by
My code is not processing statements with asterisk (*), so you should add this by yourself ;-)
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wrote on 16 Nov 2012, 03:42 last edited by
No thats not my problem.
After replacing my code with the code wat u give me to replace with, the following is the table entries now.
The following table for Question entries
QNo | Question | QueLocLang | Board | Subject | Chapter | PageNo
4724 | What is Qt? | NULL | Tamil Nadu | EnglishI | 1 | 1
4725 | Who is Sachin? | NULL | Tamil Nadu | EnglishI | 1 | 1
The table entries for Answers is,
More than one time it is entering like the followingAPNo | Statement1 | Statement2 | Option1 | QNo
80563 | | NULL | | 4724
80564 | | NULL | | 4724
80565 | | NULL | | 4724
80566 | | NULL | | 4725
80567 | | NULL | | 4725
80568 | | NULL | | 4725
The actual Answer table should be like,
APNo | Statement1 | Statement2 | Option1 | QNo
80563 | Qt is a | NULL | cross platform application framework | 4724
80564 | | is sachin | A famous crickter | 4725
But i am not getting like this. I am just getting the empty values for stmt1,option.
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wrote on 16 Nov 2012, 05:30 last edited by
Instead of the following code
@
int mainForm::parseOption(int ind,QString option, QString &stmt1, QString &phrase)
{
QTextStream cout(stdout, QIODevice::WriteOnly);
int j = 0;
int index = ind;
cout<<"index---\n"<<index<<endl;
cout<<"311 : parseOption : "<<option<<endl;
cout<<"option[index]--\n"<<option[index]<<endl;
while(option[index] != '|')
{
stmt1[j] = option[index];
cout<<"stmt1[j]\n"<<stmt1<<endl;
if(option[index]=='\0')
{
cout<<"option[index]-----\n"<<option[index]<<endl;
stmt1[j] = '\0';
option[0] = '\0';
return -1;
// return (index);
}
index++;
j++;
}
stmt1[j] = '\0';
stmt1=stmt1.replace( "{sub}","<sub>");
stmt1=stmt1.replace( "{/sub}","</sub>" );while(option[index] != '\')
{
phrase[j] = option[index];
index++;
j++;
}cout<<"425 : "<<stmt1<<endl;
j = 0;
index++;
cout<<"option[index]-->\n"<<option[index]<<endl;
phrase=phrase.replace( "{sub}","<sub>" );
phrase=phrase.replace( "{sub}","<sub>" );
cout<<"Phrase value"<<phrase<<endl;
phrase[j] = '\0';
cout<<"436 : "<<phrase<<endl;return (index + 1);
}
@I added the code u asked me to add
@
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int pos1 = option.indexOf('|');
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if (pos1 != -1)
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{
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stmt1 = option.left(pos1);
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int pos2 = option.indexOf('\\', pos1);
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if (pos2 != -1)
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{
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phrase = option.mid(pos1, pos2 - pos1);
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}
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else
- {
- // there is no '|' symbol in option
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}
@
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