generalize a c++ method

ODБOï

@mrjj do you mean like this ? this looks good except i will have a huge switch

  enum class UpdateHandlers: qint32{
        NINDEX = 0, 
        SPEED = 1,  
        XXX = 2
    };

void MachineBackend::uaSub1(QScopedPointer<QOpcUaNode> &node, QString nodeId, UpdateHandlers theHandler){
    
    node.reset(m_client->node(nodeId));
    node->enableMonitoring(QOpcUa::NodeAttribute::Value, QOpcUaMonitoringParameters(200));
    QObject::connect(node.data(),&QOpcUaNode::attributeUpdated,[=](QOpcUa::NodeAttribute attr,const QVariant &value){
              
        switch (theHandler) {
        
        case UpdateHandlers::NINDEX :   nIndexUpdated(attr,value);break;
        case UpdateHandlers::SPEED  :   nSpeeedUpdated(attr,value);break;
        case UpdateHandlers::XXX    :   xxxUpdated(attr,value);break;
        default: break;            
        }              
    });  
    
    return;    
}

ODБOï

edit @mrjj sorry not for you

@jsulm
do you mean this ?

 enum  UpdateHandlers : qint32{
        NINDEX, 
        SPEED, 
        XXX
    };


void MachineBackend::uaSub1(QScopedPointer<QOpcUaNode> &node, QString nodeId, UpdateHandlers theHandler){
    
    node.reset(m_client->node(nodeId));
    node->enableMonitoring(QOpcUa::NodeAttribute::Value, QOpcUaMonitoringParameters(200));
    QObject::connect(node.data(),&QOpcUaNode::attributeUpdated,[=](QOpcUa::NodeAttribute attr,const QVariant &value){
       
        
        switch (theHandler) {
        
        case UpdateHandlers::NINDEX :   nIndexUpdated(attr,value);break;
        case UpdateHandlers::SPEED  :   nSpeeedUpdated(attr,value);break;
        case UpdateHandlers::XXX    :   xxxUpdated(attr,value);break;
        default: break;
            
        }
        
        
    });
    
    
    return;
    
}

jsulm

@LeLev See https://stackoverflow.com/questions/14315346/function-pointer-of-a-non-static-member-function-of-a-class
With non-static methods you need an instance of the class to call the method:

typedef void (T::*MethodPtr) ();
MethodPtr method = &T::MethodA;
T *obj = new T();
obj->*method();

ODБOï

@jsulm i think i can not use this last solution, because there is only one instance of this class. it is instantiated in the main.cpp and putted as contextProperty, it is never destroyed and has same life time as my application. I can not create another object of this class

J.Hilk

@LeLev said in generalize a c++ method:

@jsulm i think i can not use this last solution, because there is only one instance of this class. it is instantiated in the main.cpp and putted as contextProperty, it is never destroyed and has same life time as my application. I can not create another object of this class

ok, when this - in essence - is a singleton, why don't you make the member variable then also static?

ODБOï

because i'm JS guy ... i 'm learning Qt/cpp only for 2 years now.
let me try it

ODБOï

@J-Hilk said in generalize a c++ method:

why don't you make the member variable then also static?

i have one member variable per subscription,
each member variable has a Q_PROPERTY corresponding to it, so i can use the variable value from QML.

is it possible do define Q_PROPERTIES for a static member variable ?

Im trying but getting errors :
moc_machinebackend.cpp:-1: erreur : undefined reference to `MachineBackend::m_url'

 Q_PROPERTY(QString url READ url WRITE setUrl NOTIFY urlChanged)

public:
 QString url()const{
       return MachineBackend::m_url; 
    }
    void setUrl(const QString nUrl){
        if(MachineBackend::m_url==nUrl)return;
        MachineBackend::m_url = nUrl;
        emit urlChanged(nUrl);
    }

private : 
static QString m_url;

signals:
void urlChanged(QString url);

jsulm

@LeLev said in generalize a c++ method:

i think i can not use this last solution

Sure you can: you pass the pointer to second method when you call the first method, right? And since both methods are not static you call the first method already on an instance (which is "this" inside the method):

this->*method(); // method is the pointer to the other method

ODБOï

@jsulm said in generalize a c++ method:

: you pass the pointer to second method when you call the first method, right?

Yes, but it only works if the
2nd method is static !

//first 
void uaSub(QScopedPointer<QOpcUaNode> &node, QString nodeId , void (*theUpdateHandler)(QOpcUa::NodeAttribute attr,const QVariant &value)){...}
// 2nd
static void nIndexUpdated(QOpcUa::NodeAttribute attr, const QVariant &value){...}


uaSub(nIndexNode,"ns=4;s=MAIN.nIndex",*nIndexUpdated){...}

//Here **nIndexUpdated** must be static !  no ?

if it is not static i get :
reference to non-static member function must be called error

jsulm

@LeLev Please take a closer look at the snippet I provided before:

typedef void (T::*MethodPtr) ();
MethodPtr method = &T::MethodA;
T *obj = new T();
obj->*method();

Your syntax is not even correct as you have to use & to get a pointer not *
So in your case something like

class A
{
    typedef void (A::*MethodPtr) ();
    void nIndexUpdated() {}
    void uaSub(..., MethodPtr ptr) {
        this->*ptr();
    }

    // Somewhere inside class A you call uaSub
    uaSub(/*params*/, &A::nIndexUpdated);
}

ODБOï

@jsulm
thank you so much for the help you provide.
Unfortunately i'm so bad, i can't make this work

class MachineBackend : public QObject
{
    typedef void (MachineBackend::*MethodPtr) ();
    Q_OBJECT

void nIndexUpdated(QOpcUa::NodeAttribute attr, const QVariant &value){...}

void uaSub2(QScopedPointer<QOpcUaNode>&node, QString nodeId, MethodPtr updateHandlerPtr){
       
       this->*updateHandlerPtr(); // < error here 

    }
};

called object type 'MachineBackend ::MethodPtr' (aka 'void (MachineBackend ::*)()' ) is not a function or function pointer

jsulm

@LeLev Try

this->updateHandlerPtr();

ODБOï

@jsulm said in generalize a c++ method:

this->updateHandlerPtr();

yes i did also, in that case error is :

no member named 'updateHandlerPtr' in 'MachineBackend '
which is true

jsulm

@LeLev This should compile:

(this->*updateHandlerPtr)();

Method pointers are a mess :-)

ODБOï

yes now it doas. awesome ! thank you so much!

class MachineBackend : public QObject
{
    typedef void (MachineBackend::*MethodPtr) ();
    Q_OBJECT

void nIndexUpdated(QOpcUa::NodeAttribute attr, const QVariant &value){...}

void uaSub2(QScopedPointer<QOpcUaNode>&node, QString nodeId, MethodPtr updateHandlerPtr){
       
       (this->*updateHandlerPtr)();

    }
};

there is still an issue in the usSub() call

//  Somewhere inside class
  uaSub2(nIndexNode,"ns=4;s=MAIN.nIndex", MachineBackend::nIndexUpdated);  // << error
//

error : reference to non-static member function must be called

im trying every possible syntax right now ...

jsulm

@LeLev said in generalize a c++ method:

uaSub2(nIndexNode,"ns=4;s=MAIN.nIndex", MachineBackend::nIndexUpdated);

uaSub2(nIndexNode,"ns=4;s=MAIN.nIndex", &MachineBackend::nIndexUpdated);

jsulm

@LeLev This small example works for me:

#include <iostream>

class A
{
public:
    typedef void (A::*MethodPtr) ();
    void someMethod() { std::cout << "Hallo!" << std::endl; }
    void uaSub2(MethodPtr updateHandlerPtr){
       (this->* updateHandlerPtr)();
    }
};

int main()
{
    A a;
    a.uaSub2(&A::someMethod); 
    return 0;
}

ODБOï

@jsulm yes sorry that is the first one i have tryed:

uaSub2(nIndexNode,"ns=4;s=MAIN.nIndex", &MachineBackend::nIndexUpdated);

// err :  cannot initialize a parameter of type 'Machinebackend::MethorPtr' (aka 'void (MAchinebackend::*)()') with an rvalue of type 'void (MAchineBAckend::*)(QOpcUa::NodeAttribute, const QVariant &)' : different number of parameters (0 vs 2)

error : no matching function for call to 'MachineBackend::uaSub2(QScopedPointer<QOpcUaNode>&, const char [19], <unresolved overloaded function type>)'
         uaSub2(nIndexNode,"ns=4;s=MAIN.nIndex",MachineBackend::nIndexUpdated);
                                                                             ^

jsulm

This post is deleted!

jsulm

@LeLev said in generalize a c++ method:

nIndexUpdated

This one has parameters, you need to adapt your typedef for the pointer accordingly.
This is what the error tells you.