I want set of totally distinct shades of QCOlor around 64

kshegunov

Convert the rectangular RGB space into a spherical one and introduce a metric (if you want), then pick the colors from splitting the unit sphere into a number of parallels and meridians. At least that's what I'd do. The math isn't that complicated you can pull the formulas from wikipedia to try and wrap something up.

Qt Enthusiast

@kshegunov

Is it possible to provide the code

Qt Enthusiast

some pseudo code of rectangles will be done

kshegunov

@Qt-Enthusiast said in I want set of totally distinct shades of QCOlor around 64:

@kshegunov

Is it possible to provide the code

Not really, I haven't any code, as I haven't done anything of that sort. It's only an idea you could explore.

mrjj

Qt Enthusiast

what algortimhs generates this

mrjj

@Qt-Enthusiast
I think its a dictionary.
Make a small test program. there is also a table of hex values to use. ~~sample the color from the bitmap. (same offset so not so complex)~~
Then alter properties (QColor) to fine tune.
http://godsnotwheregodsnot.blogspot.dk/2013/11/kmeans-color-quantization-seeding.html
Kmeans++ Color Quantization seeding it seems :)
From
https://graphicdesign.stackexchange.com/questions/3682/where-can-i-find-a-large-palette-set-of-contrasting-colors-for-coloring-many-d

mrjj

Hi
Using his table, and some ligher() and darker() calls then they seems pretty distinct ;)

alt text

#include "mainwindow.h"
#include "ui_mainwindow.h"
#include <QPainter>

MainWindow::MainWindow(QWidget* parent) :
  QMainWindow(parent),
  ui(new Ui::MainWindow) {
  ui->setupUi(this);
}

MainWindow::~MainWindow() {
  delete ui;
}

const char* indexcolors[] = {
  "#000000", "#FFFF00", "#1CE6FF", "#FF34FF", "#FF4A46", "#008941", "#006FA6", "#A30059",
  "#FFDBE5", "#7A4900", "#0000A6", "#63FFAC", "#B79762", "#004D43", "#8FB0FF", "#997D87",
  "#5A0007", "#809693", "#FEFFE6", "#1B4400", "#4FC601", "#3B5DFF", "#4A3B53", "#FF2F80",
  "#61615A", "#BA0900", "#6B7900", "#00C2A0", "#FFAA92", "#FF90C9", "#B903AA", "#D16100",
  "#DDEFFF", "#000035", "#7B4F4B", "#A1C299", "#300018", "#0AA6D8", "#013349", "#00846F",
  "#372101", "#FFB500", "#C2FFED", "#A079BF", "#CC0744", "#C0B9B2", "#C2FF99", "#001E09",
  "#00489C", "#6F0062", "#0CBD66", "#EEC3FF", "#456D75", "#B77B68", "#7A87A1", "#788D66",
  "#885578", "#FAD09F", "#FF8A9A", "#D157A0", "#BEC459", "#456648", "#0086ED", "#886F4C",

  "#34362D", "#B4A8BD", "#00A6AA", "#452C2C", "#636375", "#A3C8C9", "#FF913F", "#938A81",
  "#575329", "#00FECF", "#B05B6F", "#8CD0FF", "#3B9700", "#04F757", "#C8A1A1", "#1E6E00",
  "#7900D7", "#A77500", "#6367A9", "#A05837", "#6B002C", "#772600", "#D790FF", "#9B9700",
  "#549E79", "#FFF69F", "#201625", "#72418F", "#BC23FF", "#99ADC0", "#3A2465", "#922329",
  "#5B4534", "#FDE8DC", "#404E55", "#0089A3", "#CB7E98", "#A4E804", "#324E72", "#6A3A4C",
  "#83AB58", "#001C1E", "#D1F7CE", "#004B28", "#C8D0F6", "#A3A489", "#806C66", "#222800",
  "#BF5650", "#E83000", "#66796D", "#DA007C", "#FF1A59", "#8ADBB4", "#1E0200", "#5B4E51",
  "#C895C5", "#320033", "#FF6832", "#66E1D3", "#CFCDAC", "#D0AC94", "#7ED379", "#012C58",

  "#7A7BFF", "#D68E01", "#353339", "#78AFA1", "#FEB2C6", "#75797C", "#837393", "#943A4D",
  "#B5F4FF", "#D2DCD5", "#9556BD", "#6A714A", "#001325", "#02525F", "#0AA3F7", "#E98176",
  "#DBD5DD", "#5EBCD1", "#3D4F44", "#7E6405", "#02684E", "#962B75", "#8D8546", "#9695C5",
  "#E773CE", "#D86A78", "#3E89BE", "#CA834E", "#518A87", "#5B113C", "#55813B", "#E704C4",
  "#00005F", "#A97399", "#4B8160", "#59738A", "#FF5DA7", "#F7C9BF", "#643127", "#513A01",
  "#6B94AA", "#51A058", "#A45B02", "#1D1702", "#E20027", "#E7AB63", "#4C6001", "#9C6966",
  "#64547B", "#97979E", "#006A66", "#391406", "#F4D749", "#0045D2", "#006C31", "#DDB6D0",
  "#7C6571", "#9FB2A4", "#00D891", "#15A08A", "#BC65E9", "#FFFFFE", "#C6DC99", "#203B3C",

  "#671190", "#6B3A64", "#F5E1FF", "#FFA0F2", "#CCAA35", "#374527", "#8BB400", "#797868",
  "#C6005A", "#3B000A", "#C86240", "#29607C", "#402334", "#7D5A44", "#CCB87C", "#B88183",
  "#AA5199", "#B5D6C3", "#A38469", "#9F94F0", "#A74571", "#B894A6", "#71BB8C", "#00B433",
  "#789EC9", "#6D80BA", "#953F00", "#5EFF03", "#E4FFFC", "#1BE177", "#BCB1E5", "#76912F",
  "#003109", "#0060CD", "#D20096", "#895563", "#29201D", "#5B3213", "#A76F42", "#89412E",
  "#1A3A2A", "#494B5A", "#A88C85", "#F4ABAA", "#A3F3AB", "#00C6C8", "#EA8B66", "#958A9F",
  "#BDC9D2", "#9FA064", "#BE4700", "#658188", "#83A485", "#453C23", "#47675D", "#3A3F00",
  "#061203", "#DFFB71", "#868E7E", "#98D058", "#6C8F7D", "#D7BFC2", "#3C3E6E", "#D83D66",

  "#2F5D9B", "#6C5E46", "#D25B88", "#5B656C", "#00B57F", "#545C46", "#866097", "#365D25",
  "#252F99", "#00CCFF", "#674E60", "#FC009C", "#92896B"
};


void MainWindow::on_pbGo_released() {
  const int tilesize = 32;
  const int mapsize = tilesize * 25 ;
  QPixmap pix(QSize(mapsize, mapsize));
  QPainter Painter;

  int maxCol = sizeof(indexcolors) / sizeof(indexcolors[0]);
  int cCol = 0;
  Painter.begin(&pix);

  Painter.setPen(QPen(QBrush(Qt::black), 1, Qt::SolidLine));
  int maxX = mapsize / tilesize;
  int dark = 0;

  for (int y = 0; y < maxX; ++y) {
    for (int x = 0; x < maxX; ++x) {
      QColor col(indexcolors[cCol]);
      if (cCol < maxCol) cCol++;
      else {
        cCol = 0;
        dark++;
      }

      if(dark == 1)
        col = col.darker();
      if(dark == 2)
        col = col.lighter();

      Painter.setBrush(QBrush(col) );
      Painter.drawRect((x * tilesize), (y * tilesize), tilesize, tilesize);
    }
  }   
  Painter.end();
 ui->labPic->setPixmap(pix);
}

Qt Enthusiast

Can we generate the table with algorithm ?

mrjj

@Qt-Enthusiast

Hi.
I thinks it s made using color distance algorithm already.
If you mean algorithm to generate all the colors out of nothing, then no.

Qt Enthusiast

Algorithm means code

mrjj

@Qt-Enthusiast

the colors are already code. ?

Qt Enthusiast

Means a pseudo code that generates this table

mrjj

@Qt-Enthusiast
Nope. Not that i have seen.