Pass a Qpair value in function

[deepakkakkeel]

May i know how will i pass a QPair value in a function?

[SGaist]

Do you mean:

@void myFunction (const QPair<int, int> &myPair)
{
qDebug() << myPair.first << myPair.second;
}@

?

[deepakkakkeel]

Suppose i have
QPair <int, int >pair;
pair.first = 4;
pair.second = 3;

Now how will i call myFunction () ?
How to pass pair to my Function?
Will the following work/
myFunction(pair);

[SGaist]

Yes, why wouldn't it ?

If you have doubts write some code to test it.

[deepakkakkeel]

May i know how to initialize QPair with qmakePair.
QPair <int, int >pair = qMakePair(4, 3);
Will the above work?

[MuldeR]

Look at qpair.h:

@QPair<T1, T2> qMakePair(const T1 &x, const T2 &y)
{
return QPair<T1, T2>(x, y);
}@

This means that "qMakePair(4, 3)" is nothing but a shorthand for something like "QPair<int, int > myPair(4, 3)", which in turn does the same as:

@QPair <int, int > myPair;
myPair.first = 3;
myPair.second = 4;@

So I see no reason why it should not work. But why not try yourself?

(there often is more than one to achieve the same thing)