[Solved]Program exited with code 0

[AlekseyOk]

This means that you are trying to make something like this:

@
QVector<int> vec;
vec[-1] = 0;
@

[gayu]

ya, in my code it is returning the index value "index=-1". so it is exiting.
It should not return the "-1". I am trying to solve, bt i dont know how to solve this. please help me

[AlekseyOk]

1. Find error in your code
   or/and
2. Check for correctness your index @(index >= 0 && index < vec.size())@ before operator[]

if (index == -1) is an exit condition - just exit from your app :-))

[gayu]

The index is initialized to '0'.
Some formats are there to enter the Question and Answers in Database, through editor.
While the Question is entered the parseQuestion function is called.
While the Answer is entered the parseOption function is called.
In the parseOption function, the condition is checked. The function includes the index,option,stmt,phrase .
The phrase is the one entered within the '| ' (eg |Lotus\ is our national flower) In this eg to highlight "Lotus" we are using the '| ' symbol.
In the above eg Lotus is the phrase, if any stmt seen before the phrase is considered as stmt1,and after the phrase is the stmt2.

I give another eg.

If i am entering a Ques and Ans like this

What is Qt?
Qt is a |cross platform application framework
Qt is a is the stmt1
*|cross platform application framework* is the phrase

While running with above eg my code runs fine and every thing enters into the database.

But when i am entering like this

What is Qt?
Qt is a |cross platform application framework\ .
Qt is a is the stmt1
*|cross platform application framework* is the phrase
.. is considered as the stmt2 and returns the index value as '-1' since there is no '|'
The following is the condition it checks for the stmt2, and no '|' is seen so returning '-1'

until for stmt1 amd the phrase it reads the index value as +ve value only.
bt when reading the stmt2 it is returning '-1'.

@
while(option[index] != '|')
{
stmt1[j] = option[index];
cout<<"stmt1[j]\n"<<stmt1<<endl;
if(option[index]=='\0')
{
stmt1[j] = '\0';
option[0] = '\0';
return -1; //here it returns '-1'
}
index++;
j++;
}
@

[AlekseyOk]

You should check for '|' and NOT '\0'.

E.g.:

@
while(option[index] != '|' &&
option[index] != '\0')
@

[gayu]

I used some cout stmts to check wat the option of index is.
The option[index] is printing as the "|" symbol.
After the stmt1 the "|" is seen and return the option[index] as "|" and returning the index value as +ve value.
Then when coming to the stmt2 it checks the condition, "|" . The condition is not get satisfied returning "-1".

And I also tried wat u said,
@
1.
while(option[index] != '|' &&
2.
option[index] != '\0')
@
It is not taking the phrase value,only it reads the stmt1, and exit from the editor.

[AlekseyOk]

try to add you check

@
if(option[index]=='\0')
{
stmt1[j] = '\0';
option[0] = '\0';
return -1; //here it returns '-1'
}
@

after the loop if you want to exit with code -1.

Why are you using this loop instead of "QString::indexOf":http://qt-project.org/doc/qt-4.8/qstring.html#indexOf

[gayu]

Ya i checked by adding the "if" after the loop.
But it doesn't exit from the loop, runs until i stop the execution.

[AlekseyOk]

1. Is option a QString?
2. Is option ends with '\0'?

If 1 and 2 are true than this loop shouldn't be infinite.

[gayu]

ya the option is QString only.
You asked me to check the "if" by adding it after the loop. By adding it after the loop only becomes infinite.

[AlekseyOk]

Should this help?

@
int pos1 = option.indexOf('|');
if (pos1 != -1)
{
stmt1 = option.left(pos1);

int pos2 = option.indexOf('\\', pos1);
if (pos2 != -1)
{
    phrase = option.mid(pos1, pos2 - pos1);
}

else
{
// there is no '|' symbol in option
}
@

[gayu]

Ya i tried tis by replacing tat, bt it is still the same not exiting from the loop, also printing the stmt as null.

[AlekseyOk]

You shouldn't use a single backslash in option string, because it will be processed as '.' in second case.
So, before processing, replace single backslashes with doubled or select another symbol

[gayu]

This means whether you are asking me to use double backslash in the phrase itself or at the end of last stmt i've to put double backslash.

[gayu]

By trying with this code,

@
1.int pos1 = option.indexOf('|');
2.if (pos1 != -1)
3. {
4. stmt1 = option.left(pos1);
5. int pos2 = option.indexOf('\', pos1);
7. if (pos2 != -1)
8. {
9. phrase = option.mid(pos1, pos2 - pos1);
10 }
11. else
12. {
13. // there is no '|' symbol in option
14. }
@
I am getting this error "commitdb.cpp:1219: error: a function-definition is not allowed here before ‘{’ token" in some other functions.
so i removed this code and compile with the the original code itself.@@

[AlekseyOk]

add } before else

[gayu]

Ya i added }
Now it is not exiting from the editor and its working.
But, the question is entering into database finely, the answer is not entering to the database (i.e options) printing the null values for option,stmt1 and stmt2 . Also the null values are entering to database more than once

[AlekseyOk]

Sorry, I don't understand what you do you want.

1. Insert some values into some db?
2. something else?

[gayu]

no through editor i am entering the Ques and answer also
The xml file generates, from the xml file to database it is entering, bt the Ques is entering into the database correctly.
The options i.e Qt is a |cross platform\ appln framework is the Answer stmt.
Bt this enters the database as null value only not the stmt or phrase

[AlekseyOk]

My code is not processing statements with asterisk (*), so you should add this by yourself ;-)