Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • Users
  • Groups
  • Search
  • Get Qt Extensions
  • Unsolved
Collapse
Brand Logo
  1. Home
  2. Qt Development
  3. Qt for Python
  4. Pyside2.QtCore.QThread.terminate() Cause python to crash
Forum Update on Monday, May 27th 2025

Pyside2.QtCore.QThread.terminate() Cause python to crash

Scheduled Pinned Locked Moved Solved Qt for Python
19 Posts 5 Posters 2.7k Views
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • jsulmJ jsulm

    @brianmeasley said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

    This is not the problem

    If this is not the problem then post something which is actually related to your problem. Or should we guess?

    B Offline
    B Offline
    brianmeasley
    wrote on last edited by brianmeasley
    #7

    @jsulm

    Unable to connect because the target computer actively refused it

    Did you see this?
    I guess you should catch the exceptions from urllib.

    This is not the problem

    If this is not the problem then post something which is actually related to your problem. Or should we guess?

    What I actually said is that there is no problem with urllib, because the same code runs without problems in PySide6. You can run the above code and click the Start button repeatedly and it will crash (remember to replace the URL variable with a downloadable file ).
    If it is a problem with urllib, the same problem should also occur in PySide6, but now the problem seems to only occur in PySide2.
    The specific problem is that I found that by subclassing QThread in PySide2 and overriding the run method, when running some I/O operations that require waiting, if I want to terminate the thread immediately and execute QThread.terminate(), it will cause the entire Python program to crash.

    This problem also occurs when using the paramiko library and other operations that require network I/O. I wonder if you can understand the problem I encountered?

    jsulmJ 1 Reply Last reply
    0
    • B brianmeasley

      @jsulm

      Unable to connect because the target computer actively refused it

      Did you see this?
      I guess you should catch the exceptions from urllib.

      This is not the problem

      If this is not the problem then post something which is actually related to your problem. Or should we guess?

      What I actually said is that there is no problem with urllib, because the same code runs without problems in PySide6. You can run the above code and click the Start button repeatedly and it will crash (remember to replace the URL variable with a downloadable file ).
      If it is a problem with urllib, the same problem should also occur in PySide6, but now the problem seems to only occur in PySide2.
      The specific problem is that I found that by subclassing QThread in PySide2 and overriding the run method, when running some I/O operations that require waiting, if I want to terminate the thread immediately and execute QThread.terminate(), it will cause the entire Python program to crash.

      This problem also occurs when using the paramiko library and other operations that require network I/O. I wonder if you can understand the problem I encountered?

      jsulmJ Offline
      jsulmJ Offline
      jsulm
      Lifetime Qt Champion
      wrote on last edited by
      #8

      @brianmeasley Sorry, I will not run anything. That you can do and post the stack trace here.
      Also, if you press this button repeatedly without waiting for the previous request to finish your previous QThread instance will be probably deleted by garbage collector.

      https://forum.qt.io/topic/113070/qt-code-of-conduct

      B 1 Reply Last reply
      1
      • jsulmJ jsulm

        @brianmeasley Sorry, I will not run anything. That you can do and post the stack trace here.
        Also, if you press this button repeatedly without waiting for the previous request to finish your previous QThread instance will be probably deleted by garbage collector.

        B Offline
        B Offline
        brianmeasley
        wrote on last edited by
        #9

        @jsulm

        Sorry, I will not run anything. That you can do and post the stack trace here.

        This is the code that runs:

        import io
        import sys
        import time
        import typing
        from contextlib import suppress
        
        import paramiko
        from PySide2.QtCore import QThread
        from PySide2.QtWidgets import QApplication, QWidget, QGridLayout, QPushButton
        
        
        def ssh_connect(ssh_client: paramiko.SSHClient,
                        hostname: str,
                        port=paramiko.config.SSH_PORT,
                        username: str = None,
                        password: str = None,
                        pkey: str = None,
                        **kwargs) -> paramiko.SSHClient:
            __doc__ = paramiko.SSHClient.__doc__
        
            ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy)
        
            if isinstance(pkey, str):
                pkey = paramiko.RSAKey.from_private_key(io.StringIO(pkey))
        
            hostname = hostname.strip()
            username = username.strip()
        
            if password == '':
                with suppress(paramiko.ssh_exception.AuthenticationException):
                    ssh_client.connect(hostname, port, username=username, password='', pkey=pkey, **kwargs)
                ssh_client.get_transport().auth_none(username)
            else:
                ssh_client.connect(hostname, port, username=username, password=password, pkey=pkey, **kwargs)
            return ssh_client
        
        
        class MyThread(QThread):
            def run(self) -> None:
                client = paramiko.SSHClient()
                while True:
                    ssh_connect(client, '192.168.1.4', 22, 'root', ' ')
                    if client.get_transport().active:
                        client.close()
                    time.sleep(0.1)
        
        
        class Window(QWidget):
            def __init__(self, parent=None):
                super().__init__(parent)
                self._thread: typing.Optional[QThread] = None
                self.grid = QGridLayout(self)
                self.btn = QPushButton("Start", self)
                self.btn.clicked.connect(self.on_btn_clicked)
                self.grid.addWidget(self.btn)
        
            def on_btn_clicked(self, clicked=False):
                self.btn.setDisabled(True)
                if self._thread is not None:
                    if self._thread.isRunning():
                        self._thread.terminate()
                    self._thread = None
                    self.btn.setText("Start")
                else:
                    self._thread = MyThread()
                    self._thread.setTerminationEnabled(True)
                    self._thread.start()
                    self.btn.setText("Stop")
                self.btn.setDisabled(False)
        
        
        def main():
            app = QApplication(sys.argv)
            window = Window()
            window.show()
        
            sys.exit(app.exec_())
        
        
        if __name__ == '__main__':
            main()
        
        

        After running the code, I clicked the Start button twice. The second button was used to call and kill the running QThread, but the following error occurred. This problem does not exist in PySide6:

        Fatal Python error: This thread state must be current when releasing
        Python runtime state: initialized
        
        Thread 0x00007f8476872700 (most recent call first):
          File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 100 in _read_all
          File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 95 in _send_message
          File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 434 in sign_ssh_data
          File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 395 in _parse_service_accept
          File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 2164 in run
          File "/usr/lib/python3.8/threading.py", line 932 in _bootstrap_inner
          File "/usr/lib/python3.8/threading.py", line 890 in _bootstrap
        
        Current thread 0x00007f84770b3700 (most recent call first):
          File "/usr/lib/python3.8/threading.py", line 306 in wait
          File "/usr/lib/python3.8/threading.py", line 558 in wait
          File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 240 in wait_for_response
          File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 1635 in auth_publickey
          File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 702 in _auth
          File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 435 in connect
          File "/home/wo/Dev/main.py", line 34 in ssh_connect
          File "/home/wo/Dev/main.py", line 42 in run
        
        Thread 0x00007f849f735740 (most recent call first):
          File "/home/wo/Dev/main.py", line 77 in main
          File "/home/wo/Dev/main.py", line 81 in <module>
        
        Process finished with exit code 134 (interrupted by signal 6: SIGABRT)
        
        SGaistS jeremy_kJ 2 Replies Last reply
        0
        • B brianmeasley

          @jsulm

          Sorry, I will not run anything. That you can do and post the stack trace here.

          This is the code that runs:

          import io
          import sys
          import time
          import typing
          from contextlib import suppress
          
          import paramiko
          from PySide2.QtCore import QThread
          from PySide2.QtWidgets import QApplication, QWidget, QGridLayout, QPushButton
          
          
          def ssh_connect(ssh_client: paramiko.SSHClient,
                          hostname: str,
                          port=paramiko.config.SSH_PORT,
                          username: str = None,
                          password: str = None,
                          pkey: str = None,
                          **kwargs) -> paramiko.SSHClient:
              __doc__ = paramiko.SSHClient.__doc__
          
              ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy)
          
              if isinstance(pkey, str):
                  pkey = paramiko.RSAKey.from_private_key(io.StringIO(pkey))
          
              hostname = hostname.strip()
              username = username.strip()
          
              if password == '':
                  with suppress(paramiko.ssh_exception.AuthenticationException):
                      ssh_client.connect(hostname, port, username=username, password='', pkey=pkey, **kwargs)
                  ssh_client.get_transport().auth_none(username)
              else:
                  ssh_client.connect(hostname, port, username=username, password=password, pkey=pkey, **kwargs)
              return ssh_client
          
          
          class MyThread(QThread):
              def run(self) -> None:
                  client = paramiko.SSHClient()
                  while True:
                      ssh_connect(client, '192.168.1.4', 22, 'root', ' ')
                      if client.get_transport().active:
                          client.close()
                      time.sleep(0.1)
          
          
          class Window(QWidget):
              def __init__(self, parent=None):
                  super().__init__(parent)
                  self._thread: typing.Optional[QThread] = None
                  self.grid = QGridLayout(self)
                  self.btn = QPushButton("Start", self)
                  self.btn.clicked.connect(self.on_btn_clicked)
                  self.grid.addWidget(self.btn)
          
              def on_btn_clicked(self, clicked=False):
                  self.btn.setDisabled(True)
                  if self._thread is not None:
                      if self._thread.isRunning():
                          self._thread.terminate()
                      self._thread = None
                      self.btn.setText("Start")
                  else:
                      self._thread = MyThread()
                      self._thread.setTerminationEnabled(True)
                      self._thread.start()
                      self.btn.setText("Stop")
                  self.btn.setDisabled(False)
          
          
          def main():
              app = QApplication(sys.argv)
              window = Window()
              window.show()
          
              sys.exit(app.exec_())
          
          
          if __name__ == '__main__':
              main()
          
          

          After running the code, I clicked the Start button twice. The second button was used to call and kill the running QThread, but the following error occurred. This problem does not exist in PySide6:

          Fatal Python error: This thread state must be current when releasing
          Python runtime state: initialized
          
          Thread 0x00007f8476872700 (most recent call first):
            File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 100 in _read_all
            File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 95 in _send_message
            File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 434 in sign_ssh_data
            File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 395 in _parse_service_accept
            File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 2164 in run
            File "/usr/lib/python3.8/threading.py", line 932 in _bootstrap_inner
            File "/usr/lib/python3.8/threading.py", line 890 in _bootstrap
          
          Current thread 0x00007f84770b3700 (most recent call first):
            File "/usr/lib/python3.8/threading.py", line 306 in wait
            File "/usr/lib/python3.8/threading.py", line 558 in wait
            File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 240 in wait_for_response
            File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 1635 in auth_publickey
            File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 702 in _auth
            File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 435 in connect
            File "/home/wo/Dev/main.py", line 34 in ssh_connect
            File "/home/wo/Dev/main.py", line 42 in run
          
          Thread 0x00007f849f735740 (most recent call first):
            File "/home/wo/Dev/main.py", line 77 in main
            File "/home/wo/Dev/main.py", line 81 in <module>
          
          Process finished with exit code 134 (interrupted by signal 6: SIGABRT)
          
          SGaistS Offline
          SGaistS Offline
          SGaist
          Lifetime Qt Champion
          wrote on last edited by
          #10

          Hi,

          There might have been changed between PySide6 and 2 with regard to thread termination however and in any case, thread termination like that should be the last resort when there's no other solution.

          Since you thread contains an infinite loop, you should use QThread::isInterruptionRequested and QThread::requestInterruption to cleanly stop your thread.

          Interested in AI ? www.idiap.ch
          Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

          B 1 Reply Last reply
          1
          • B brianmeasley

            @jsulm

            Sorry, I will not run anything. That you can do and post the stack trace here.

            This is the code that runs:

            import io
            import sys
            import time
            import typing
            from contextlib import suppress
            
            import paramiko
            from PySide2.QtCore import QThread
            from PySide2.QtWidgets import QApplication, QWidget, QGridLayout, QPushButton
            
            
            def ssh_connect(ssh_client: paramiko.SSHClient,
                            hostname: str,
                            port=paramiko.config.SSH_PORT,
                            username: str = None,
                            password: str = None,
                            pkey: str = None,
                            **kwargs) -> paramiko.SSHClient:
                __doc__ = paramiko.SSHClient.__doc__
            
                ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy)
            
                if isinstance(pkey, str):
                    pkey = paramiko.RSAKey.from_private_key(io.StringIO(pkey))
            
                hostname = hostname.strip()
                username = username.strip()
            
                if password == '':
                    with suppress(paramiko.ssh_exception.AuthenticationException):
                        ssh_client.connect(hostname, port, username=username, password='', pkey=pkey, **kwargs)
                    ssh_client.get_transport().auth_none(username)
                else:
                    ssh_client.connect(hostname, port, username=username, password=password, pkey=pkey, **kwargs)
                return ssh_client
            
            
            class MyThread(QThread):
                def run(self) -> None:
                    client = paramiko.SSHClient()
                    while True:
                        ssh_connect(client, '192.168.1.4', 22, 'root', ' ')
                        if client.get_transport().active:
                            client.close()
                        time.sleep(0.1)
            
            
            class Window(QWidget):
                def __init__(self, parent=None):
                    super().__init__(parent)
                    self._thread: typing.Optional[QThread] = None
                    self.grid = QGridLayout(self)
                    self.btn = QPushButton("Start", self)
                    self.btn.clicked.connect(self.on_btn_clicked)
                    self.grid.addWidget(self.btn)
            
                def on_btn_clicked(self, clicked=False):
                    self.btn.setDisabled(True)
                    if self._thread is not None:
                        if self._thread.isRunning():
                            self._thread.terminate()
                        self._thread = None
                        self.btn.setText("Start")
                    else:
                        self._thread = MyThread()
                        self._thread.setTerminationEnabled(True)
                        self._thread.start()
                        self.btn.setText("Stop")
                    self.btn.setDisabled(False)
            
            
            def main():
                app = QApplication(sys.argv)
                window = Window()
                window.show()
            
                sys.exit(app.exec_())
            
            
            if __name__ == '__main__':
                main()
            
            

            After running the code, I clicked the Start button twice. The second button was used to call and kill the running QThread, but the following error occurred. This problem does not exist in PySide6:

            Fatal Python error: This thread state must be current when releasing
            Python runtime state: initialized
            
            Thread 0x00007f8476872700 (most recent call first):
              File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 100 in _read_all
              File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 95 in _send_message
              File "/usr/local/lib/python3.8/dist-packages/paramiko/agent.py", line 434 in sign_ssh_data
              File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 395 in _parse_service_accept
              File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 2164 in run
              File "/usr/lib/python3.8/threading.py", line 932 in _bootstrap_inner
              File "/usr/lib/python3.8/threading.py", line 890 in _bootstrap
            
            Current thread 0x00007f84770b3700 (most recent call first):
              File "/usr/lib/python3.8/threading.py", line 306 in wait
              File "/usr/lib/python3.8/threading.py", line 558 in wait
              File "/usr/local/lib/python3.8/dist-packages/paramiko/auth_handler.py", line 240 in wait_for_response
              File "/usr/local/lib/python3.8/dist-packages/paramiko/transport.py", line 1635 in auth_publickey
              File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 702 in _auth
              File "/usr/local/lib/python3.8/dist-packages/paramiko/client.py", line 435 in connect
              File "/home/wo/Dev/main.py", line 34 in ssh_connect
              File "/home/wo/Dev/main.py", line 42 in run
            
            Thread 0x00007f849f735740 (most recent call first):
              File "/home/wo/Dev/main.py", line 77 in main
              File "/home/wo/Dev/main.py", line 81 in <module>
            
            Process finished with exit code 134 (interrupted by signal 6: SIGABRT)
            
            jeremy_kJ Offline
            jeremy_kJ Offline
            jeremy_k
            wrote on last edited by jeremy_k
            #11

            @brianmeasley said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

            This is the code that runs:

                            self._thread.terminate()
            

            Using QThread::terminate() is a terrible idea:
            Warning: This function is dangerous and its use is discouraged. The thread can be terminated at any point in its code path. Threads can be terminated while modifying data. There is no chance for the thread to clean up after itself, unlock any held mutexes, etc.

            On Windows, it appears to be implemented with TerminateThread():
            TerminateThread is a dangerous function that should only be used in the most extreme cases. You should call TerminateThread only if you know exactly what the target thread is doing, and you control all of the code that the target thread could possibly be running at the time of the termination.

            The QThread unix implementation uses pthread_cancel(). The documentation I've seen doesn't carry as bold of a caveat, but it should.

            After running the code, I clicked the Start button twice. The second button was used to call and kill the running QThread, but the following error occurred. This problem does not exist in PySide6:

            Fatal Python error: This thread state must be current when releasing
            Python runtime state: initialized
            

            That looks like the python interpreter complaining that its internal state is not as expected, as might occur if the thread of execution was unexpectedly terminated...

            Asking a question about code? http://eel.is/iso-c++/testcase/

            1 Reply Last reply
            2
            • SGaistS SGaist

              Hi,

              There might have been changed between PySide6 and 2 with regard to thread termination however and in any case, thread termination like that should be the last resort when there's no other solution.

              Since you thread contains an infinite loop, you should use QThread::isInterruptionRequested and QThread::requestInterruption to cleanly stop your thread.

              B Offline
              B Offline
              brianmeasley
              wrote on last edited by
              #12

              @SGaist @jeremy_k

              thank you for your reply,
              It's true that using QThread.terminate() to kill a thread is not a good idea.
              I would like to ask a related question. If a thread is executing a long-running task and the task puts the thread in a blocked state, what should I do if I want to terminate the blocked thread immediately?
              For example, in the ssh_connect code above, if the while loop in the run method is removed and a connection is made, a crash will still occur. If this is placed in an SSH terminal program/SFTP file manager, the user wants to stop logging in/refresh the directory immediately. How to implement the operation?

              JonBJ 1 Reply Last reply
              0
              • B Offline
                B Offline
                brianmeasley
                wrote on last edited by
                #13

                I found the solution! I checked the official binding source code of PySide, and in fact PySide2-5.15.2.1 and later versions fix this bug.

                1 Reply Last reply
                0
                • B brianmeasley has marked this topic as solved on
                • B brianmeasley

                  @SGaist @jeremy_k

                  thank you for your reply,
                  It's true that using QThread.terminate() to kill a thread is not a good idea.
                  I would like to ask a related question. If a thread is executing a long-running task and the task puts the thread in a blocked state, what should I do if I want to terminate the blocked thread immediately?
                  For example, in the ssh_connect code above, if the while loop in the run method is removed and a connection is made, a crash will still occur. If this is placed in an SSH terminal program/SFTP file manager, the user wants to stop logging in/refresh the directory immediately. How to implement the operation?

                  JonBJ Online
                  JonBJ Online
                  JonB
                  wrote on last edited by JonB
                  #14

                  @brianmeasley said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                  If a thread is executing a long-running task and the task puts the thread in a blocked state, what should I do if I want to terminate the blocked thread immediately?

                  You may have already found your solution. But just to pick up on this. If you expect to want the ability to interrupt/terminate a thread what you are supposed to do is have it run an event loop. Then you can either send it a Qt signal or PySide2.QtCore.QThread.requestInterruption() and isInterruptionRequested(). I think it's worth knowing about these, maybe for other cases if it does not fit yours.

                  If what it calls in some external blocking operation and you cannot be running an event (or other) loop checking for "interruption request" then I agree you are in trouble. And you may have to terminate the thread. But this may indeed do bad things to the state of your execution, system resource usage or whatever. But then you would equally be in a pickle for this whether you used a thread or not.

                  jeremy_kJ 1 Reply Last reply
                  1
                  • SGaistS Offline
                    SGaistS Offline
                    SGaist
                    Lifetime Qt Champion
                    wrote on last edited by
                    #15

                    The usual solution, when you have a long running operation is to check at regular points in your code for termination request. It's not always possible but it's a pretty standard solution. Then, if you really have to kill the thread, don't restart it, create a new one that will be clean.

                    Interested in AI ? www.idiap.ch
                    Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

                    1 Reply Last reply
                    1
                    • JonBJ JonB

                      @brianmeasley said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                      If a thread is executing a long-running task and the task puts the thread in a blocked state, what should I do if I want to terminate the blocked thread immediately?

                      You may have already found your solution. But just to pick up on this. If you expect to want the ability to interrupt/terminate a thread what you are supposed to do is have it run an event loop. Then you can either send it a Qt signal or PySide2.QtCore.QThread.requestInterruption() and isInterruptionRequested(). I think it's worth knowing about these, maybe for other cases if it does not fit yours.

                      If what it calls in some external blocking operation and you cannot be running an event (or other) loop checking for "interruption request" then I agree you are in trouble. And you may have to terminate the thread. But this may indeed do bad things to the state of your execution, system resource usage or whatever. But then you would equally be in a pickle for this whether you used a thread or not.

                      jeremy_kJ Offline
                      jeremy_kJ Offline
                      jeremy_k
                      wrote on last edited by
                      #16

                      @JonB said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                      If what it calls in some external blocking operation and you cannot be running an event (or other) loop checking for "interruption request" then I agree you are in trouble. And you may have to terminate the thread. But this may indeed do bad things to the state of your execution, system resource usage or whatever. But then you would equally be in a pickle for this whether you used a thread or not.

                      Make it an external process. If it must be unceremoniously terminated, leave no part of the process running in a possibly corrupted state.

                      Asking a question about code? http://eel.is/iso-c++/testcase/

                      JonBJ 1 Reply Last reply
                      0
                      • jeremy_kJ jeremy_k

                        @JonB said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                        If what it calls in some external blocking operation and you cannot be running an event (or other) loop checking for "interruption request" then I agree you are in trouble. And you may have to terminate the thread. But this may indeed do bad things to the state of your execution, system resource usage or whatever. But then you would equally be in a pickle for this whether you used a thread or not.

                        Make it an external process. If it must be unceremoniously terminated, leave no part of the process running in a possibly corrupted state.

                        JonBJ Online
                        JonBJ Online
                        JonB
                        wrote on last edited by JonB
                        #17

                        @jeremy_k said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                        Make it an external process.

                        If you can. You know there are plenty of circumstances where this may not be suitable/possible.

                        jeremy_kJ 1 Reply Last reply
                        0
                        • JonBJ JonB

                          @jeremy_k said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                          Make it an external process.

                          If you can. You know there are plenty of circumstances where this may not be suitable/possible.

                          jeremy_kJ Offline
                          jeremy_kJ Offline
                          jeremy_k
                          wrote on last edited by jeremy_k
                          #18

                          @JonB said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                          @jeremy_k said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                          Make it an external process.

                          If you can. You know there are plenty of circumstances where this may not be suitable/possible.

                          Use explicit communication rather than relying on pointers and a shared address space. If a thread is killed in the middle of modifying data in that address space, you can't count on that data having sane values. The same applies to modifying without explicit signaling/barriers. I am unaware of any systems that reorder communication within a single i/o channel. That makes earlier data potentially usable even with later data is absent.

                          Excluding resource limited environments where the extra communication exceeds the available time or memory, I don't know of situations where a second thread can do something that a second process can't. Different interfaces may be required.

                          This is a monolithic versus microkernel discussion, except in user space.

                          Asking a question about code? http://eel.is/iso-c++/testcase/

                          JonBJ 1 Reply Last reply
                          0
                          • jeremy_kJ jeremy_k

                            @JonB said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                            @jeremy_k said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                            Make it an external process.

                            If you can. You know there are plenty of circumstances where this may not be suitable/possible.

                            Use explicit communication rather than relying on pointers and a shared address space. If a thread is killed in the middle of modifying data in that address space, you can't count on that data having sane values. The same applies to modifying without explicit signaling/barriers. I am unaware of any systems that reorder communication within a single i/o channel. That makes earlier data potentially usable even with later data is absent.

                            Excluding resource limited environments where the extra communication exceeds the available time or memory, I don't know of situations where a second thread can do something that a second process can't. Different interfaces may be required.

                            This is a monolithic versus microkernel discussion, except in user space.

                            JonBJ Online
                            JonBJ Online
                            JonB
                            wrote on last edited by
                            #19

                            @jeremy_k said in Pyside2.QtCore.QThread.terminate() Cause python to crash:

                            I don't know of situations where a second thread can do something that a second process can't.

                            Our experiences differ them. But let's leave it at that, may have nothing to with OP's situation. I have never disagreed that terminating is bad, and that external process might be preferable. Let's see how OP gets on with that.

                            1 Reply Last reply
                            0

                            • Login

                            • Login or register to search.
                            • First post
                              Last post
                            0
                            • Categories
                            • Recent
                            • Tags
                            • Popular
                            • Users
                            • Groups
                            • Search
                            • Get Qt Extensions
                            • Unsolved