Qt QRadioButton (1) setChecked problem

[Proton Phoenix]

Hi ~~ i have connected lineedit textChanged() which is also connected to QRadiobutton in the second form with a slot and value *passed successfully from form to form

connect(ui->statuslineedit,SIGNAL(textChanged(QString)),reg,SLOT(recieveacc(QString)));

void licenceagrement::on_statuslineedit_textChanged(const QString &arg1)
{
    Q_UNUSED(arg1)
    if(ui->licenceag->isChecked()){
      ui->statuslineedit->setText("yes");
    }else{
        ui->statuslineedit->setText("no");
    }
}

when i want to control QRadioButton which is in the first form from the second QRadiobutton nothing change
this is the

void registeracc::recieveacc(QString recieve){

    if(recieve=="yes"){
       ui->licenceagrement->setChecked(true);
       qDebug()<<recieve; //qDebug result here = "yes" on every setchecked by mouse not programmatically 

    }if(recieve=="no"){
        ui->licenceagrement->setChecked(false);
        qDebug()<<recieve; //qDebug result here = "no" on every setchecked by mouse not programmatically 
}
}

is there any solution or is it a bug in QT?
The problem is Nothing change even if the value ="yes" or "no"

[mrjj]

Hi
Could you try

ui->licenceagrement->hide()
and
ui->licenceagrement->show()

jus to be sure you are looking at the correct one.

setChecked should work so its something else.

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

ui->licenceagrement->hide()

void registeracc::recieveacc(QString recieve){

    ch = recieve;
    if(recieve=="yes"){
        ui->licenceagrement->show();
       qDebug()<<recieve;

    }if(recieve=="no"){
        ui->licenceagrement->hide();
        qDebug()<<recieve;
}
}

still the same problem it doesn't hide

[mrjj]

Hi
Ok then something is up as hide() can't fail as such.

and you are 100% sure it goes into the IFs so it will call the code?

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

Hi
Ok then something is up as hide() can't fail as such.

and you are 100% sure it goes into the IFs so it will call the code?

this is the the application output qDebug it's already in recieve slot
so recieve slot get the value successfully
every click from me (second window) it shows "yes" , then "no" .... from qDebug() in the first window

[mrjj]

Hi

I cant guess it. hide() cannot fail so im lost.

How do you send signal back to the first window when no button is pressed (in dialog)?

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

Hi

I cant guess it. hide() cannot fail so im lost.

How do you send signal back to the first window when no button is pressed (in dialog)?

void licenceagrement::on_licenceag_clicked()
{
    if(ui->licenceag->isChecked()){
      ui->statuslineedit->setText("yes");
    }else{
        ui->statuslineedit->setText("no");
    }
}

this is the code of the QRadioButton in Dialog window when i click QRadiobutton in Dialog it send QString to lineedit which is also send a signal to recieve slot in registeracc Widget qDebug() show's that the public slot received the QString successfully but the If's can't do the rest and apply that to the QRadioButton in the first window (registeracc)

[mrjj]

Hi
Ok so it's via the text change signal back to form 1

Could you try to place a button on form 1 and in its clicked
try
ui->licenceagrement->hide();

just to see it can work. All look good so im a bit baffled.

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

Hi
Ok so it's via the text change signal back to form 1

Could you try to place a button on form 1 and in its clicked
try
ui->licenceagrement->hide();

just to see it can work. All look good so im a bit baffled.

void registeracc::on_justtestbutton_clicked()
{
    ui->licenceagrement->hide();
}

from the first form it works and it hides the QRadiobutton as the picture

[mrjj]

Hi
Ok so names etc are fine.

Then last test

void registeracc::recieveacc(QString recieve){
    ch = recieve;
    if(recieve=="yes"){
        ui->licenceagrement->show();
       qDebug()<<"i just called show";
    }
    if(recieve=="no"){
        ui->licenceagrement->hide();
         qDebug()<<"i just called hide";
    }
}

and tell me if the new texts show as it should ?

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

Hi
Ok so names etc are fine.

Then last test

void registeracc::recieveacc(QString recieve){
    ch = recieve;
    if(recieve=="yes"){
        ui->licenceagrement->show();
       qDebug()<<"i just called show";
    }
    if(recieve=="no"){
        ui->licenceagrement->hide();
         qDebug()<<"i just called hide";
    }
}

and tell me if the new texts show as it should ?

[SGaist]

Hi,

In the upper part of that picture you have a lic variable that is a licenseagrement object. I suspect that this is the one you are seeing. You are likely not hiding what you think you are hiding.

[Proton Phoenix]

@SGaist said in Qt QRadioButton (1) setChecked problem:

Hi,

In the upper part of that picture you have a lic variable that is a licenseagrement object. I suspect that this is the one you are seeing. You are likely not hiding what you think you are hiding.

i think you are correct bro ! i used this object when i click the QRadiobutton in the first form it shows the second dialog!?

[Proton Phoenix]

@Proton-Phoenix said in Qt QRadioButton (1) setChecked problem:

@SGaist said in Qt QRadioButton (1) setChecked problem:

Hi,

In the upper part of that picture you have a lic variable that is a licenseagrement object. I suspect that this is the one you are seeing. You are likely not hiding what you think you are hiding.

i think you are correct bro ! i used this object when i click the QRadiobutton in the first form it shows the second dialog!?

i have change it now to this but the same problem

[mrjj]

@Proton-Phoenix

Hi
So testWindow is the "Dialog " (in title) we see ?

if yes, dont it miss a connect there so its textChanged signal can come back to registeracc ?

Its a new object so its not connected.

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

@Proton-Phoenix

Hi
So testWindow is the "Dialog " (in title) we see ?

if yes, dont it miss a connect there so its textChanged signal can come back to registeracc ?

Its a new object so its not connected.

Yes bro

every time i click the first QRadioButton it shows The Dialog window
then in Dialog cpp i connected it using this (i am just a beginner)

connect(ui->statuslineedit,SIGNAL(textChanged(QString)),reg,SLOT(recieveacc(QString)));
so the problem is the new object which is not connected??
but how it send the QString! every time i click The QRadioButton in the dialog which was opened from the new object?
is there any solution?
sorry for making you all that tired but anyway it's experience for you may someday you will help another beginner on it
Really Thank you all what you are doing guys <3

registeracc *reg=new registeracc(); // i think the problem here it's also a new object!
  connect(ui->statuslineedit,SIGNAL(textChanged(QString)),reg,SLOT(recieveacc(QString)));

[mrjj]

@Proton-Phoenix
Hi
yes that is the issue.
Its not the one we are looking at :)

[Proton Phoenix]

@mrjj said in Qt QRadioButton (1) setChecked problem:

@Proton-Phoenix
Hi
yes that is the issue.
Its not the one we are looking at :)

:D Strange :D ^^ Really Thank you bro all of you guys You are making Great job here <3 i wish all the best happy great life for all of you <3
may someday someone will have the same problem and it will be in the hippocampus sql ^^ :D
so it's changing but it doesn't show changes because it's a new object not the original form
^^ is there any solution !? advice !
registeracc *reg=new registeracc();
it accept only new object pointers to connect

connect(ui->statuslineedit,SIGNAL(textChanged(QString)),reg,SLOT(recieveacc(QString)));

[Proton Phoenix]

problem fixed ... Really Thank you guys <3
mrjj and SGaist ...
this is the warning which were deceiving me from the very beginning
i thought it was a problem
but it's the solution