Important: Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct
HYSuperman last edited by
When I initialize a QPushButton Object, I can do it this way:
I can also do it this way:
@QPushButton *p2 = new QPushButton;@
The first way initialize an object while the later way initialize a pointer.
But when I add either of them to the widget and show this widget, the first way doesn't show.
I wonder why? As far as I know, the QPushButton class has a constructor:QPushtButton(QWidget *parent = 0);, so I don't think the construction process will go wrong...
Quentique last edited by
For me, it works. My code :
@ QWidget test;
p1.setGeometry(1, 1, 50, 40);
QPushButton *p2 = new QPushButton(&test);
p2->setGeometry(30, 20, 50, 40);
I think that you don't set the position of yours buttons.
If you do it e.g. in the constructor, p1 will be destroyed at the end of the constructor since it goes out of scope. That's why you don't see it.