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inherite from QThread, but donnot overrider virtual void run(), is this OK?

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  • O opengpu
    17 Jun 2019, 08:56

    is the above code OK?
    or i have to maintain a vector/list of myInfo, and append into it @slot. while loop this vector/list @run()?

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    kshegunov
    Moderators
    wrote on 17 Jun 2019, 09:05 last edited by
    #4

    @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

    is the above code OK?

    Not if you intend slot_SendEmail to be called in the thread you spawned, no. QThread is living in the main thread (as it should be). Use the worker object approach which @sierdzio alluded to.

    Read and abide by the Qt Code of Conduct

    1 Reply Last reply
    4
    • S sierdzio
      17 Jun 2019, 08:59

      A more classic approach would be to use worker object here. But yes, what you wrote should work fine as long as you don't call slot_SendEmail() directly (to make sure your compiler will check this - move it to private part of your header).

      To be 100% sure you can print thread ID in main.cpp and in your slot - if they are different then the method is invoked in the thread.

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      opengpu
      wrote on 17 Jun 2019, 09:16 last edited by
      #5

      @sierdzio said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

      use worker object here

      how to use worker object here? is there any doc or demo?

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        opengpu
        wrote on 17 Jun 2019, 09:18 last edited by
        #6

        the slot_SendEmail is slow, and the emit signal_SendEmail is very very frequently.
        so is it OK when the previous signal's slot_SendEmail is still not finished & the next (maybe more than one)signal_SendEmail is already emitted.

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        • O opengpu
          17 Jun 2019, 08:50

          inherite from QThread, but donnot overrider virtual void run(), is this OK?

          class MyThread : public QThread
          {
          public:
              MyThread(QObject* parent) : QThread(parent) {}
              ~MyThread() { exit(); }
          protected:
              //virtual void run();//use the dafault QThread::run().
          protected slots:
              void slot_SendEmail(const MyInfo& info) {......;}
          }
          
          void main()
          {
              MyThread t;
              connect(...,...,...,slot_SendEmail);
               t.start();
              //and then emit the signal_SendEmail(const MyInfo& /*info*/) @MainThread in some class::function frequently
          }
          
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          KroMignon
          wrote on 17 Jun 2019, 09:21 last edited by
          #7

          @opengpu I don't think this is OK. There is a common mistake with QThread usage.
          QThread is a Qt object which will control a thread, but QThread instance leaves in the thread in which the instance has been created, not in the created thread.
          So the slots/signals of the MyThread class will be launched in the thread used to create the MyThread instance.

          A good practice for multi-threading with Qt, is to create a worker class and to move the instance to the thread, not to sub-class QThread.

          Take a look at following links for more details:

          • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-1/
          • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-2/
          • https://blog.qt.io/blog/2010/06/17/youre-doing-it-wrong/
          • https://mayaposch.wordpress.com/2011/11/01/how-to-really-truly-use-qthreads-the-full-explanation/

          It is an old maxim of mine that when you have excluded the impossible, whatever remains, however improbable, must be the truth. (Sherlock Holmes)

          O S 2 Replies Last reply 17 Jun 2019, 09:30
          1
          • K KroMignon
            17 Jun 2019, 09:21

            @opengpu I don't think this is OK. There is a common mistake with QThread usage.
            QThread is a Qt object which will control a thread, but QThread instance leaves in the thread in which the instance has been created, not in the created thread.
            So the slots/signals of the MyThread class will be launched in the thread used to create the MyThread instance.

            A good practice for multi-threading with Qt, is to create a worker class and to move the instance to the thread, not to sub-class QThread.

            Take a look at following links for more details:

            • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-1/
            • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-2/
            • https://blog.qt.io/blog/2010/06/17/youre-doing-it-wrong/
            • https://mayaposch.wordpress.com/2011/11/01/how-to-really-truly-use-qthreads-the-full-explanation/
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            opengpu
            wrote on 17 Jun 2019, 09:30 last edited by opengpu
            #8

            @KroMignon thank you , i think you are right. the signal and slot will be both at MainThread...before this i normally overide the virutal run(), and mainly do things @run().
            at this time, i just need to SendMail(const MyInfo& info), so i tried to make it simple, without loop @run() with a list.

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            • K KroMignon
              17 Jun 2019, 09:21

              @opengpu I don't think this is OK. There is a common mistake with QThread usage.
              QThread is a Qt object which will control a thread, but QThread instance leaves in the thread in which the instance has been created, not in the created thread.
              So the slots/signals of the MyThread class will be launched in the thread used to create the MyThread instance.

              A good practice for multi-threading with Qt, is to create a worker class and to move the instance to the thread, not to sub-class QThread.

              Take a look at following links for more details:

              • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-1/
              • http://blog.debao.me/2013/08/how-to-use-qthread-in-the-right-way-part-2/
              • https://blog.qt.io/blog/2010/06/17/youre-doing-it-wrong/
              • https://mayaposch.wordpress.com/2011/11/01/how-to-really-truly-use-qthreads-the-full-explanation/
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              sierdzio
              Moderators
              wrote on 17 Jun 2019, 09:37 last edited by
              #9

              @KroMignon said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

              So the slots/signals of the MyThread class will be launched in the thread used to create the MyThread instance.

              Yep, I've just tested. @opengpu so you have to use worker object or implement run(). Both approaches are described in great detail in QThread documentation.

              (Z(:^

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                opengpu
                wrote on 17 Jun 2019, 09:56 last edited by opengpu
                #10
                class Worker : public QObject
                {
                    Q_OBJECT
                
                public slots:
                    void doWork(const QString &parameter) {
                        QString result;
                        /* ... here is the expensive or blocking operation ... */
                        emit resultReady(result);
                    }
                
                signals:
                    void resultReady(const QString &result);
                };
                
                class Controller : public QObject
                {
                    Q_OBJECT
                    QThread workerThread;
                public:
                    Controller() {
                        Worker *worker = new Worker;
                        worker->moveToThread(&workerThread);
                        connect(&workerThread, &QThread::finished, worker, &QObject::deleteLater);
                        connect(this, &Controller::operate, worker, &Worker::doWork);
                        connect(worker, &Worker::resultReady, this, &Controller::handleResults);
                        workerThread.start();
                    }
                    ~Controller() {
                        workerThread.quit();
                        workerThread.wait();
                    }
                public slots:
                    void handleResults(const QString &);
                signals:
                    void operate(const QString &);
                };
                

                thanks, and i will use this.

                ///////////////////////////////////////////////////////////////////////////////////////////////
                is this OK?
                the 'doWork' is slow, and the emit 'operate' is very very frequently.
                so is it OK when the previous signal's 'doWork' is still not finished & the next (maybe more than one)'operate' is already emitted.

                K 1 Reply Last reply 17 Jun 2019, 12:32
                0
                • O opengpu
                  17 Jun 2019, 09:56
                  class Worker : public QObject
                  {
                      Q_OBJECT
                  
                  public slots:
                      void doWork(const QString &parameter) {
                          QString result;
                          /* ... here is the expensive or blocking operation ... */
                          emit resultReady(result);
                      }
                  
                  signals:
                      void resultReady(const QString &result);
                  };
                  
                  class Controller : public QObject
                  {
                      Q_OBJECT
                      QThread workerThread;
                  public:
                      Controller() {
                          Worker *worker = new Worker;
                          worker->moveToThread(&workerThread);
                          connect(&workerThread, &QThread::finished, worker, &QObject::deleteLater);
                          connect(this, &Controller::operate, worker, &Worker::doWork);
                          connect(worker, &Worker::resultReady, this, &Controller::handleResults);
                          workerThread.start();
                      }
                      ~Controller() {
                          workerThread.quit();
                          workerThread.wait();
                      }
                  public slots:
                      void handleResults(const QString &);
                  signals:
                      void operate(const QString &);
                  };
                  

                  thanks, and i will use this.

                  ///////////////////////////////////////////////////////////////////////////////////////////////
                  is this OK?
                  the 'doWork' is slow, and the emit 'operate' is very very frequently.
                  so is it OK when the previous signal's 'doWork' is still not finished & the next (maybe more than one)'operate' is already emitted.

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                  KroMignon
                  wrote on 17 Jun 2019, 12:32 last edited by KroMignon
                  #11

                  @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                  so is it OK when the previous signal's 'doWork' is still not finished & the next (maybe more than one)'operate' is already emitted.

                  The worker QThread implements a QEventQueue, when a new signal emitted from Controller, it will be stored in message queue. And when slot has been processed on Worker, next message will be extract from queue. And so on.

                  More details can be found here: https://www.toptal.com/qt/qt-multithreading-c-plus-plus

                  Messages will be processed in the order of reception in WorkerThread.

                  I would to initialization of Thread and Worker like this:

                  Worker *worker = new Worker; // no need to hold pointer to worker 
                  QThread *workerThread = new QThread; // no need to hold pointer to worker thread
                  
                  connect(this, &Controller::operate, worker, Worker::doWork);
                  connect(worker, &Worker::resultReady, this, &Controller::handleResults);
                  
                  // delete worker on controller end
                  connect(this, &QObject::destroyed, worker, Worker::deleteLater, Qt::DirectConnection);
                  
                  // stop and delete worker thread on worker end
                  connect(worker, &QObject::destroyed, workerThread, [](QObject *){
                      quit();
                      wait();
                      deleteLater();
                  }, Qt::DirectConnection);
                  
                  worker->moveToThread(workerThread);
                  workerThread.start();
                  

                  It is an old maxim of mine that when you have excluded the impossible, whatever remains, however improbable, must be the truth. (Sherlock Holmes)

                  K 1 Reply Last reply 17 Jun 2019, 19:27
                  1
                  • K KroMignon
                    17 Jun 2019, 12:32

                    @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                    so is it OK when the previous signal's 'doWork' is still not finished & the next (maybe more than one)'operate' is already emitted.

                    The worker QThread implements a QEventQueue, when a new signal emitted from Controller, it will be stored in message queue. And when slot has been processed on Worker, next message will be extract from queue. And so on.

                    More details can be found here: https://www.toptal.com/qt/qt-multithreading-c-plus-plus

                    Messages will be processed in the order of reception in WorkerThread.

                    I would to initialization of Thread and Worker like this:

                    Worker *worker = new Worker; // no need to hold pointer to worker 
                    QThread *workerThread = new QThread; // no need to hold pointer to worker thread
                    
                    connect(this, &Controller::operate, worker, Worker::doWork);
                    connect(worker, &Worker::resultReady, this, &Controller::handleResults);
                    
                    // delete worker on controller end
                    connect(this, &QObject::destroyed, worker, Worker::deleteLater, Qt::DirectConnection);
                    
                    // stop and delete worker thread on worker end
                    connect(worker, &QObject::destroyed, workerThread, [](QObject *){
                        quit();
                        wait();
                        deleteLater();
                    }, Qt::DirectConnection);
                    
                    worker->moveToThread(workerThread);
                    workerThread.start();
                    
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                    kshegunov
                    Moderators
                    wrote on 17 Jun 2019, 19:27 last edited by
                    #12

                    @KroMignon said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                    connect(this, &QObject::destroyed, worker, Worker::deleteLater, Qt::DirectConnection);
                    

                    This is a race condition - deleteLater is a slot and it's not thread-safe. Don't force the connection type.

                    Read and abide by the Qt Code of Conduct

                    K 1 Reply Last reply 18 Jun 2019, 07:04
                    4
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                      opengpu
                      wrote on 17 Jun 2019, 20:26 last edited by opengpu
                      #13

                      i want to set a min time interval inside which the emit operate or the slot doWork should be INVALID and do nothing.
                      before when overrider the virtual run(), that's easy to do.

                      how about this situation while using this worker-method?

                      eg. if doWork is implemented and until 1 min passed, the signal or slot should not emit or implemented in this 1 min. and the signal/slot doesnot be renmembered, just ignore them.

                      K 1 Reply Last reply 17 Jun 2019, 20:34
                      0
                      • O opengpu
                        17 Jun 2019, 20:26

                        i want to set a min time interval inside which the emit operate or the slot doWork should be INVALID and do nothing.
                        before when overrider the virtual run(), that's easy to do.

                        how about this situation while using this worker-method?

                        eg. if doWork is implemented and until 1 min passed, the signal or slot should not emit or implemented in this 1 min. and the signal/slot doesnot be renmembered, just ignore them.

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                        kshegunov
                        Moderators
                        wrote on 17 Jun 2019, 20:34 last edited by
                        #14

                        Emit a deadline (QDeadlineTimer) along with the input data. In the slot check if the deadline has expired, and if so just return immediately.

                        Read and abide by the Qt Code of Conduct

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                        0
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                          opengpu
                          wrote on 18 Jun 2019, 03:44 last edited by opengpu
                          #15
                          QElapsedTimer m_ElapsedTimer;
                          
                          if ( !m_ElapsedTimer.isValid() ||  m_ElapsedTimer.hasExpired(timeout))
                          {
                              emit signalSendEmail();
                              m_ElapsedTimer.restart();
                          }
                          

                          i want to write like this, this will not restrict the 1st time emit, and since the 1st emit, the next emit is only allowed outof timeout milliseconds.
                          However, i want the exe runs very very long time. the qinit64 seems still not that long enough for the longest interval in theory(qint64 is only about 214783 seconds). What will happen if the real time interval is longer than this?
                          And what is the best method to get the longest time interval supportted in code?

                          J K 2 Replies Last reply 18 Jun 2019, 04:24
                          0
                          • O opengpu
                            18 Jun 2019, 03:44
                            QElapsedTimer m_ElapsedTimer;
                            
                            if ( !m_ElapsedTimer.isValid() ||  m_ElapsedTimer.hasExpired(timeout))
                            {
                                emit signalSendEmail();
                                m_ElapsedTimer.restart();
                            }
                            

                            i want to write like this, this will not restrict the 1st time emit, and since the 1st emit, the next emit is only allowed outof timeout milliseconds.
                            However, i want the exe runs very very long time. the qinit64 seems still not that long enough for the longest interval in theory(qint64 is only about 214783 seconds). What will happen if the real time interval is longer than this?
                            And what is the best method to get the longest time interval supportted in code?

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                            jsulm
                            Lifetime Qt Champion
                            wrote on 18 Jun 2019, 04:24 last edited by jsulm
                            #16

                            @opengpu See my answer in your other thread (https://forum.qt.io/topic/104026/about-the-longest-elapsed-time-in-qt). I really have no idea why you think it is 214783 seconds only when using qint64...

                            https://forum.qt.io/topic/113070/qt-code-of-conduct

                            O 1 Reply Last reply 18 Jun 2019, 06:29
                            0
                            • J jsulm
                              18 Jun 2019, 04:24

                              @opengpu See my answer in your other thread (https://forum.qt.io/topic/104026/about-the-longest-elapsed-time-in-qt). I really have no idea why you think it is 214783 seconds only when using qint64...

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                              opengpu
                              wrote on 18 Jun 2019, 06:29 last edited by
                              #17

                              @jsulm thank you. i got it from INT_MAX, which is int32

                              J 1 Reply Last reply 18 Jun 2019, 06:34
                              0
                              • O opengpu
                                18 Jun 2019, 06:29

                                @jsulm thank you. i got it from INT_MAX, which is int32

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                                jsulm
                                Lifetime Qt Champion
                                wrote on 18 Jun 2019, 06:34 last edited by jsulm
                                #18

                                @opengpu With int32 you have more than 2 million seconds, not 214783

                                https://forum.qt.io/topic/113070/qt-code-of-conduct

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                                  opengpu
                                  wrote on 18 Jun 2019, 06:44 last edited by
                                  #19

                                  @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                  workerThread

                                  workerThread donot need sleep?

                                  J 1 Reply Last reply 18 Jun 2019, 06:48
                                  0
                                  • O opengpu
                                    18 Jun 2019, 06:44

                                    @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                    workerThread

                                    workerThread donot need sleep?

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                                    J Offline
                                    jsulm
                                    Lifetime Qt Champion
                                    wrote on 18 Jun 2019, 06:48 last edited by
                                    #20

                                    @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                    workerThread donot need sleep?

                                    No, they are not humans :-)
                                    Why are you asking? A thread can sleep or be busy.

                                    https://forum.qt.io/topic/113070/qt-code-of-conduct

                                    O 1 Reply Last reply 18 Jun 2019, 07:02
                                    1
                                    • J jsulm
                                      18 Jun 2019, 06:48

                                      @opengpu said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                      workerThread donot need sleep?

                                      No, they are not humans :-)
                                      Why are you asking? A thread can sleep or be busy.

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                                      opengpu
                                      wrote on 18 Jun 2019, 07:02 last edited by
                                      #21

                                      @jsulm ok, so it will automatically sleep when no signal or event, right?
                                      because i used to overider the virtual run()
                                      thanks

                                      J 1 Reply Last reply 18 Jun 2019, 07:05
                                      0
                                      • K kshegunov
                                        17 Jun 2019, 19:27

                                        @KroMignon said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                        connect(this, &QObject::destroyed, worker, Worker::deleteLater, Qt::DirectConnection);
                                        

                                        This is a race condition - deleteLater is a slot and it's not thread-safe. Don't force the connection type.

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                                        KroMignon
                                        wrote on 18 Jun 2019, 07:04 last edited by KroMignon
                                        #22

                                        @kshegunov said in inherite from QThread, but donnot overrider virtual void run(), is this OK?:

                                        This is a race condition - deleteLater is a slot and it's not thread-safe. Don't force the connection type.

                                        Where did you found this information.... I mean not thread safe?
                                        Because on Qt Mailing list, Thiago Macieira (which is deep involved in Qt devlopement) has written:

                                        It's thread-safe with almost any operation, except one: the actual object's
                                        deletion, of course.

                                        But we haven't documented it as such. It just happens to be due to the
                                        implementation.

                                        ==> cf. https://lists.qt-project.org/pipermail/interest/2015-October/019197.html

                                        It is an old maxim of mine that when you have excluded the impossible, whatever remains, however improbable, must be the truth. (Sherlock Holmes)

                                        K 1 Reply Last reply 18 Jun 2019, 07:33
                                        0
                                        • O opengpu
                                          18 Jun 2019, 07:02

                                          @jsulm ok, so it will automatically sleep when no signal or event, right?
                                          because i used to overider the virtual run()
                                          thanks

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                                          jsulm
                                          Lifetime Qt Champion
                                          wrote on 18 Jun 2019, 07:05 last edited by
                                          #23

                                          @opengpu If you call exec() in your run() method then your thread will have an event loop and sleep if there is nothing to do. Else it will finish as soon as run() finishes (https://doc.qt.io/qt-5/qthread.html#run).

                                          https://forum.qt.io/topic/113070/qt-code-of-conduct

                                          O 1 Reply Last reply 18 Jun 2019, 07:09
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