QRegularExpression, implying regex on data contains NULL character

ikuris

Hello,
I am trying to parse some inputs that can have multiple NULL characters in it but I couldnt make it word, here is code I tried.

    QByteArray data = "[12]Hello\0\0World";
    QRegularExpression reg("(?<h1>\\[.*\\])(?<h2>.*)");
    reg.setPatternOptions(QRegularExpression::DotMatchesEverythingOption);
    QRegularExpressionMatchIterator itr = reg.globalMatch(data);
    while(itr.hasNext())
    {
        QRegularExpressionMatch match = itr.next();
        qDebug() << match.captured("h2");
    }

I want it to print HelloWorld but all I can see is Hello,
Thank you.

Christian Ehrlicher

It does not even compile. Since a QString should not contain a \0 (and you don't show how you convert your data to str) I doubt this will work at all with a regexp. Looks like another problem which shows a use of a regex where a simple search and replace would be much more efficent and understandable.

ikuris

Sorry, I was trying with QString str = QString::fromLatin1(data, data.size). It didnot work either.
I updated the code.

SGaist

Hi,

That's one of the issue: a string can only have one terminator char. Work on your QByteArray to change them. For example use the replace function.

JonB

@ikuris said in QRegularExpression, implying regex on data contains NULL character:

QRegularExpression reg("(?<h1>\\[.*\\])(?<h2>.*)");

Separately from the correct observations of my colleagues. What are \\[ and \\] doing here inside a C literal? What are you trying to achieve with these?