get the numeric RGB color values ( QColor)

[Craiginator]

Using QColor selection, I would like to know how to get and store the individual R, G, B values as 0-255.
In my example below, I'm just focusing on trying to get one value to work so I understand the concept, but the output is not as I'd expect.

• When I pick pure red from the color selector, my debug code is showing the output of MyRed as: Color Choosen : "ÿ"

• What I want and thought would display based on the help file is: Color Choosen : "255"

• Then, what I ultimately need to get to is something like pure red yields MyRed = 255 , MyGreen = 0, MyBlue = 0

void MainWindow::on_pushButton_clicked()
{
  QString MyRed;

    QColor color = QColorDialog::getColor(Qt::yellow, this ).rgb();
    if( color.isValid() )
    {

      //qDebug() << "Color Choosen : " << color.name();
      MyRed = color.red();
      qDebug() << "Color Choosen : " << MyRed;

}
};

[Christian Ehrlicher]

@Craiginator said in get the numeric RGB color values ( QColor):

MyRed = color.red();

You're assigning an integer to a QString - what do you expect??
You're looking either for QString::number() or simply

qDebug() << "Color Choosen : " << color.red();

or even

qDebug() << "Color Choosen : " << color.name(QColor::HexArgb);

[Craiginator]

Holy Cow , that was silly. I waisted more time than I'd like to say and all over 1 mistake I kept overlooking.
Thanks!

[Kent-Dorfman]

@Christian-Ehrlicher said in get the numeric RGB color values ( QColor):

You're assigning an integer to a QString - what do you expect??
You're looking either for QString::number() or simply

and one of the huge dangers of overloaded constructors run amuck.