Context Menu : lambda triggered connect - called with same args?

[nicholas_yue]

I am attempting to build a context menu programmatically and connecting them too.

I thought I am passing unique arguments to my handler but when I print out the values, they all seems to be given the same arguments when I print them out in the function createInstance(). What am I doing wrongly in the loop ?

    def createInstance(self, category: str, classname: str):
        print('000000000000000000000 createInstance {}:{}'.format(category,classname))
        # self.scene().addNode(category, classname, xpos = 0, ypos = 0, node_id = None)

    def createContextMenu(self):
        menu = QtWidgets.QMenu()
        for k, v in self.scene().nodeManager.getClasses().items():
            submenu = menu.addMenu(k)
            for kk, vv in v.items():
                print('createContextMenu {}:{}'.format(k,kk))
                action = submenu.addAction(kk)

                # C++ version : https://stackoverflow.com/questions/42522136/qaction-triggered-signal-to-pass-parameter-to-slot
                # connect(copyDataAction, &QAction::triggered, this, [=](){
                # CopyTableData(DataTable);
                # });

                # PySide2 implementation : https://www.pythonguis.com/tutorials/pyside-transmitting-extra-data-qt-signals/
                action.triggered.connect(lambda x: self.createInstance(k, kk))

        return menu

[SGaist]

Use a parameter with default values as explained here.

[SGaist]

Hi,

k and kk (you should use proper variable names) are not captured so they keep the last value they were assigned.

[nicholas_yue]

@SGaist Thanks for the advice.

How do I ensure that they are captured, I cannot use string literal as I would not know in advanced what they will be.

Cheers

[SGaist]

Use a parameter with default values as explained here.

[nicholas_yue]

@SGaist Thank you for the link. I have got it working.