Connecting signals and slots with different parameters: Is it possible?

Jorge

HI,
I wish to make a connection, and I'm aware that they both must have the same type of parameter in order to work. My question is:
Is there a way, or workaround, to this issue?
In my project, I want to connect a simple valuechanged signal to a a slot that receives 3 QWidet parameters.
This is the code in question:

//OperatorLogged is a valuechanged signal, nothing weird.
connect(login, SIGNAL(operatorLogged(int)),
            this, SLOT(createOperatorInterface(QWidget*, QWidget*, QWidget*)));
//createOperatorInterface takes the QWidget arguments and adds them to "this" stacked layout. "This" being  the main widget, by the way.

I would also like to know if using the main.cpp is the best practice, as I was taught in OOP, to work with my code. The whole issue comes from me trying to work in the main.cpp like this:

#include "mainwidget.h"
#include "qlogin.h"
#include "qdispense.h"
#include "qdispensedisplay.h"
#include "qresult.h"
#include <QApplication>
#include <QCalendarWidget>

int main(int argc, char *argv[])
{
    QApplication Skylord(argc, argv);
    mainWidget mwMainWidget;
    mwMainWidget.show();

    QLogin *loginWidget = new QLogin;
    QDispense *dispenseWidget = new QDispense;
    QDispenseDisplay *dispenseDisplayWidget = new QDispenseDisplay;
    QResult *resultWidget = new QResult;

    mwMainWidget.createLogin(loginWidget);

    return Skylord.exec();
}

Thanks in advance.

t3685

@Jorge

Hi,

How would your slot know what arguments to use, i.e. which pointers to QWidgets?

Greetings,

t3685

SGaist

Hi,

Short answer: no

The slot signature must either have the same number or less parameters than the signal and the type must be the same.