Memory access by address

[mohmo]

hey bros;
I have a program to access the variables by their addresses and this is my code:

float f;
int t;

QHash <int,int*> hash;
hash.insert(1,&t);
hash.insert(2,(int*)&f);

*hash.value(1)=34;
qDebug()<<"t1="<<t1; //t1= 34

*hash.value(2)=456.987;
qDebug()<<"f="<<f; //f=7.94536e-43 !!!!!!

why this code is not working? and how can i fix that?
Actually the objective of this code is to indexing every variable with any type (int, float, structure, Boolean, .. ) by an integer number. Hashing is used to achieve this goal.
Thanks a lot

[mohmo]

If i use QVariant like below:

@QHash <int,QVariant*> hash;
@
and i insert the same values into it, i encounter this error:

: error: C2664: 'QHash<Key,T>::insert' : cannot convert parameter 2 from 'int *' to 'QVariant *const &'
with
[
Key=int,
T=QVariant *
]

But if i use the previous code and retrieve the address as below:
@_(float_)hash.value(2)=456.987;
qDebug()<<“f=”<<f; //f=456.987@

everything will be OK.

[Jeroentjehome]

Hi,
Better to not use pointers to your variables for this. A QVariant will use the same amount of memory space as the variable it will point to. So, the QHash should have an <int, QVariant> not the pointer. Then add the variable to the QVariant via a constructor or other variant function and you should be able to convert any variable into that QHash. Even mix them if needed.

[mohmo]

hey Jeroentje@home
thanks for your reply But could you please make an example of your plan?

[SGaist]

Jeroentje@home meant that you should follow koahnig's example

@
QHash<int, QVariant> hash;
float fInput= 1.2
hash.insert(1, fInput);
float myFloat = hash.value(1).toFloat();
@