QVector has no assign method?

[jsulm]

@Publicnamer said in QVector has no assign method?:

Isn't there an automatically resized array?

Such a thing would be extremely dangerous as it would simply resize if the programmer uses an invalid index instead of crashing the application with "out of bounds" exception.
Why do you need such a thing actually?! What is the problem to properly resize the QVector?

[JonB]

@Publicnamer said in QVector has no assign method?:

Isn't there an automatically resized array?

As @jsulm says.
However if you really want this then (presumably, untested) you can derive from QVector and override the [] operator?

EDIT
I don't think you can override the [] operator after all?
In which case it may not be as "elegant" as you might wish, but you do realize that before going [index] you can insert

if (index >= qVector.size())
    qVector.resize(index);

Up to you whether you want to do this where you are using qVector[index] only as an l-value or also as an r-value (i.e. when writing to it versus reading from it, if I am using the wrong terminology).

[jsulm]

@JonB said in QVector has no assign method?:

I don't think you can override the [] operator after all?

Why not?

[Publicnamer]

@JonB said in QVector has no assign method?:

if (index >= qVector.size())
qVector.resize(index);

Yes that's what I'm doing now. It's a tiny inconvenience.

[Publicnamer]

@jsulm said in QVector has no assign method?:

Such a thing would be extremely dangerous

Not necessarily. It depends on the use case.

[Christian Ehrlicher]

@Publicnamer said in QVector has no assign method?:

Not necessarily. It depends on the use case.

Your example above will result in an oom exception after a few milliseconds. If you don't call this dangerous...

[JonB]

@jsulm said in QVector has no assign method?:

I don't think you can override the [] operator after all?

Because operator[] is listed among Public functions but does not say virtual?

[VRonin]

@JonB said in QVector has no assign method?:

Because operator[] is listed among Public functions but does not say virtual?

unlikely you need operator[] to be virtual. You normally don't use base classes interfaces for containers.

#include<QVector>
template <class T>
class ExpandingVector : public QVector<T>{
public:
    using QVector<T>::QVector;
    T& operator[](int index) {
        if (index >= QVector<T>::size())
            QVector<T>::resize(index+1);
        return QVector<T>::operator[](index);
    }
};

P.S.

There are many cases where

I still think there is no case where this is useful but you do you bro.

[JonB]

@VRonin
This is very useful, but I don't understand :)
If I use your template, but the base opertaor[] isn't virtual/overridable, what happens when some other code receiving my array as QVector<> parameter, not ExpandingVector<>, and then accesses it via []? They won't get my oevrride if it wasn't virtual?

[VRonin]

@JonB That's correct but 3rd party code receiving a QVector<> would need to stick to the QVector contract (i.e. index must be within bounds). ExpandingVector will behave exactly like QVector in that case.

[JonB]

@VRonin
Then I understand completely, thank you.

You just have your own definition of operator[]. You might as well have defined it as a foobar() method :)

[JKSH]

@Publicnamer said in QVector has no assign method?:

And yet a hash isn't good enough.

Why? Can you describe your use-case?

[JonB]

@JKSH I asked this too at the start, but no response....