Convert QQuickItem* to QObject*

Adrian.Aioanei

I have succeed to create some signal an qml and some slot to deal with them.
I have created an empty project with the new application and it works, but when i add the code to an older app it say
cannot convert 'QQuickItem*' to 'QObject*' in initialization QObject *item = view2.rootObject()

My function look like this:

void fromQML::loadQuestion()
{
    view2.setSource (QUrl("qrc:/question.qml"));
    QObject *item = view2.rootObject(); //here is the error and doesn't work if i make cast
    loadProcess load;
    QObject::connect(item, SIGNAL(qmlYesSig()),&load, SLOT(forYes()));
    QObject::connect(item, SIGNAL(qmlNoSig()),&load, SLOT(forNo()));
}

It the working application the code looks like this:

    QGuiApplication app(argc, argv);

    QQuickView view;
    view.setSource (QUrl("qrc:/main.qml"));
    QObject *item = view.rootObject();

    testClass myClass;
    QObject::connect(item, SIGNAL(qmlYesSig(QString)),
                     &myClass, SLOT(cppSlot(QString)));

    QObject::connect(item, SIGNAL(qmlNoSig(QString)),
                     &myClass, SLOT(cppSlot(QString)));

From my point of view is the same staff so i don't understand why in first sample doesn't work and is the second does.

Adrian.Aioanei

I have try again and if i make the connection in main it works but if i copy and paste the some code in a C++ slot it give me the above error.

SGaist

Hi,

While that is surprising, why not use QQuickItem* item = view2.rootObject(); since it's what the method returns ?

Note that your load object will be destroyed at the end of loadQuestion so it might not do anything.