object address

[ODБOï]

Hello,
sorry for this 2 stupid questions, i could not find information on this by my self.

   QObject * obj;
   obj = new QObject();
   qDebug() << "obj  : " << obj;
   qDebug() << "obj adr  : " << &obj;

//output
//obj  :  QObject(0x2532b60)
//obj adr :  0x65fd48

what is the 0x2532b60 ? i always tought it is the object adress.

second question is : If i look at qdebug operator << https://doc.qt.io/qt-5/qdebug.html#public-functions
i don't understand witch one is used when i call,

qDebug() << obj;

is it the last one "operator<<(const void *t)" ?
Thank you

[Christian Ehrlicher]

@LeLev said in object adress:

what is the 0x2532b60 ? i always tought it is the object adress.

&obj

since obj is a pointer, you see the address of the pointer

[Konstantin Tokarev]

@LeLev said in object adress:

what is the 0x2532b60 ? i always tought it is the object adress.

0x2532b60 is the address of QObject, which is allocated in heap by operator new.

0x65fd48 is the address of obj variable of type QObject*, which is allocated on stack and holds address of QObject object.

second question is : If i look at qdebug operator << https://doc.qt.io/qt-5/qdebug.html#public-functions
i don't understand witch one is used when i call,

qDebug() << obj;

is it the last one "operator<<(const void *t)" ?

No, it's QDebug operator<<(QDebug, const QObject *). Overload for void* pointers prints just value without "QObject(...)" wrapping

[ODБOï]

@Christian-Ehrlicher, @Konstantin-Tokarev
thank you very much for your inputs.