Maximize application on display 2 when existing

filipdns

@jpnurmi oh ok, I have the 5.9.0, I go to update it then, thank you

ODБOï

@jpnurmi said in Maximize application on display 2 when existing:

visibility: Window.Maximized

Hello, do visibility : Window::Maximized or visibility : "Maximized"
LA

filipdns

oh no qt used is the 5.9.2 then no reason to get this error...

filipdns

I got same error under QT 5.10...

jpnurmi

Works for me with Qt 5.9.3 and 5.10.0. What did you import? How does the relevant part of the code look like, that you're trying to run?

filipdns

I'm using stackview main qml is like that:

import QtQuick 2.9
import QtQuick.Controls 2.1
import QtQuick.Window 2.3
import QtQuick.Controls.Styles 1.1
import QtQuick.Controls 1.4

ApplicationWindow {
    id: window
    visible: true   // this is mandatory
    visibility: Window.Maximized
    screen: Qt.application.screens[1] || null

    StackView {
        id: stackView
        //y:60
        anchors.fill: parent
        initialItem: GardePage {
            header: ToolBar {
                width: parent.width
                height: 60
                style: ToolBarStyle {
                        padding {
                            left: 8
                            right: 8
                            top: 3
                            bottom: 3
                        }
                        background: Rectangle {
                            gradient: Gradient {
                                GradientStop { position: 0 ; color: "black" }
                                GradientStop { position: 1 ; color: "green" }
                            }
                        }
                    }

                Label {
                    id: pageTitle
                    text: "KARDEX DU SIA DE L'IGN "
                    textFormat: Text.AutoText
                    fontSizeMode: Text.VerticalFit
                    font.pixelSize: 50
                    color: "lightgrey"
                    anchors.centerIn: parent
                    font.family: "Times New Roman"
                    font.bold: true
                    font.italic: true

                }
            }
        }
    }
}

filipdns

you probably see I'm importing 2 QtQuick.Controls, the 1.4 and the 2.1, It's not an error, don't ask me why but some functions work with one and other with the other, 2.1 don't take all function of the 1.4...

jpnurmi

It's fine to import QtQuick.Controls 1.x and QtQuick.Controls 2.x in the same file, but only if you specify namespaces to avoid conflicts. In this particular QML file, you're not actually using QtQuick.Controls 2.x for anything. The ApplicationWindow, StackView, ToolBar, and Label types provided by QtQuick.Controls 2.x are all overridden by the QtQuick.Controls 1.x import that comes later.

The correct way to mix QQC1 and QQC2:

import QtQuick.Controls 1.x as C1
import QtQuick.Controls 2.x as C2

C2.ApplicationWindow {
    // ...
    C1.ToolBar {
        // ...
    }
    // ...
}

How you call the namespaces is up to you, but as long as at least one of the overlapping imports has a namespace, you avoid a lot of confusion. However, I don't see anything in this file that cannot be done with Qt Quick Controls 2. The changes are minimal:

import QtQuick 2.9
import QtQuick.Controls 2.1
import QtQuick.Window 2.3

ApplicationWindow {
    id: window
    visible: true   // this is mandatory
    visibility: Window.Maximized
    screen: Qt.application.screens[1] || null

    StackView {
        id: stackView
        anchors.fill: parent
        initialItem: GardePage {
            header: ToolBar {
                width: parent.width
                height: 60
                leftPadding: 8
                rightPadding: 8
                topPadding: 3
                bottomPadding: 3
                background: Rectangle {
                    gradient: Gradient {
                        GradientStop { position: 0 ; color: "black" }
                        GradientStop { position: 1 ; color: "green" }
                    }
                }

                Label {
                    id: pageTitle
                    text: "KARDEX DU SIA DE L'IGN "
                    textFormat: Text.AutoText
                    fontSizeMode: Text.VerticalFit
                    font.pixelSize: 50
                    color: "lightgrey"
                    anchors.centerIn: parent
                    font.family: "Times New Roman"
                    font.bold: true
                    font.italic: true
                }
            }
        }
    }
}

filipdns

Thank you very much.

Then now, with [1] the application start correctly on screen 2 fine, but with [0] or [2] the application start on screen were my mouse is

jpnurmi

This statement:

screen: Qt.application.screens[1] || null

means that the second screen will be set, or if not available (no such entry in the array == undefined) it assigns null instead to avoid:

Cannot assign undefined to Screen

It’s an example. Adapt it to your needs.

filipdns

yes understood but If I want to have 2 qt applications and force 1 in screen 1 and other on screen 2, how do that?
I try :

screen: Qt.application.screens[0]

but it's not working

jpnurmi

On which platform? If screen: Qt.application.screens[0] doesn't place the window on the primary screen, you should report a bug at bugreports.qt.io and provide details about the platform. Provide a minimal but complete runnable test case without references to any GardePage and others. Explain what you are doing, what you expect to happen, and what you get instead.

I don't have access to a suitable environment right now to be able to test, but out of curiosity, does it make any difference if you assign the screen in Component.onCompleted?

Window {
    Component.onCompleted: screen = Qt.application.screens[0]
}

Also, have you inspected, what is the contents of the Qt.application.screens array, actually?

filipdns

no difference with

Component.onCompleted: screen = Qt.application.screens[0]

jpnurmi

What about in C++?

#include <QtGui>
#include <QtDebug>

int main(int argc, char *argv[])
{
    QGuiApplication app(argc, argv);

    QWindow window;
    window.resize(100, 100);
    window.setScreen(app.screens().value(1));
    window.show();

    qDebug() << "available:" << app.screens();
    qDebug() << "primary:" << app.primaryScreen();
    qDebug() << "window:" << window.screen();

    return app.exec();
}

filipdns

@jpnurmi debug say:
available: (QScreen(0x3923528, name="\\.\DISPLAY1"), QScreen(0x39236b0, name="\\.\DISPLAY2"))
primary: QScreen(0x3923528, name="\\.\DISPLAY1")
window: QScreen(0x3923528, name="\\.\DISPLAY1")

or

available: (QScreen(0x36b0f30, name="\\.\DISPLAY1"), QScreen(0x36b1160, name="\\.\DISPLAY2"))
primary: QScreen(0x36b0f30, name="\\.\DISPLAY1")
window: QScreen(0x36b1160, name="\\.\DISPLAY2")

following mouse position window: QScreen switch to DISPLAY1 or DISPLAY2
changing
window.setScreen(app.screens().value(0));
to
window.setScreen(app.screens().value(1));
nothing change