[PyQt5] QTableWidget Input crash with wchar_t (specifically, Korean characters)

[chan1123]

Hi. I'm developing my application with PyQt5.
I'm using QTableWidget, but when I try to insert Korean characters, it crashes.

I will describe what's possible and not possible.
After executing my program, I can click one cell on the QTableWidget.
And then, If I try to put a korean character with the changed input mode with convert key,
It crashes.

However, If I double click one cell on the QTableWidget, the cell edit is activated. And
I can see the text edit cursor. When it's in the situation, I can write korean characters without crash.

But, When I just use English, There is no problem like above.

Is there any way to solve this problem If I click one cell and try to put korean characters?

Thanks in advance.

[SGaist]

Hi and welcome to devnet,

Please provide a minimal example that reproduces your situation as well as a source for Korean input.

By the way:

• What version of PyQt5 are your using ?
• On what OS ?
• What python version ?

[chan1123]

Hi @SGaist .

• PyQt5 : 5.14.1
• Windows 10 1909
• Python 3.7 (32bit)

This is the minimal example that reproduces my situation.
and I noticed that the crash does not happen when I deleted setCellWidget().

I'm not sure you can have another country keyboard input.
You need your korean keyboard input to reproduce this crash.

So to reproduce this situation.

1. Get the Korean keyboard input
2. Execute this program
3. Convert input mode into Korean Input
4. Click one cell once
5. put the keyboard input
6. crash

As I already said, the program does not crash with English.

import sys
from PyQt5.QtCore import *
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *

screenWidth = 800
screenHeight = 600

def testCallback():
    print("cell changed")

def main():
    # App 초기화
    App = QApplication(sys.argv)

    # Window 초기화
    Window = QMainWindow()
    myDesktop = QApplication.desktop()
    rect = myDesktop.screenGeometry()
    Window.setGeometry(rect.width() / 2 - screenWidth / 2, rect.height() / 2 - screenHeight / 2, screenWidth, screenHeight);
    
    Widget = QWidget()
    myLayout = QVBoxLayout(Widget)
    myLabel = QLabel("blah")
    myLayout.addWidget(myLabel)
    myTable = QTableWidget(10, 3)
    
    myTable.setItem(0, 0, QTableWidgetItem(""))
    myTable.setItem(0, 1, QTableWidgetItem(""))
    myTable.setHorizontalHeaderLabels(("테스트1", "테스트2", "기능"))
    myTable.cellChanged.connect(testCallback)
    myLayout.addWidget(myTable)
    myTable.setCellWidget(0, 2, QLabel("hallo"))

    Window.setCentralWidget(Widget)
    Window.show()

    App.exec_()

if __name__ == "__main__":
    main()

I found the same issue on the Stackoverflow : https://stackoverflow.com/questions/54923039/pyqt5-with-qtablewidget-program-crashes-without-any-exception

I guess there is some error code on the QTableWidget implementation when handling with UTF-8 input, with the CellWidget added.

[eyllanesc]

@chan1123 Your code has an error: The callback that is expected to be callable (function, method, etc.) but instead you pass a string:

class AddButton(QPushButton):
    def __init__(self, callback, rowIndex):
        super(QPushButton, self).__init__("Add")
        self.rowIndex = rowIndex
        self.clicked.connect(lambda: callback(self))

myTable.setCellWidget(0, 2, AddButton("", 0))

Where:

callback = ""
rowIndex = 0

I recommend you to run your code in the console/terminal/CMD since many IDEs do not handle Qt errors correctly.

[chan1123]

@eyllanesc Okay. I see.
But, That's not the point in this issue.

I changed the code like this. It still crashes.

import sys
from PyQt5.QtCore import *
from PyQt5.QtGui import *
from PyQt5.QtWidgets import *

screenWidth = 800
screenHeight = 600

def testCallback():
    print("cell changed")

def main():
    # App 초기화
    App = QApplication(sys.argv)

    # Window 초기화
    Window = QMainWindow()
    myDesktop = QApplication.desktop()
    rect = myDesktop.screenGeometry()
    Window.setGeometry(rect.width() / 2 - screenWidth / 2, rect.height() / 2 - screenHeight / 2, screenWidth, screenHeight);
    
    Widget = QWidget()
    myLayout = QVBoxLayout(Widget)
    myLabel = QLabel("blah")
    myLayout.addWidget(myLabel)
    myTable = QTableWidget(10, 3)
    
    myTable.setItem(0, 0, QTableWidgetItem(""))
    myTable.setItem(0, 1, QTableWidgetItem(""))
    myTable.setHorizontalHeaderLabels(("테스트1", "테스트2", "기능"))
    myTable.cellChanged.connect(testCallback)
    myLayout.addWidget(myTable)
    myTable.setCellWidget(0, 2, QLabel("hallo"))

    Window.setCentralWidget(Widget)
    Window.show()

    App.exec_()

if __name__ == "__main__":
    main()

And I also executed the program on Windows Command line terminal.
and it does not output anything when it crahses.

[eyllanesc]

@chan1123 In Linux with PyQt5 5.14.1 and python 3.8 I don't see that problem. You could indicate the versions of the libraries in your environment.

[chan1123]

@eyllanesc
What does "the versions of the libraries" mean?
My environment is

• PyQt5 : 5.14.1
• Windows 10 1909
• Python 3.7 (32bit)

you are on the Linux, and I'm on the Windows

And Did you do my reproduction order? :

1. Get the Korean keyboard input
2. Execute this program
3. Convert input mode into Korean Input
4. Click one cell once
5. put the keyboard input
6. crash

[chan1123]

@Denni-0
Hi. I already wrote the MRE in the previous comment.
Please, look at the previous comments carefully.

And Can you give me a link where there is the compatibility issues document?

[John1014]

I had the same problem when typing Chinese character in QTableWidget if QTableWidget contain a widget in a cell

[XiaoTuDui]

I had the same problem when typing Chinese character in QTableWidget if QTableWidget contain a widget in a cell

[minor code]

HELP!!!!
same issue : https://forum.qt.io/topic/141477/qtablewidget-setcellwidget-input-crash-bug