@mrjj Thank you very much! Problem solved.

@badr
You have one table widget (or similar, actually presumably QTableView rather than QTableWidget since you have your own model) holding rows & columns from a SQL query. You say you want another table widget to show a column "computed" (at client side) from columns in the first one.

So why not create a second model whose data() method is overridden to perform the necessary computation and return the desired final string for Qt::DisplayRole using the index.row/column() (not just the index) as indexers into the SQL model's rows/columns?

Or, if you want to stick with your current usage of QTableWidget (not ideal that you use Python SQL calls and copy result set into that, but up to you), you could make your second one a QTableWidget too and use setData() to populate its rows/columns with the actual corresponding strings whenever the first one changes (more work depending on how often your data changes, but in your case it might only be during loaddata() when you populate if it does not change thereafter).

Hi,

You can put your QStackedLayout and buttons in a QVBoxLayout so you can re-use the buttons. Put that layout in a QWidget and set that widget as the central widget of your QMainWindow.

Hi and welcome to devnet,

How are you building your executable ?
What version of PyQt5 and Qt are you using ?

Since you are using PyQt, you might want to consider contacting its authors.

@raven-worx you sir saved my life! I cant believe i was stuck at this for 2 days, when it was simply just about using the right object in qml. thanks!

Hi,

Looks like there's some problem with the PySide 2 implementation. You should check the bug report system to see if it's something known. If not, please consider opening a new report providing your example and as much details as possible about your current setup.

@MATTK said in Configuring checkbox when using QTreeWidget:

is this a bug or a known issue from Qt Designer?

No, it's 100% intended behaviour. the condition is checked here

You have 2 options:

set the Qt::CheckStateRole for the indexes you want to have a checkbox. In your widget constructor you'd call something like setUnchecked(ui->treeWidget->model()); void setUnchecked(QAbstractItemModel* model, const QModelIndex& parent = QModelIndex()){ if(!model) return; for(int i=0, maxRow=model->rowCount(parent);i<maxRow;++i){ for(int j=0, maxCol=model->columnCount(parent);j<maxCol;++j){ const QModelIndex currIdx = model->index(i,j,parent); model->setData(currIdx,Qt::Unchecked,Qt::CheckStateRole); if(model->hasChildren(currIdx)) setUnchecked(model,currIdx); } } } subclass the delegate to check the flag instead of Qt::CheckStateRole and call something like ui->treeWidget->setItemDelegate(new CheckFlagDelegate(this)); in your widget constructor class CheckFlagDelegate : public QStyledItemDelegate{ Q_OBJECT Q_DISABLE_COPY(CheckFlagDelegate) public: explicit CheckFlagDelegate(QObject* parent = Q_NULLPTR) : QStyledItemDelegate(parent){} protected: void initStyleOption(QStyleOptionViewItem *option, const QModelIndex &index) const Q_DECL_OVERRIDE{ QStyledItemDelegate::initStyleOption(option,index); if(index.model()->flags(index) & Qt::ItemIsUserCheckable) option->features |= QStyleOptionViewItem::HasCheckIndicator; } };

Since the functionality is defined in a QObject (the delegate) and not in a QWidget this is not something designer can and probably ever will manage

@mrjj okay thank you very much! And yes, my Designer also have a StyleSheet editor like this:

Cheers

Hi there.

I think you can use TableViewColumn element to create a new column inside a TableView component.
If necessary, you can define your own delegate to set how the data is showed to user.

Read more:
http://doc.qt.io/qt-5/qml-qtquick-controls-tableview.html#details <- TableView Documentation
http://doc.qt.io/qt-5/qtquickcontrols-tableview-main-qml.html <- TableView Example

Hi,

You are replacing the central widget in OpenVTK. You should rather add your widget to the current central widget's layout.

def clearvbox(self, L = False): if not L: L = self.vbox if L is not None: while L.count(): item = L.takeAt(0) widget = item.widget() if widget is not None: widget.deleteLater() else: self.clearvbox(item.layout())

Hi,

What résolution are you expecting ?

Well... Then you can translate the example from the class detailed documentation in Python and you have a minimal video player.

@Dl10

Hi
I think it exists

https://www.youtube.com/watch?v=Dmo8eZG5I2w

There you just place 4 qframes on center mainwindow
Then right click (not on frames) and from layout menu
select Grid layout

@Dl10
You may split the function and start a timer.. something like..
from :

testFunction(){ step1.. step2.. time.sleep().. step3.. }

to

testFunction(){ step1.. step2.. qtimer t; connect(&t,SIGNAL(timeOut()),this,SLOT(testFunction2())); t.start(2000); } testFunction2(){ step3... }

PS: Syntax may vary.. this is a c++ code.. please convert it to pyqt5.. Hope this is what you are expecting...
and thats what i understood from your post...

[This post cross-posed to https://forum.qt.io/topic/85493/unicodedecodeerror-with-output-from-windows-os-command/18 ]

For the record, I have done exhaustive investigation, and there is only one solution which "correctly" displays the £ character under Windows. I am exhausted so will keep this brief:

To create a file name with a £ in it: Go into, say, Notepad and use its Save to name a file like abc£.txt. This is in the UK, using a UK keyboard and a standard UK-configured Windows.

Note that at this point if you view the filename in either Explorer or, say, via dir you do see a £, not some other character. That's what my user will want to see in the output of the command he will run.

Run an OS command like robocopy or even dir, which will include the filename in its output.

Read the output with QProcess.readAllStandardOutput(). I'm saying the £ character will arrive as a single byte of value 0x9c.

For the required Python/PyQt decoding bytes->str (QByteArray->QString) line, the only thing which works (does not raise an exception) AND represents the character as a £ is: ba.bytes().decode("cp850").

That is the "Code Page 850", used in UK/Western Europe (so I'm told). It is the result output of you open a Command Prompt and execute just chcp.

Any other decoding either raises UnicodeDecodeError (e.g. if utf-8) or decodes but represents it with another character (e.g. if windows_1252 or cp1252).

I still haven't found a way of getting that cp850 encoding name programatically from anywhere --- if you ask Python for, say, the "system encoding" or "user's preferred encoding" you get the cp1252 --- so I've had to hard-code it. [EDIT: If you want it, it's ctypes.cdll.kernel32.GetConsoleOutputCP().]

So there you are. I don't have C++ as opposed to Python for Qt, but I have a suspicion that if anyone tries it using the straight C++ Qt way of text = QString(process.readAllStandardOutput()) they'll find they do not actually get to see the £ symbol....

@SGaist I need the slot send_console_log to be called when the signal written in ConsoleStream is emitted. When running the program with a normal while/for loop in the interpreter, the slot will be called becuase at that moment its non blocking. But the moment I add time.sleep into a loop, slots will only be called at the end when all the blocking is over. Thank you for looking into this.

A quick google search returns this article which covers most aspects of this subject.

@Pierone Can you put you code in GitHub instead of a rar file? Its pretty awkward to unpack your code.

Thanks @jsulm!! That sorted it!

@alekssandrap
Hello,

I found your topic because I am looking for a virtual keyboard for my PUQT5 application.
So, I found the problem of your error and this is my solution to solve it (maybe that can help some other people) :

In your pyqtSignal you have to pass an object :
sigKeyButtonClicked = pyqtSignal(object) #line 9

sigInputString = pyqtSignal(object) #line 32
sigKeyButtonClicked = pyqtSignal(object) #line 33

Then you have just to pass your key and your inputString in the signal emit :
self.sigKeyButtonClicked.emit(self._key) #line 20

self.sigInputString.emit("") #line111 in function Cancel in order to avoid an other error

Don't modify line 71 with lambda as @AlfredoC suggest because you won't be able to get the key pressed.

That's all :)

Hope that can help someone else.

Have a great day

Thank you! I didnt noticed that. I did correct this mistakes, but still getting the same error:( and empty window :/

Hi,

That's a question you should rather bring to the PyQt forum/mailing list.

@Masonsu your QTextEdit is an implementation detail of your Chatlog widget. You should use e.g. a slot in Chatlog that will internally append the text to your QTextEdit. So if you change it for something else. You don't have to rewrite everything because of that.

I did the test and appearantly it's the painting which is very expensive... with no slot connected, the program takes 1,5 seconds to complete the task. There is a very similar issue reported at https://bugreports.qt.io/browse/QTBUG-49655.

But generally ProgressBars are consuming especially when we update it that often (>365000 times) while there is no significant change at each iteration. So I simply update the QProgressBar less often and the results are good (~1s) and the progression still smooth. PSB :

class ParseFileAsync(QtCore.QThread): match = QtCore.pyqtSignal(str) PBupdate = QtCore.pyqtSignal(int) PBMax = QtCore.pyqtSignal(int) def run(self): with open("test_long.log", "r") as fichier: fileLines = fichier.readlines() self.lineNumber = len(fileLines) self.PBMax.emit(self.lineNumber) if (self.lineNumber < 30): self.parseFile(fileLines, False) else: self.parseFile(fileLines, True) def parseFile(self, fileLines, isBig): cpt = 0 if(isBig): for line in fileLines: cpt+=1 if(cpt % (int(self.lineNumber/30)) == 0): self.PBupdate.emit(cpt) for element in liste: if element in line: self.match.emit(line) self.PBupdate.emit(self.lineNumber) #To avoid QProgressBar stopping at 99% else: for line in fileLines: cpt+=1 self.PBupdate.emit(cpt) for element in liste: if element in line: self.match.emit(line)

super :)
also using "#MainWindow" makes sure it dont apply to childs as stylesheets does.

Hi and welcome
not directly an answer, but have you looked at the example ?
http://doc.qt.io/qt-5/qtwidgets-dialogs-findfiles-example.html

there is also QFileSystemModel
http://doc.qt.io/qt-5/qfilesystemmodel.html#details
to be used with views.

also, just to be sure u saw it
http://doc.qt.io/qt-5/model-view-programming.html

Good intro on how it fits together.

Hello,
Well it's says there in the question. Don't pass a QWindow to the QFileDialog::getOpenFileName function. A window is not a widget and it expects QWidget. You could just use NULL (or whatever its equivalent in python is).

Kind regards.

Hi and welcome to devnet,

How are you updating your progress bar ?

Hi, thanks!

I call the child QMainWindow from the parent QMainWindow as follows:

self.responseBox = responseBox(self)

This is the code initializing the child QMainWindow:

class responseBox(QMainWindow): def __init__(self, parent): QMainWindow.__init__(self, parent) self.setWindowFlags(QtCore.Qt.Window | QtCore.Qt.CustomizeWindowHint | QtCore.Qt.WindowMinimizeButtonHint | QtCore.Qt.WindowMaximizeButtonHint) self.setWindowModality(Qt.NonModal)

The full source code of the application is available online:
https://github.com/sam81/pychoacoustics
The child main window is created on line 834 here
and the code initializing it is here

I'll try to generate a small reproducible example and post it here as soon as I have time.

@errolflynn You should write self.button1.clicked.connect(ft_handler) - this will register the function ft_handler as a slot for the clicked signal. On http://doc.qt.io/qt-5/qabstractbutton.html you see that the signature of that signal is void clicked(bool checked). In other words, when the signal is activated, your handler is called as ft_handler(checked) where checked is either True or False. Per the signature of the clicked signal, this is the only information you will get out of the signal.

If you want to pass additional parameters, you indeed will need to create a separate function that encodes those extra parameters and passes them to the handler. In Python it makes a lot of sense to use a lambda for it, for instance:
self.button1.clicked.connect(lambda checked: fct_handler(par1, par2, par3, checked))

Hope this helps