Help me understand C++ constructor syntax

Anonymous_Banned275

APPEND

I am not sure if this is a good idea - adding to older post , so I may copy it into a new post .

I am again at lost analyzing this syntax.

I have some udersting of the "new" entried, but I do not get this part

MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),

Would it be possible to get an expiation in English ?

I am trying to convert QMainWindow class to QWidget.

//! [0]
MainWindow::MainWindow(QWidget *parent) :
    QMainWindow(parent),
    m_ui(new Ui::MainWindow),
    m_status(new QLabel),
    m_console(new Console),
    m_settings(new SettingsDialog),
//! [1]
    m_serial(new QSerialPort(this))
//! [1]

DeviceDiscoveryDialog::DeviceDiscoveryDialog(QWidget *parent)
: QDialog(parent), localDevice(new QBluetoothLocalDevice),
ui(new Ui_DeviceDiscovery)
{

Where would be a good resource to learn this?

I actually need to get info on "localDevice" , and have never used C++ this way.

Actually this complex constructor is used by passing null pointer , or better - passing default NULL pointer
as QWidget *parent). Little too complex for me...

If it is OK - I could probably get started if somebody reads me the code in English...

Thanks

Chris Kawa

// Create an instance of DeviceDiscoveryDialog
// and pass a "parent" parameter of type QWidget* to the constructor
DeviceDiscoveryDialog::DeviceDiscoveryDialog(QWidget *parent)

// Call the constructor of base class QDialog and pass the "parent" parameter to it
: QDialog(parent),

// dynamically allocate an instance of class QBluetoothLocalDevice
// initialize member DeviceDiscoveryDialog::localDevice using that instance
localDevice(new QBluetoothLocalDevice),

// dynamically create an instance of class Ui_DeviceDiscovery
// initialize member DeviceDiscoveryDialog::ui  using that instance
ui(new Ui_DeviceDiscovery)

Where would be a good resource to learn this?

Probably any C++ book e.g. "A Tour of C++".
If you prefer online resource cppreference page about constructors is a good place to start.

DerReisende

I would like to throw this page into the ring which explains member initializer lists from the beginning.

Anonymous_Banned275

Thank you very much for replies. Appreciate the help.

I think I asked this before - would "allocate an instance of class" be same as " build an object of class " ?

Anonymous_Banned275

@DerReisende This is also "correct answer
. Thanks.

Chris Kawa

@AnneRanch said:

would "allocate an instance of class" be same as " build an object of class "

Yes