Conversion from QByteArray to int

mulfycrowh

I tried what you suggested:

qFromLittleEndian<quint16>(info.data());

I've got the compiler error :

C2665 'qFromLittleEndian': none of the 2 overloads could convert all the argument types

mulfycrowh

I mean qint16.
Same issue

Paul Colby

@mulfycrowh said in Conversion from QByteArray to int:

I've got the compiler error :
C2665 'qFromLittleEndian': none of the 2 overloads could convert all the argument types

Ah... from the qFromLittleEndian docs:

Note: Since Qt 5.7, the type of the src parameter is a void pointer.

For pre-5.7, you will need to cast to uchar, like:

int count = qFromLittleEndian<qint16>(reinterpret_cast<const uchar *>(info.data()));

(I just tested that on Qt 5.5.1)

Cheers.

mulfycrowh

thanks, it runs perfectly !

kshegunov

@mulfycrowh
A two byte sequence is a short, not int. You should use the data stream classes for such deserializations instead of going to type-safety hell:

QByteArray data; //< This is your data

QDataStream in(data); //< Attach a read-only stream to it
in.setByteOrder(QDataStream::LittleEndian); //< Set the proper byte order

qint16 result; //< The result you want
in >> result; //< Just read it from the stream

sude

@kshegunov said in Conversion from QByteArray to int:

QByteArray data; //< This is your data

QDataStream in(data); //< Attach a read-only stream to it
in.setByteOrder(QDataStream::LittleEndian); //< Set the proper byte order

qint16 result; //< The result you want
in >> result; //< Just read it from the stream

Hi i want to read more than one number and i can read only first number how can i read all of them plese help me :) !!

JonB

@sude
Execute a further in >> something operation to read more data. What else is there to say?

sude

It isnt work, i still read first number of array :(

JonB

@sude
It does work. So your code is wrong, or your data is not what you expect, or you are not looking at the right thing. Suggest you open your own new topic for this and post your problem/code; this topic is very old.

sude

@JonB OK, thanks a lot. I'm appriciate your answer. I will create new topic. :)