Parent in PyQt5 with QML

AliReza Beytari

I'm using PyQt5 with QML. This is my code:

import sys
from PyQt5.QtCore import QObject, QUrl, Qt
from PyQt5.QtWidgets import QApplication, QFileDialog
from PyQt5.QtQml import QQmlApplicationEngine

if __name__ == "__main__":

    def myBtnClicked():
        fileDialog = QFileDialog.getOpenFileName(win, 'Open file', '/home')

    app = QApplication(sys.argv)
    engine = QQmlApplicationEngine()
    ctx = engine.rootContext()
    ctx.setContextProperty("main", engine)

    engine.load('test.qml')

    win = engine.rootObjects()[0]    

    myBtn= win.findChild(QObject, "myBtn")
    myBtn.clicked.connect(myBtnClicked)

    win.show()
    sys.exit(app.exec_())

But when I click on "myBtn", I got this error:
builtins.TypeError: QFileDialog.getOpenFileName(QWidget parent=None, str caption='', str directory='', str filter='', str initialFilter='', QFileDialog.Options options=0) -> (str, str): argument 1 has unexpected type 'QWindow'

What is the solution?!

kshegunov

Hello,
Well it's says there in the question. Don't pass a QWindow to the QFileDialog::getOpenFileName function. A window is not a widget and it expects QWidget. You could just use NULL (or whatever its equivalent in python is).

Kind regards.