QState::addTransition method gives error when called by non-pointer type

[BosGemiler]

Hello everyone,
I faced with an unexpected error. And I couldn't understand what causes this error.

I created one button and want to transmit from phase-1 to phase-2 when button is clicked.

QStateMachine machine;
QState phase_1_st;
QState phase_2_st;
machine.addState(&phase_1_st);
machine.addState(&phase_2_st);

phase_1_st.addTransition(ui->btn_change, &QPushButton::clicked, phase_2_st); // ERROR: function declaration is not matched 

When I used QState variable in pointer type, then problem is resolved.

QStateMachine machine;
QState *phase_1_st = new QState();
QState *phase_2_st = new QState();
machine.addState(phase_1_st);
machine.addState(phase_2_st);

phase_1_st->addTransition(ui->btn_change, &QPushButton::clicked, phase_2_st);

Maybe , it is related with C++ rules, no even Qt.
I would like to learn this mystery :)
Thank you.

[SGaist]

Hi,

Look at the function signature, it takes a pointer to an object and not an object. If you want to keep the object on the stack, you still have to pass its address.

Nothing Qt here, just plain C++.