Error: use of undeclared identifier: exception in template class

[Infinity]

I would like to create this template class:

#include <sstream>
#include <string>
#include <exception>

template<class T>
std::string ToStr(const T &value)
{
  std::ostringstream oss;
  if (!(oss << std::dec << value)) throw exception("Invalid argument");
  return oss.str();
}

But I get the following compiler error:

error: use of undeclared identifier 'exception'
.../conversions.h:41: Fehler: there are no arguments to ‘exception’ that depend on a template parameter, so a declaration of ‘exception’ must be available [-fpermissive]
   41 |   if(!(iss>>std::dec>>result))throw exception("Invalid argument");
      |                                     ^~~~~~~~~

How do I have to handle that?

[Christian Ehrlicher]

@Infinity said in Error: use of undeclared identifier: exception in template class:

How do I have to handle that?

There is no class 'exception' somewhere. It's maybe std::exception what you're looking for.

[Infinity]

I found the solution:

#include <sstream>
#include <string>
#include <exception>

class MyException : public std::exception
{
    virtual const char* what() const throw() {
        return "Invalid argument";
    }
};

MyException myException;

//---------------------------------------------------------------------------
// Convert a number to a string

template<class T>
std::string NumberToStr(const T &value)
{
    std::ostringstream oss;
    if (!(oss << std::dec << value)) throw myException;
    return oss.str();
}