Find what rows are visible in a scrolling table

ACollins

I would appreciate if somebody can point me in the right direction. I have a table with 1 column and 60 rows of which 24 rows are visible at any one time. This table has 24 checkboxes on the side, one for each visible row. When a person clicks on the checkbox how can I find out which row was selected? If I can find out the top most row that is visible I can find out everything else. Is there any function that will tell me that say, 7th row is the top most visible row at this time? Thanks.

SGaist

Hi and welcome to devnet,

No there's no such method. However you can use visualRect to achieve that.

ACollins

SGaist: Thanks but I just started working with qt and visualRect is well beyond my grasp at this juncture.

Denni: I took your advice and added the checkboxes into the table using the code from the answer section of this post:
https://stackoverflow.com/questions/48057638/how-should-i-connect-checkbox-clicked-signals-in-table-widgets-in-pyqt5

Now how do I center this checkbox in the table cell? Thanks.

ACollins

My code for inserting the checkbox in the table looks like this. The checkbox comes out as left-justified and I would like to center it. Thanks.

    for i in range(self.tableWidget.rowCount()):
        ch = QtWidgets.QCheckBox(parent=self.tableWidget)
        ch.clicked.connect(lambda checked, row=0, col=i: self.onStateChanged(checked, row, col))
        self.tableWidget.setCellWidget(i, 0, ch)

JonB

@ACollins said in Find what rows are visible in a scrolling table:

ch.clicked.connect(lambda checked, row=0, col=i: self.onStateChanged(checked, row, col))

Before you overlook it, I presume you intend:

ch.clicked.connect(lambda checked, row=i, col=0: self.onStateChanged(checked, row, col))

(row/col values swapped).

This isn't the best way to do things [ I'm looking at you, @VRonin ;-) ], but from where you are now presumably you can always:

        w =  QtWidgets.QWidget(parent=self.tableWidget)
        w.setLayout(QtWidgets.QHBoxLayout())
        ch = QtWidgets.QCheckBox()
        w.layout().addWidget(ch)
        ch.clicked.connect(lambda checked, row=i, col=0: self.onStateChanged(checked, row, col))
        self.tableWidget.setCellWidget(i, 0, w)

i.e. just put the checkbox in a horizontal layout.

I'm not sure why in the code you copied from the author goes for a setCellWidget(QCheckBox) at all. Wouldn't a blank QTableWidgetItem with setFlags(... or Qt.ItemIsUserCheckable) suffice?

ACollins

Thank you very much JonB & Denni. All good and working perfectly!

Denni: I wasn't sure what MUC is. I have been away from programming for 15+ years so this lingo is all new. I think I will read the FAQ.