[ SOLVED ]Problem in getting mouseEvent on QTableWidget

giesbert

I only fixed the compare statement, not optimized the whole code ;-)

luca72

There is a way to know if is the right or left button thet he press?

Luca

giesbert

Cast the event to a QMouseEvent and use the members

M_31

Now i am able to get the co-ordinates from mouse press & release event

@
if( object == ui->TableWidget->viewport() )
{
QMouseEvent mouseEvent = static_cast <QMouseEvent>( event );
qDebug()<<"MouseButtonPress event!@"<<mouseEvent->x()<<":"<<mouseEvent->y();

        QTableWidgetItem *item =  ui->TableWidget->currentItem();
       // qDebug()<<"ITEMS !@"<<item->row()<<":"<<item->column();

//This line is not working ..my app is getting crashing ..saying that ..No value found in "item"

@

Is there any other to get the QTableWidget row & column value using mouse event other than X & Y
co-ordinates....

giesbert

[quote author="M_31" date="1316014954"]Now i am able to get the co-ordinates from mouse press & release event

@
if( object == ui->TableWidget->viewport() )
{
QMouseEvent mouseEvent = static_cast <QMouseEvent>( event );
qDebug()<<"MouseButtonPress event!@"<<mouseEvent->x()<<":"<<mouseEvent->y();

        QTableWidgetItem *item =  ui->TableWidget->currentItem();
       // qDebug()<<"ITEMS !@"<<item->row()<<":"<<item->column();

//This line is not working ..my app is getting crashing ..saying that ..No value found in "item"

@

Is there any other to get the QTableWidget row & column value using mouse event other than X & Y
co-ordinates....[/quote]

No, it is not.

The only way is to use "indexAt":http://doc.qt.nokia.com/latest/qabstractitemview.html#indexAt

luca72

Hello i have one question :

@bool Widget::eventFilter(QObject *object, QEvent *event){
if (object == ui->tableWidget->viewport()){
QMouseEvent mouseEvent = static_cast<QMouseEvent>(event);
if (mouseEvent->button()==2){
messaggio = new QMessageBox;
messaggio->information(this,tr("Packing"),tr("Tasto destro schiacciato"),messaggio->Ok);
}
}
}@

Why the message is open two time when i click the right button?

Thanks

Luca

giesbert

it is called for mousepress and mouserelease... :-)
and you even do not check, which one is called...

@
bool Widget::eventFilter(QObject *object, QEvent *event)
{
if (object == ui->tableWidget->viewport())
{
QMouseEvent mouseEvent = static_cast<QMouseEvent>(event);
if ((QEvent::MouseButtonPress == event->type()) && (mouseEvent->button()==Qt::RightButton))
{
messaggio = new QMessageBox;
messaggio->information(this,tr("Packing"),tr("Tasto destro schiacciato"),messaggio->Ok);
}
}
}
@

Additionally, I suggest not to use magic numbers, if there are enums that can be used...

M_31

Thanks Gerolf...for your valuable inputs..
Its working fine with viewport and i achived my task...

timswoosh

Hi, everyone!

I had a similar problem and used a similiar approach to it, but I faced an obstacle when used method QTableWidget::itemAt: it uses coordinates relative to the left upper corner of data cells and doesn't take to account header cells!
So, when I transformed global coordiantes to the widget's ones via QWidget::mapFromGlobal I obtained not what I needed at all!
It gave me coordinates relative to the left upper corner of the widget itself, not the data cells.
How can I obtain the proper coordinates?

I wanted to try methods QTableView::horizontalOffset() and QTableView::verticalOffset(), but they are protected :(
(Sorry for my English, it's not my native language)

[quote author="Gerolf" date="1316016131"]
No, it is not.

The only way is to use "indexAt":http://doc.qt.nokia.com/latest/qabstractitemview.html#indexAt[/quote]

timswoosh

Hi, everyone!

I had a similar problem and used a similiar approach to it, but I faced an obstacle when used method QTableWidget::itemAt: it uses coordinates relative to the left upper corner of data cells and doesn't take to account header cells!
So, when I transformed global coordiantes to the widget's ones via QWidget::mapFromGlobal I obtained not what I needed at all!
It gave me coordinates relative to the left upper corner of the widget itself, not the data cells.
How can I obtain the proper coordinates?

I wanted to try methods QTableView::horizontalOffset() and QTableView::verticalOffset(), but they are protected :(
(Sorry for my English, it's not my native language)

[quote author="Gerolf" date="1316016131"]
No, it is not.

The only way is to use "indexAt":http://doc.qt.nokia.com/latest/qabstractitemview.html#indexAt[/quote]

andre

Well, as you can see from the QAbstractScrollArea documentation, of which QTableWidget is derived, the actual scrolling area is provided by a widget called viewport. That widget can be also be used for your coordinate transformations.

andre

Well, as you can see from the QAbstractScrollArea documentation, of which QTableWidget is derived, the actual scrolling area is provided by a widget called viewport. That widget can be also be used for your coordinate transformations.

timswoosh

Thank you, that's what I need!
Sorry I failed to find it myself...

I guess it would be advisable to add a link to viewport() member into QTableWidgetItem::itemAt() documentation.

[quote author="Andre" date="1421132571"]Well, as you can see from the QAbstractScrollArea documentation, of which QTableWidget is derived, the actual scrolling area is provided by a widget called viewport. That widget can be also be used for your coordinate transformations.[/quote]

timswoosh

Thank you, that's what I need!
Sorry I failed to find it myself...

I guess it would be advisable to add a link to viewport() member into QTableWidgetItem::itemAt() documentation.

[quote author="Andre" date="1421132571"]Well, as you can see from the QAbstractScrollArea documentation, of which QTableWidget is derived, the actual scrolling area is provided by a widget called viewport. That widget can be also be used for your coordinate transformations.[/quote]