Template: Force const parameter

[kshegunov]

I haven't tried it, but:

template<class T>
QList<const T *> libraryItems() const
{
    // ...
    QList<const T *> list;
    // ...
}

?

[Joel Bodenmann]

The problem with that is that then the user/caller of that method has to write code like this:

QList<const MyLibraryItem*> myLibraryItems = mimeData->libraryItems<MyLibraryItem*>();

In my opinion that is just a no-go. You'd expect the two template parameters to be the same in that assignment.

[kshegunov]

@Joel-Bodenmann
Actually:

QList<const MyLibraryItem *> myLibraryItems = mimeData->libraryItems<MyLibraryItem>();

But yes, they differ. Whether or not it's acceptable it's up to you, I know of no other way.

PS.
I think a fat notice in the docs should be just enough. This isn't c++11 so what's on the left can be different from what's on the right (i.e. there's no auto confusing code). It's still valid to write:

QWidget * button = new QToolButton();

[Chris Kawa]

Can I force the caller of that method to only use template types/parameters (the T thing) that are const pointers?

I'll just assume you really meant pointers to const, because const pointer would be LibraryItem* const, which is entirely different beast.

This is one of those cases where templates come really handy. Here's a stripped down implementation:

class LibraryMimeData
{
private:
    QList<const LibraryItem*> _libraryItems;

    // this general type will get rid of non-pointer and pointer to non-const types
    template<typename T, bool is_pointer_to_const> struct Foo {
        static inline QList<T> convert(const QList<const LibraryItem*>& items) = delete;
    };

    //the specialized type will only accept pointer to const types
    template<typename T> struct Foo<T, true> {
        static inline QList<T> convert(const QList<const LibraryItem*>& items)
        {
            return /* DO THE CONVERSION */;
        }
    };

public:
    //and here's a public interface
    template<typename T> QList<T> libraryItems() const {
        return Foo<T, std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value>::convert(_libraryItems);
    }
};

This way it will work for pointer to const types and will give a lovely error about using deleted function for all others.

[kshegunov]

Ahahah, I needed a couple of reads to get it. It's quite nifty, albeit pretty verbose.

[Chris Kawa]

@kshegunov Yeah, templates usually do that when it's not you who wrote them ;) I usually steer away from them if I can but when you need to deal with type system and avoid runtime overhead they are a very flexible tool.
The verbose part is an implementation detail. Commented well and renamed to something better than Foo can live happily in a codebase. The user facing function has a nice clean signature.

[kshegunov]

@Chris-Kawa said in Template: Force const parameter:

I usually steer away from them

Me too, which you can deduce from my simplistic answer :P
They're just marginally better than the preprocessor ... code writing code always perplexes me, I must admit ...

PS.
I must also give you credit for the partial specialization trick ... never would've come up with it myself.

[Chris Kawa]

They're just marginally better than the preprocessor

Awww, that's hurtful to the templates :) Preprocessor is just glorified find/replace machinery. Templates are a full blown, type safe, statically checked sub-language. Combined with constexpr they really have a Death-Star-like power (with similar caveats ;) )
I remember when I wrote template based compile time quick sort back in the days. Sure it resulted in a 500Mb executable and crashed the compiler for input arrays larger then a dozen elements but it was constant O(1) time for any input :P
Sorry for offtopic. Nostalgia took me over ;)

[Joel Bodenmann]

@Chris-Kawa said in Template: Force const parameter:

I'll just assume you really meant pointers to const, because const pointer would be LibraryItem* const, which is entirely different beast.

Your assumption is correct. Sorry for using the wrong terminology. I'll blame not-getting-enough-sleep for it :p

@Chris-Kawa said in Template: Force const parameter:

Here's a stripped down implementation:

Oh boy... This is going to take a while (and lots of reading) for me to understand it. But I appreciate your efforts. Also, experience tells me that all code examples you write/post on this forum always just work, so huge Thank you! although I don't understand it yet :p

@Chris-Kawa said in Template: Force const parameter:

I remember when I wrote template based compile time quick sort back in the days. Sure it resulted in a 500Mb executable and crashed the compiler for input arrays larger then a dozen elements but it was constant O(1) time for any input :P

Is there any blog post / white paper you can link to? Sounds interesting :)

[Chris Kawa]

I guess the line that need the most explaining is this one:

return Foo<T, std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value>::convert(_libraryItems);

All the std magic is just a verbose way of saying "is T a pointer and does it point to a const value" so it's pretty much
Foo<T, true>::convert(_libraryItems) for types that qualify and
Foo<T, false>::convert(_libraryItems) for those that don't.

Foo<T, false> will call into thet deleted specialization and Foo<T, true> into the real conversion.

std::is_pointer<T>::value - this is true for pointers, false for others
std::remove_pointer<T>::type - for any given pointer type it's a typedef for the pointed to type e.g for T being int* it's int.
std::is_const<X>::value - this is true for const types and false for others

Is there any blog post / white paper you can link to? Sounds interesting :)

It was a class assignment over a decade ago. I'm sure the topic has a vast coverage, but I can't give you any links because it's simply useless in practice and I hadn't any interest in it after completing it.

[VRonin]

I'm definitely in the wrong section of the forum given my knowledge of the language but why wouldn't a simple static_assert work here?

template<class T>
    QList<T> libraryItems() const
    {
static_assert(std::is_pointer<T>::value && std::is_const<std::remove_pointer<T>::type>::value,"You can only use const pointers as template parameters");
        QList<T> list;
\\ etc

[Chris Kawa]

@VRonin said in Template: Force const parameter:

why wouldn't a simple static_assert work here?

It definitely would.