[PyQt4] QTableWidget Readonly?

[SGaist]

@Daniel26 said in [PyQt4] QTableWidget Readonly?:

QTableWidgetItem is only a cell of the QTableWidget? is that correct?

Not exactly, it's an object that will be stored in the model coming with QTableWidget and provide all the necessary data to be rendered by a cell of the table.

A QTableWidget is a QTableView + a model all packed in one.

You should check the Model/View Programming chapter in Qt's documentation for a good overview of how it is working.

[Daniel26]

Ok,

so I set every Cell with an empty QWidgetItem so I can set it to readOnly?

I'm totally confused....

[JonB]

@Daniel26
You can indeed do it as @Denni-0 has said. To my mind, it doesn't really make the cells read-only, but it does stop the user doing anything to edit :) And it's only one line!

For making the items not-editable, you could look at the code in https://stackoverflow.com/questions/7727863/how-to-make-a-cell-in-a-qtablewidget-read-only/ which is the accepted solution. Other answers there also show @Denni-0 's approach.

[Daniel26]

hello @ all,

thanks for the help. I've got it, did it with the QTableWidget.
But how can I check, if a column is empty?
A simple "if self.addip_tw.item(x,y)" won't work :)

Regards

Daniel

[JonB]

@Daniel26
What do you mean by "if a column is empty"? Plus, why do you care if you are choosing to go for the simplest QTreeView.setEditTriggers(QAbstractItemView.NoEditTriggers)?

[Daniel26]

Sorry, I ment if a cell is empty.

I store the content of the cells into a dictionary, but only if the first cell of the line is not empty.

[JonB]

@Daniel26
The I don't understand why you say

A simple "if self.addip_tw.item(x,y)" won't work :)

since https://doc.qt.io/qt-5/qtablewidget.html#item does return nullptr for no item.

[Daniel26]

@JonB
if self.addip_tw.item[row,0]:
TypeError: 'builtin_function_or_method' object has no attribute 'getitem'

[JonB]

@Daniel26
Please look at your code before saying things "don't work". Could this be because item() is a function and not an array?

[Daniel26]

Maybe.....fu....I'm blind, sorry.