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ASSERT failure in QList<T>::operator[]: "index out of range"

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  • JerwinprabuJ Jerwinprabu

    I am still relatively new to Qt and I have recently been working on a large project. When I attempt to run the project I get this error:

    /ASSERT failure in QList<T>::operator[]: "index out of range", file /usr/include/arm-linux-gnueabihf/qt5/QtCore/qlist.h, line 487
    The program has unexpectedly finished.
    

    How I might go about tracking down the source of the problem?

    I believe that the addition of this code is causing the error

    startvaluexy = Client::straightxy;
    qDebug() << "start value Received from server :" << startvaluexy;
    QStringList xy = startvaluexy.split("|");
    
    x = xy[2];
    
    QString num1 = x;
    int x = num1.toInt();
    
    qDebug() << "start x value :" << x;
    
    y = xy[3];
    
    QString num2 = y;
    int y = num2.toInt();
    
    qDebug() << "start y value :" << y;
    

    When this x = xy[2]; y = xy[3]; is taken out, then runs fine.

    joeQJ Offline
    joeQJ Offline
    joeQ
    wrote on last edited by
    #4

    @Jerwinprabu Hi,friend,welcome.

    I modified your code snippet.

    startvaluexy = Client::straightxy;
    qDebug() << "start value Received from server :" << startvaluexy;
    QStringList xy = startvaluexy.split("|");
    int xySize = sy.size(); ///< get the xy list size;
    
    if(xySize < 4){
        return false;
    }
    
    bool ok;
    int x = xy[2].toInt(&ok); ///< you should check whether convert success
    if(!ok){
        return false;
    }
    
    int y = xy[3].toInt(&ok);
    if(!ok){
        return false;
    }
    
    // when run here, you will get the correct x,y value
    return true;
    

    Just do it!

    1 Reply Last reply
    2
    • JerwinprabuJ Offline
      JerwinprabuJ Offline
      Jerwinprabu
      wrote on last edited by
      #5

      If I sent start command from server, output displayed like this on client side

      WebSocket connected
      message received : "straight|xy|3|0" 
      
      start xy value Received from server : "straight|xy|3|0"
      start x value emitted to Robot : 3
      start y value emitted to Robot: 0
      int of start x value emitted : 3
      int start y value emitted : 0
      

      If I click start button on client side that time only I got the error.

      WebSocket connected
      
      start xy value Received from server : ""
      ASSERT failure in QList<T>::operator[]: "index out of range", file /usr/include/arm-linux-gnueabihf/qt5/QtCore/qlist.h, line 487
      
      jsulmJ 1 Reply Last reply
      0
      • JerwinprabuJ Jerwinprabu

        If I sent start command from server, output displayed like this on client side

        WebSocket connected
        message received : "straight|xy|3|0" 
        
        start xy value Received from server : "straight|xy|3|0"
        start x value emitted to Robot : 3
        start y value emitted to Robot: 0
        int of start x value emitted : 3
        int start y value emitted : 0
        

        If I click start button on client side that time only I got the error.

        WebSocket connected
        
        start xy value Received from server : ""
        ASSERT failure in QList<T>::operator[]: "index out of range", file /usr/include/arm-linux-gnueabihf/qt5/QtCore/qlist.h, line 487
        
        jsulmJ Offline
        jsulmJ Offline
        jsulm
        Lifetime Qt Champion
        wrote on last edited by jsulm
        #6

        @Jerwinprabu You see: you're trying to split an empty string, this is not going to work. So please add some check to your code as @joeQ suggested.
        And you should check why you don't get what server sent, but this is another issue.

        https://forum.qt.io/topic/113070/qt-code-of-conduct

        1 Reply Last reply
        3
        • JerwinprabuJ Offline
          JerwinprabuJ Offline
          Jerwinprabu
          wrote on last edited by Jerwinprabu
          #7

          @joeQ When I was try to run the program I got the error

          error: return-statement with a value, in function returning 'void' [-fpermissive]
                   return false;
          
          joeQJ jsulmJ 2 Replies Last reply
          0
          • JerwinprabuJ Jerwinprabu

            @joeQ When I was try to run the program I got the error

            error: return-statement with a value, in function returning 'void' [-fpermissive]
                     return false;
            
            joeQJ Offline
            joeQJ Offline
            joeQ
            wrote on last edited by joeQ
            #8

            @Jerwinprabu (⊙o⊙)…

            bool myFunctionName() ///< Notes; function return value type must bool
            {
                  /* ... */
                  return true;
            }
            

            Just do it!

            1 Reply Last reply
            4
            • JerwinprabuJ Jerwinprabu

              @joeQ When I was try to run the program I got the error

              error: return-statement with a value, in function returning 'void' [-fpermissive]
                       return false;
              
              jsulmJ Offline
              jsulmJ Offline
              jsulm
              Lifetime Qt Champion
              wrote on last edited by
              #9

              @Jerwinprabu @joeQ Or just do

              return;
              

              if you do not use the return value...

              https://forum.qt.io/topic/113070/qt-code-of-conduct

              1 Reply Last reply
              3
              • JerwinprabuJ Offline
                JerwinprabuJ Offline
                Jerwinprabu
                wrote on last edited by Jerwinprabu
                #10

                @jsulm @joeQ Thanks for your help. Ya @joeQ given proper sample. I have tried that. Here I have posted the solution now client side that is working fine, one time I want to check from server side. Kindly check, if anything wrong awaiting for your further response

                startvaluexy = Client::straightxy;
                qDebug() << "start xy value Received from server :" << startvaluexy;
                QStringList xy = startvaluexy.split("|");
                int xySize = xy.size(); 
                qDebug() << "start xy size :" << xySize;
                
                if(xySize > 4){
                     x = xy[2];
                     y = xy[3];
                  }
                
                     QString num1 = x;
                     int x = num1.toInt();
                
                     qDebug() << "start x value  :" << x;
                
                     QString num2 = y;
                     int y = num2.toInt();
                
                     qDebug() << "start y value :" << y;
                
                    xstart = x;
                    ystart = y;
                

                After checking the size will modify this xySize > 4

                jsulmJ 1 Reply Last reply
                0
                • JerwinprabuJ Jerwinprabu

                  @jsulm @joeQ Thanks for your help. Ya @joeQ given proper sample. I have tried that. Here I have posted the solution now client side that is working fine, one time I want to check from server side. Kindly check, if anything wrong awaiting for your further response

                  startvaluexy = Client::straightxy;
                  qDebug() << "start xy value Received from server :" << startvaluexy;
                  QStringList xy = startvaluexy.split("|");
                  int xySize = xy.size(); 
                  qDebug() << "start xy size :" << xySize;
                  
                  if(xySize > 4){
                       x = xy[2];
                       y = xy[3];
                    }
                  
                       QString num1 = x;
                       int x = num1.toInt();
                  
                       qDebug() << "start x value  :" << x;
                  
                       QString num2 = y;
                       int y = num2.toInt();
                  
                       qDebug() << "start y value :" << y;
                  
                      xstart = x;
                      ystart = y;
                  

                  After checking the size will modify this xySize > 4

                  jsulmJ Offline
                  jsulmJ Offline
                  jsulm
                  Lifetime Qt Champion
                  wrote on last edited by jsulm
                  #11

                  @Jerwinprabu said in ASSERT failure in QList<T>::operator[]: "index out of range":

                  if(xySize > 4){

                  shouldn't it be

                  if(xySize >= 4){
                  

                  ?
                  And if it is not >= 4 what would be the values of x and y? Shouldn't you just skip processing in this case (do return as @joeQ suggested)?

                  What are you trying to do with this

                  QString num1 = x;
                  int x = num1.toInt();
                  

                  ?! Why do you assign an integer to a string and then convert this string to integer again? Same for

                  QString num2 = y;
                  int y = num2.toInt();
                  

                  https://forum.qt.io/topic/113070/qt-code-of-conduct

                  JerwinprabuJ 1 Reply Last reply
                  0
                  • jsulmJ jsulm

                    @Jerwinprabu said in ASSERT failure in QList<T>::operator[]: "index out of range":

                    if(xySize > 4){

                    shouldn't it be

                    if(xySize >= 4){
                    

                    ?
                    And if it is not >= 4 what would be the values of x and y? Shouldn't you just skip processing in this case (do return as @joeQ suggested)?

                    What are you trying to do with this

                    QString num1 = x;
                    int x = num1.toInt();
                    

                    ?! Why do you assign an integer to a string and then convert this string to integer again? Same for

                    QString num2 = y;
                    int y = num2.toInt();
                    
                    JerwinprabuJ Offline
                    JerwinprabuJ Offline
                    Jerwinprabu
                    wrote on last edited by
                    #12

                    @jsulm from server I will receive the string then I want to convert that string into int. Again I want to convert for sending to server(for map).

                    jsulmJ 1 Reply Last reply
                    0
                    • JerwinprabuJ Jerwinprabu

                      @jsulm from server I will receive the string then I want to convert that string into int. Again I want to convert for sending to server(for map).

                      jsulmJ Offline
                      jsulmJ Offline
                      jsulm
                      Lifetime Qt Champion
                      wrote on last edited by jsulm
                      #13

                      @Jerwinprabu Then why do you convert it back from string to int? x is already int, what's the point to convert from string to int?
                      Also

                      QString num1 = x;
                      

                      is not a conversion to string from int! It will not even compile. If you want to convert int to string then do it like shown here http://doc.qt.io/qt-5/qstring.html#number

                      https://forum.qt.io/topic/113070/qt-code-of-conduct

                      JerwinprabuJ 1 Reply Last reply
                      0
                      • jsulmJ jsulm

                        @Jerwinprabu Then why do you convert it back from string to int? x is already int, what's the point to convert from string to int?
                        Also

                        QString num1 = x;
                        

                        is not a conversion to string from int! It will not even compile. If you want to convert int to string then do it like shown here http://doc.qt.io/qt-5/qstring.html#number

                        JerwinprabuJ Offline
                        JerwinprabuJ Offline
                        Jerwinprabu
                        wrote on last edited by Jerwinprabu
                        #14

                        @jsulm Because I want to take that value to int only xstart, ystart. I want to convert from string to int only. x, y is not int.

                        QString x;
                        QString y;
                        
                        jsulmJ 2 Replies Last reply
                        0
                        • JerwinprabuJ Jerwinprabu

                          @jsulm Because I want to take that value to int only xstart, ystart. I want to convert from string to int only. x, y is not int.

                          QString x;
                          QString y;
                          
                          jsulmJ Offline
                          jsulmJ Offline
                          jsulm
                          Lifetime Qt Champion
                          wrote on last edited by jsulm
                          #15

                          @Jerwinprabu Again

                          QString num1 = x;
                          int x = num1.toInt();
                          

                          x already contains the integer value! Now you convert it to string then again to int - it will be same as before.

                          int x = 1;
                          QString num1 = QString::number(x);
                          x = num1.toInt();
                          qDebug() << x;
                          

                          What do you think the last line will print out?
                          Shouldn't it be just

                          QString num1 = QString::number(x);
                          xstart = x;
                          

                          ?

                          https://forum.qt.io/topic/113070/qt-code-of-conduct

                          1 Reply Last reply
                          0
                          • JerwinprabuJ Jerwinprabu

                            @jsulm Because I want to take that value to int only xstart, ystart. I want to convert from string to int only. x, y is not int.

                            QString x;
                            QString y;
                            
                            jsulmJ Offline
                            jsulmJ Offline
                            jsulm
                            Lifetime Qt Champion
                            wrote on last edited by
                            #16

                            @Jerwinprabu Also here you redefine the variable x

                            QString num1 = x;
                            int x = num1.toInt();
                            

                            is there a reason why you're doing this?

                            https://forum.qt.io/topic/113070/qt-code-of-conduct

                            1 Reply Last reply
                            0
                            • jsulmJ Offline
                              jsulmJ Offline
                              jsulm
                              Lifetime Qt Champion
                              wrote on last edited by
                              #17

                              After chatting with @Jerwinprabu I realised that I misunderstood his code: x and y are actually QString not int.

                              https://forum.qt.io/topic/113070/qt-code-of-conduct

                              mrjjM 1 Reply Last reply
                              1
                              • jsulmJ jsulm

                                After chatting with @Jerwinprabu I realised that I misunderstood his code: x and y are actually QString not int.

                                mrjjM Offline
                                mrjjM Offline
                                mrjj
                                Lifetime Qt Champion
                                wrote on last edited by
                                #18

                                @jsulm
                                Well x is a pretty confusing name for a string in most cases.
                                I was sure also it was int.

                                1 Reply Last reply
                                1

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