Problem login window

[fra_mecc]

@jsulm I should define a function (?) so if "Username and password == test" then my icon goes off. But I do not know how to define the function

[ODБOï]

@fra_mecc hi,
Whitch kind of application is this? Could you show your code exemple ?

one solution could be to having states on your client, ( connected, disconnected )
Create a boolean bool connected=false;
then in your connection funtion, if (username=="test" && pass=="test") connected=true

after this you can use 'connected' as condition

//qml exemple
Image{
source : connected ? "img/disconect.png" : "img/connect.png"
}

[fra_mecc]

@LeLev I did not understand much ..I show you the code of dialog file:

#include "accedi.h"
#include "ui_accedi.h"
#include <QMessageBox>
#include <QLineEdit>

Accedi::Accedi(QWidget *parent) :
    QDialog(parent),
    ui(new Ui::Accedi)
{
    ui->setupUi(this);
    setWindowTitle("Accedi");
    setWindowIcon(QIcon("accedi.png"));
}

Accedi::~Accedi()
{
    delete ui;
}

void Accedi::on_buttonBox_accepted()
{

}

void Accedi::on_pushButton_2_clicked()
{
    hide();
}

void Accedi::on_pushButton_clicked()
{
    QString username = ui->lineEdit_username->text();
    QString password = ui->lineEdit_password->text();

    if(username == "test" && password == "test") {
        ui->status->setText("Accesso effettuato.");
        QMessageBox::information(this, "Accesso effettuato",
                                       "Bentornato! \nOra potrai usare il programma registrando automaticamente i risultati sul tuo account.");
        hide();
        ui->status->clear();
        ui->status->setText("Connessione...");
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();


    }
    else {
        ui->status->setText("Accesso Negato! Username o password errati");
        //ui->status->clear();
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();

        //QMessageBox::warning(this, "Accesso negato", "Username e password sono errati");
    }



}

```and this is the part of code of Main Windows (where there is the icon):

}

void MainWindow::on_actionLogin_2_triggered()
{
login->show();
}

[ODБOï]

@fra_mecc

if(username == "test" && password == "test") {
        ui->status->setText("Accesso effettuato.");

// can't you change your image here ?  ui->yourIcon->setEnabled(false);

        QMessageBox::information(this, "Accesso effettuato",
                                       "Bentornato! \nOra potrai usare il programma registrando automaticamente i risultati sul tuo account.");
        hide();
        ui->status->clear();
        ui->status->setText("Connessione...");
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();


    }
    else {
        ui->status->setText("Accesso Negato! Username o password errati");
        //ui->status->clear();
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();

        //QMessageBox::warning(this, "Accesso negato", "Username e password sono errati");
    }

[fra_mecc]

@LeLev ui-> yourIcon->setEnabled(false); it's a piece of code that belongs to the main window while the if loop belongs to a "login" file.
It does not let me insert the Main Windows code in the other file

[KillerSmath]

@fra_mecc

if loop belongs to a "login" file.
It does not let me insert the Main Windows code in the other file

You could emit the accept or reject signal of dialog and capture them of mainwindow:
NOTE: when accept or reject signals are emitted, your dialog is forced to close.

Login Dialog cpp

if(username == "test" && password == "test") {
        ui->status->setText("Accesso effettuato.");

        QMessageBox::information(this, "Accesso effettuato",
                                       "Bentornato! \nOra potrai usare il programma registrando automaticamente i risultati sul tuo account.");
        ui->status->clear();
        ui->status->setText("Connessione...");
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();

        accept(); // emit accept signal
    }
    else {
        ui->status->setText("Accesso Negato! Username o password errati");
        ui->lineEdit_username->clear();
        ui->lineEdit_password->clear();

        //QMessageBox::warning(this, "Accesso negato", "Username e password sono errati");
    }

main window :

void MainWindow::on_actionLogin_2_triggered () 
{ 
  int returnCode = login->exec();

  if(returnCode == QDialog::Accepted)  // returns by accept signal
     ui->yourIcon->setEnabled(false);
  else if(dialogCode == QDialog::Rejected)
     ui->yourIcon->setEnabled(true);
}

or you can connect thefinished (int)signal of login dialog to a mainwindow slot or lambda function and do the same action.

[fra_mecc]

This post is deleted!

[fra_mecc]

@KillerSmath Resolved! Thanks so much! I do not know how to thank you..

[ODБOï]

@fra_mecc up vote him :p

[jsulm]

@fra_mecc Keep in mind that it is very easy to find the user name and password in your executable. So, if an user with a bit of knowledge gets your app he/she will extract the user name and password from the executable file.