Solved layout->removeWidget(QWidget*) not working correctly

[Daniel_Contro]

Hi to everyone,
I'm developing an application which has different custom widgets. In particulate I have derived the QScrollArea widget for adding my own widgets to it. So far I can easily add widgets to it, but when it comes to deleting a widget it's kinda buggy, half of the widget disappear, but the remaining half is still visible and interactive. The following is my current code:

void TasksList::removeTask(const unsigned short taskId) {
  auto children = _layout->children();
  for (auto i = 0; i < _layout->count(); i++) {
    TaskPreview* tmp = dynamic_cast<TaskPreview*>(_layout->itemAt(i)->widget());
    if (tmp && (tmp->getId() == taskId)) {
      _layout->removeWidget(tmp);
    }
  }
}

I should also point out that _layout is a pointer to the QScrollArea's associated widget layout.

[Bonnie]

void QLayout::removeWidget(QWidget *widget)
Removes the widget widget from the layout. After this call, it is the caller's responsibility to give the widget a reasonable geometry or to put the widget back into a layout or to explicitly hide it if necessary.

If you don't need the removed widget anymore, don't forget to delete it.

[Bonnie]

void QLayout::removeWidget(QWidget *widget)
Removes the widget widget from the layout. After this call, it is the caller's responsibility to give the widget a reasonable geometry or to put the widget back into a layout or to explicitly hide it if necessary.

If you don't need the removed widget anymore, don't forget to delete it.

[Daniel_Contro]

Thank you, I actually commented out the delete because I wasn't sure of the removeWidget behaviour, now it works flawlessly