Access Tabview button from main

[fermatqt]

hi!

i have this form:

Item {
    width: 900
    height: 900
    id: root

    TabView {
        id: tabView
        width: 900
        height: 900

        Tab {
            id: tabClienti
            title: "Clienti"
            source: "Clienti.qml"

            Rectangle {
                id: rectangleClienti
                x: 0
                y: 32
                width: 900
                height: 69
                color: "#ffffff"

                TextField {
                    id: textNpu
                    x: 8
                    y: 22
                    width: 164
                    height: 26
                    placeholderText: qsTr("NPU")
                }

                Button {
                    id: btnClienti
                    x: 807
                    y: 21
                    text: qsTr("Cerca")
                }
            }
        }
}

i'd need access to button from my main.qml:

ApplicationWindow {
    visible: true
    width: 900
    height: 900
    minimumWidth: 900
    minimumHeight: 900
    maximumWidth: 900
    maximumHeight: 900
    title: qsTr("Cimoda Admin")

    menuBar: MenuBar {
        Menu {
            title: qsTr("File")
            MenuItem {
                text: qsTr("&Open")
                onTriggered: console.log("Open action triggered");
            }
            MenuItem {
                text: qsTr("Exit")
                shortcut: "Ctrl+Q"
                onTriggered: Qt.quit();
            }
        }
    }

    MainForm {
        anchors.fill: parent
        // ACCESS TO BUTTON
    }
}

how can i do this operation in qml??

[SGaist]

Hi,

Why do you need to access that button from your ApplicationWindow ?

[fermatqt]

@SGaist

hi!

to set the onCliecked event.
if i do simething like this:

                Button {
                    id: btnClienti
                    x: 807
                    y: 21
                    text: qsTr("Cerca")
                    onClicked: messageDialog.show("hello")
                }

qtcreator tell me this message:

Functions are not supported in a Qt Quick UI Form

[SGaist]

It's not the role of your ApplicationWindow to know that there's a specific button in a sub-control from another control that you want do react on.

You should rather emit a signal from that form that you will react on in ApplicationWindow. That way you'll avoid tight coupling and maintenance nightmare. Just imagine that you change that button for something else, now you have to modify at least two files to make things work again.

[fermatqt]

something like this?

Item {
    width: 900
    height: 900
    id: root

    signal searchClient(string msg)

    TabView {
        id: tv
        width: 900
        height: 900

        Tab {
            id: tabClienti
            title: "Clienti"
            source: "Clienti.qml"

            Rectangle {
                id: rectangleClienti
                x: 0
                y: 32
                width: 900
                height: 69
                color: "#ffffff"

                TextField {
                    id: textNpu
                    x: 8
                    y: 22
                    width: 164
                    height: 26
                    placeholderText: qsTr("NPU")
                }

                Button {
                    id: btnClienti
                    x: 807
                    y: 21
                    text: qsTr("Cerca")
                    onClicked: root.searchClient("HELLO")
                }
            }
        }
    }

}

but i have always this message:

Functions are not supported in a Qt Quick UI Form

and the designer doesn't work properly!

[fermatqt]

ok, this seems to work:

        Button {
            id: btnClienti
            x: 800
            y: 21
            text: qsTr("Cerca")
            onClicked: {
                console.log('OK')
            }
        }