Comparison of QChars

LogiSch17

Hi guys,
sry for this nooby question, but i am trying to compare a QChar out of a QString with a simple char and i dont get it.

I have simply a line of numbers and want to seperate it where a ":" is.
For example 315:15 -> x=315 , y=15

here is my code

QString part1="";
QString part2="";
bool before;
for(int y=0; y < line.size(); y++){
        if( before && line.at(y)!=":")){
                        part1 += line.at(y);
         }else if(line.at(y)==":"){
                        before = false;
         }else if(!before && line.at(y)=""){
                        part2 += line.at(y);
        }
}

In this case i get the errror:

 error: no match for 'operator==' (operand types are 'const QChar' and 'const char [2]')

so i tried to cast the char, but it is still a QChar[2] . And i do not understand how a simple char can be a QChar array of 2.
So i tried:

QChar seperator = (QChar)(":");

Same problem. So what i am doing wrong here?

J.Hilk

I think, the error in your code is here:

}else if(!before && line.at(y)=""){
                        part2 += line.at(y);
        }

thats a typo, = needs to be a == for a valid if statement.

Anyway have you thought about useing

split(':')

could make things simpler for you.

LogiSch17

oh ,
in the code i had i correctly.
But i always tells me that ":" is an const char [2]

But split() is exactly what i was looking for.
Thanks a lot for that.

VRonin

Side Note: the problem your compiler is warning you about is that ":" is actually a string so 2 chars, a : and the null termination(\0). use single quotes for single chars, ':'

Chris Kawa

If I may - split() is horrible. It creates a list of copies - really bad for performance. Please use splitRef() when parsing data. It creates a vector of StringRefs, a much better solution if you don't need to copy the data (and you don't need to here) and a much more cache friendy structure.