[SOLVED] Error to declare signal

guidupas

Hello All!

I am trying to declare a signal as the code below shows:
@
//bancodados.h
#ifndef BANCODADOS_H
#define BANCODADOS_H

#include <QObject>

class bancoDados : public QObject
{
Q_OBJECT

public:
explicit bancoDados(QObject *parent = 0);

signals:
void conectar();

public slots:

};
@
@
//bancodados.cpp
#include "bancodados.h"

#include <QSqlDatabase>

bancoDados::bancoDados(QObject *parent) :
QObject(parent)
{

}
void bancoDados::conectar()
{
bool retorno = true;

emit retorno;

}
@

Well, when I run this code it show the error:
@:-1: error: 1 duplicate symbol for architecture x86_64@

But, if I change "void conectar();" from signals to public, it runs, but I need to it stays as a signal

Can anyone help me?

Thanks a lot.

SGaist

Hi,

signals don't have an implementation and you can't emit a variable.

See the "Signals And Slots":http://qt-project.org/doc/qt-5/signalsandslots.html documention for more information

guidupas

Thaks a lot