QT virtualkeyboard size

[A Former User]

Hello everyone!

I'm fighting with keyboard size. I would like to get the right keyboard position based on size.

// variant 1
InputPanel {
   x:1
   y:1
   height: 100
   width: 100

Keyboard is exactly on the position where it has to be 1x1[px] from 0x0.

// variant 2
InputPanel {
   x:1
   y:1
   height: 100
   width: 200

Now the keyboard has width set to 200 and suddenly both of coordinates are not matching. Which is little bit strange to me.

// variant 3
InputPanel {
   x:1
   y:51 //<--- why there is an needed offset?
   height: 100
   width: 200

Last measurement show, that if I set height to the same value as width, 1x1[px] offset is ok. So what's the ratio between width and height?
The main reason why I'm asking about keyboard coordinates is that, I would like to set the max keyboard with/height in landscape/portrait mode. I need to know the XY due to keyboard rotation.

Regards,
Andy

[IntruderExcluder]

According to docs the application should only set the width and y coordinates of the InputPanel, and not the height. Probably you doing something wrong.

[A Former User]

Yes, I tried to set only with according to documentation. It works in landscape mode. But if I rotate the keyboard and set width only, it is working like I described.