Find what rows are visible in a scrolling table

[ACollins]

I would appreciate if somebody can point me in the right direction. I have a table with 1 column and 60 rows of which 24 rows are visible at any one time. This table has 24 checkboxes on the side, one for each visible row. When a person clicks on the checkbox how can I find out which row was selected? If I can find out the top most row that is visible I can find out everything else. Is there any function that will tell me that say, 7th row is the top most visible row at this time? Thanks.

[SGaist]

Hi and welcome to devnet,

No there's no such method. However you can use visualRect to achieve that.

[ACollins]

SGaist: Thanks but I just started working with qt and visualRect is well beyond my grasp at this juncture.

Denni: I took your advice and added the checkboxes into the table using the code from the answer section of this post:
https://stackoverflow.com/questions/48057638/how-should-i-connect-checkbox-clicked-signals-in-table-widgets-in-pyqt5

Now how do I center this checkbox in the table cell? Thanks.

[ACollins]

My code for inserting the checkbox in the table looks like this. The checkbox comes out as left-justified and I would like to center it. Thanks.

    for i in range(self.tableWidget.rowCount()):
        ch = QtWidgets.QCheckBox(parent=self.tableWidget)
        ch.clicked.connect(lambda checked, row=0, col=i: self.onStateChanged(checked, row, col))
        self.tableWidget.setCellWidget(i, 0, ch)

[JonB]

@ACollins said in Find what rows are visible in a scrolling table:

ch.clicked.connect(lambda checked, row=0, col=i: self.onStateChanged(checked, row, col))

Before you overlook it, I presume you intend:

ch.clicked.connect(lambda checked, row=i, col=0: self.onStateChanged(checked, row, col))

(row/col values swapped).

This isn't the best way to do things [ I'm looking at you, @VRonin ;-) ], but from where you are now presumably you can always:

        w =  QtWidgets.QWidget(parent=self.tableWidget)
        w.setLayout(QtWidgets.QHBoxLayout())
        ch = QtWidgets.QCheckBox()
        w.layout().addWidget(ch)
        ch.clicked.connect(lambda checked, row=i, col=0: self.onStateChanged(checked, row, col))
        self.tableWidget.setCellWidget(i, 0, w)

i.e. just put the checkbox in a horizontal layout.

I'm not sure why in the code you copied from the author goes for a setCellWidget(QCheckBox) at all. Wouldn't a blank QTableWidgetItem with setFlags(... or Qt.ItemIsUserCheckable) suffice?

[ACollins]

Thank you very much JonB & Denni. All good and working perfectly!

Denni: I wasn't sure what MUC is. I have been away from programming for 15+ years so this lingo is all new. I think I will read the FAQ.